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kuchela

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  1. Hello friends, I need help in imagecopy function used in php i write the code here is the sample................... <?php $w = getimagesize("image2.jpg"); echo $w[0]; echo $w[1]; $src = "/var/www/html/image2.jpg"; imagecopy("image1.jpg","$src","50","100","40","100","$w[0]","$w[1]"); ?> and i am getting the error like this.................... PHP Warning: imagecopy(): supplied argument is not a valid Image resource in /var/www/html/imagecp.php on line 19 please help me anybody i need very urgently thank u
  2. hello friends, i need help in the php with imagecopy function. when i run my php program it is showing errors like this in command line argument PHP Warning: imagecopy(): supplied argument is not a valid Image resource in /var/www/html/imagecp.php on line 19 please any body tell me out to solve this problem, i need sample code that will copy image from one to another thank u
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