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Lamez

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Posts posted by Lamez

  1. I am a bit lost on your question.

     

    You can call files from different folders with php, and include them in the current script.

     

    Such as:

    <?php
    //in current dir.
    include("file.php");
    //up a folder, a in the folder name: folder_name
    include("../folder_name/file.php");
    ?>
    

     

    Maybe you can rephrase your question.

     

    -Lamez :)

  2. Okay, I am getting a error with my query. I am sure it's nothing, but I cannot find it. I just need a fresh pair of eyes.

     

    Here is the error:

    You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'key, ip, first, last, email, disp, review) VALUES ('0', '6a4c85fbb4772a41f645b8a' at line 1

     

    Here is the code:

    <?php
    $q = "INSERT INTO `reviews` (valid, key, ip, first, last, email, disp, review) VALUES ('".$valid."', '".$key."', '".$ip."', '".$fname."', '".$lname."', '".$email."', '".$disp."', '".$review."')";
    mysql_query($q) or die(mysql_error());
    ?>

     

    Oh, Here is the Database Structure:

    id

    post

    vaild

    key

    ip

    first

    last

    email

    disp

    review

    -Thanks Guys!

  3. My action script that adds points to the users, and updates the database is not doing any of the mysql querys, it has work times and times before, but not now for some reason. It does redirect, but it does not echo anything out. I have no idea why.

     

    Here is the code:

    <?php
    ob_start();
    $path = "../../";
    $title = "Update Winners"; 
    $u_login = "yes";
    $admin = "yes"; 
    include ($path."main/include/cons/head.php");
    if(siteStat() == "Basketball" && $basketReg == 0){
    function getPnts($round){
    	$f = mysql_fetch_array(mysql_query("SELECT * FROM `basket_pnts` WHERE `round` = '".$round."'"));
    	return $f['value'];
    }
    $i = 1;
    $cnt = 1;
    while($i<=16*4){
    	if($i <= 16*1){
    		$r = "a";
    	}else if($i <= 16*2){
    		$r = "b";
    	}else if($i <= 16*3){
    		$r = "c";
    	}else if($i <=16 *4){
    	 	$r = "d";
    	}
    	$win = $_POST[$cnt."_".$r];
    	$spot = $cnt;
    	$round = $_POST['round'];
    	if(!empty($win)){
    		mysql_query("INSERT INTO `basket_winner` (team, region, spot, round) VALUES ('".$win."', '".$r."', '".$spot."', '".$round."')")or die(mysql_error());
    		$pnt = getPnts($round);
    		$table = "basket_rnd".$round;			
    		$q = mysql_query("SELECT * FROM `".$table."` WHERE `".$spot."` = '".$win."' AND `region` = '".$r."'");
    		while($f = mysql_fetch_array($q)){
    			$usr = $f['user'];
    			$p = mysql_query("SELECT * FROM `basket_usrpnts` WHERE `user` = '".$usr."'");
    			$p = mysql_fetch_array($p);
    			$brnd = "rnd".$round;
    			$rnd = $p[$brnd];
    			$total = $p['total'];
    			$rnd+=$pnt;
    			$total+=$pnt;
    			mysql_query("UPDATE `basket_usrpnts` SET `".$brnd."` = '".$rnd."', `total` = '".$total."' WHERE `user` = '".$usr."'");
    			echo $table." ".$spot." ".$usr." ".$pnt;
    		}	
    	}
    	$i++;	
    	if($cnt <= 16){
    		$cnt++;
    	}else{
    		$cnt = 1;
    	}
    }
    //header("Location: up_win.php");		
    }else{
    header("Location: ../index.php");
    }
    include ($path."main/include/cons/foot.php");
    ?>
    

  4. I keep getting a mySql error, but I have no idea why, can someone help me look for the error?

     

    This is the Error:

    You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1, 2, 3, 4, 5, 6, 7, 8) VALUES ('Lamez', 'a', 'Louisville', 'Ohio St.', 'Utah', ' at line 1

     

     

    <?php
    mysql_query("INSERT INTO `basket_rnd1` (user, region, 1, 2, 3, 4, 5, 6, 7,  VALUES ('".$user_."', '".$x."', '".$a."', '".$b."', '".$c."', '".$d."', '".$e."', '".$f."', '".$g."', '".$h."')") or die(mysql_error());
    ?>
    

     

    Whole Code:

    <?php
    ob_start();
    $path = "../../";
    $title = "Basketball Bracket";
    $rank = "yes";
    $u_login = "yes";
    include ($path."main/include/cons/head.php"); 
    $y = $_SESSION['xz'];
    $end = "endRnd_on";
    $end2 = "endRnd_on2";
    $end3 = "endRnd_on3";
    $end4 = "endRnd_on4";
    
    if($y == $end || $y == $end2 || $y == $end3 || $y == $end4){
    
    	if($y == $end){ 
    		$region = 1; $x = "a"; $re = "b";
    
    	} else if($y == $end2){ 
    		$region = 2; $x = "b"; $re = "c";
    
    	}else if($y == $end3){
    		$region = 3; $x = "c"; $re = "d";
    
    	}else if($y == $end4){ 
    		$region = 4; $x = "d"; $re = "e";
    	}else{ 
    		header("Location: ?yyz=r112d"); 
    	}
    	$a = $_POST['1'];
    	$b = $_POST['2'];
    	$c = $_POST['3'];
    	$d = $_POST['4'];
    	$e = $_POST['5'];
    	$f = $_POST['6'];
    	$g = $_POST['7'];
    	$h = $_POST['8'];
    
    	$i = $_POST['9'];
    	$j = $_POST['10'];
    	$k = $_POST['11'];
    	$l = $_POST['12'];
    
    	$m = $_POST['13'];
    	$n = $_POST['14'];
    
    	$o = $_POST['15'];
    	mysql_query("INSERT INTO `basket_reg` (id, name) VALUES ('1','A')")or die(mysql_error());
    
    
    	mysql_query("INSERT INTO `basket_rnd1` (user, region, 1, 2, 3, 4, 5, 6, 7,  VALUES ('".$user_."', '".$x."', '".$a."', '".$b."', '".$c."', '".$d."', '".$e."', '".$f."', '".$g."', '".$h."')") or die(mysql_error());
    	mysql_query("INSERT INTO `basket_rnd2` (user, region, 9, 10, 11, 12) VALUES ('".$user_."', '".$x."', '".$i."', '".$j."', '".$k."', '".$l."')") or die(mysql_error());
    	mysql_query("INSERT INTO `basket_rnd3` (user, region, 13, 14) VALUES ('".$user_."', '".$x."', '".$m."', '".$n."')") or die(mysql_error());
    	mysql_query("INSERT INTO `basket_rnd4` (user, region, 15) VALUES ('".$user_."', '".$x."', '".$o."')") or die(mysql_error());
    	header("Location index.php?region=".$re); 
    }else{
    echo "ERROR!";
    }
    ?>
    <?php
    include ($path."main/include/cons/foot.php");
    ?>
    

     

    Any Ideas?

     

    Thanks Guys

  5. Lamez, here in America, we don't go to jail for questioning the government.  I do not think people should ever have to live under a government that they did not choose to live under.

     

     

    Also, just because an economy is good doesn't mean a government is good for its people.

     

     

    Just because he's in the middle of it he has no reason to complain?  So it's his fault he lives in China.

     

     

     

    Wow.

    sure if you want to look at my post in that perspective.

     

  6. China is top of the world with their economy, so they know what they are doing, and just because you are in the middle of it, does not give you a reason to complain. (run on :P) Ya I live in America, and we Americans get what we want. I am sorry you live in a strict environment, but you do not have any reason in the world to break the rules, so get over it.

  7. I usually only post here when I am tired and cannot find the problem, but I think I will not be able to solve this one when I am mentally sober.

     

    This bit of code below is suppose to check to see if the user has added the other user as their friend, if so it will return a error message, well I do believe I tested it before, but that was before I added someone else as my friend, meaning you get the error no matter what when you have more than one friend!

     

    Does anyone know why?

     

    Code:

    <?php
        $f_id = findInfo($user, "id");
    $q = mysql_query("SELECT * FROM `friends` WHERE `a` OR `b` = '".$f_id."'");
    $f = mysql_fetch_array($q);
    if($f['a'] == $f_id){
      $n == 1;
    }else{
      if($f['b'] == $f_id){
        $n == 1;
      }else{
        $n == 0;
      }
    }
    if($n == 1){
      echo "<b>".$user."</b> is your friend already";
    }
    ?>
    

     

    findInfo function:

    <?php
    function findInfo($user, $what){
      $q = mysql_query("SELECT * FROM `users` WHERE `username` = '".$user."'");
      $f = mysql_fetch_array($q);
      return $f[$what];
    }
    ?>
    

  8. I am trying to get my insert query to insert a 1 in the accept field, but it is add a 0 instead. Here is the code:

     

    <?php
           $me_id = findInfo($user_, "id");
           $them_id = findInfo($a_usr, "id");
           mysql_query("UPDATE `friends` WHERE `friend_id` = '".$them_id."' AND `user_id` = '".me_id."' SET `accept` = '1'");
           mysql_query("INSERT INTO `friends` (user_id, friend_id, accept) VALUES('$me_id', '$them_id', '1')")or die(mysql_error());
           echo "<b>".$a_usr."</b> has been added as your friend!";
    ?>
    

    no errors are being returned. The update query works, but not the insert!

  9. I went to the domain, and all I got was a blank page, of course on the port you have listed above. My home server has a domain that is pointed to my server from servage's servers but, I cannot load my website using the domain, when I am on my network, I have to use the host name, "megatron". I have no idea why, and it just changed on me all of a sudden, but that might be your problem, try loading the website from a different computer off your network.

     

     

    You probably don't care at this point, but if you ever wanted to use the full domain name, you could just modify your hosts file (C:\Windows\System32\drivers\etc\hosts) to have your host name redirected to megatron.

     

    lol its a linux server!

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