izzytees

For anyone out there that can solve this, I appreciate it well in advance. I'm sure it must be something simple, but it has got my head spinning. I also emailed the author of this code and posted this message on phpbuilder but have yet to hear back so I thought I'd expand my reach to users of this forum. Here is how I'm calling the image page: <img src="view_image.php?cattype=<?php echo $row_viewimages['cat_type']; ?>&id=<?php echo $row_viewimages['display_id']; ?>" width="110" height="110" border="0" alt="catalog"/> Here are sample issues: http://www.izzytees.com/viewcatalog.php http://www.izzytees.com Here is the view_image.php code: <?php // getdata.php3 - by Florian Dittmer <dittmer@gmx.net> // Example php script to demonstrate the direct passing of binary data // to the user. More infos at http://www.phpbuilder.com // Syntax: getdata.php3?id=<id> if($id) { $cat = $_REQUEST['cattype']; $id = $_REQUEST['id']; // you may have to modify login information for your database server: @MYSQL_CONNECT("xxx","xxx","xxx"); mysql_select_db("xxx"); $query = "select bin_data,filetype,display_id,cat_type from image_display where display_id='$id' AND cat_type='$cat'"; $result = @MYSQL_QUERY($query); $data = @MYSQL_RESULT($result,0,"bin_data"); $type = @MYSQL_RESULT($result,0,"filetype"); Header( "Content-type: $type"); echo ($data); }; ?>