phpretard
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Posts posted by phpretard
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I use this structure all the time
<head> </head> <body> <div id="main"> <div id="site_content"> <? include 'header.php'; include 'navigation.php'; include "pages/$page.php"; // DIFFERENT PAGES include 'footer.php'; ?> </div> '</div> </body> </html> // HERE IS THE NAVIGATION PAGE echo" <ul id='menu'> <li><a href='?page=home'>Home</a></li> <li><a href='?page=schedule'>Schedule</a></li> <li><a href='?page=pricing'>Pricing</a></li> <li><a href='?page=about'>About Us</a></li> <li><a href='?page=gallery&loc=gallery'>Gallery</a></li> <li><a href='?page=contact'>Contact Us</a></li> </ul>";
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I need some code that will validate a full name.
Argument: 'John'=No Good | 'Doe'=No Good | 'John Doe'=Good
if ($Name=='ONE WORD'){ $pass="No"; } if ($Name=='TWO WORDS'){ $pass="Yes"; }Anyone got an Idea
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Can you post your code.
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I would look more into the connection error.
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$event=$_GET['event'];
header( 'Location: http://www.website.com/index.php?page=checkout&event=$event' );
The redirect works but the address bar reads:
http://www.website.com/index.php?page=checkout&event=$event' <---should be event=Sports
I need the $event.
It work throughout the site exept when a header redirect is used.
Any thought?
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<?php
if ($action=='delete'){
$file="P1040050.jpg";
unset($_SESSION[$file]['file']);
}
?>
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How do I unset just one part of the array?
unset($_SESSION[$file]['P1040050.jpg']); <--doesn't work
$_SESSION:Array ( [P1040050.jpg] => Array ( [picture] => ALBUMS/Holmes_Adams/P1040050.jpg [file] => P1040050.jpg [s46] => 4 x 6 [QU46] => 10 [s57] => 5 x 7 [QU57] => 20 [s810] => 8 x 10 [QU810] => 30 [order_photo] => Order This Photo ) [P1040052.jpg] => Array ( [picture] => ALBUMS/Holmes_Adams/P1040052.jpg [file] => P1040052.jpg [s46] => 4 x 6 [QU46] => 30 [s57] => 5 x 7 [QU57] => 20 [s810] => 8 x 10 [QU810] => 10 [order_photo] => Order This Photo ) )
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Hey BrianM,
Know anything about Multidimensional Arrays?
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I set it up and it worked. How about you?
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Did you put that code on a new page?
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That would be funny if I new what it meant. lol
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The onlt problem i saw was:
if (mysql_num_rows($result) == 1) {
Should be:
$count=mysql_num_rows($result);
if($count==1){
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Make a new file and put this code and only this code in it...
Be sure --include '../tracking/db_connx.php';-- is still correct
<?php session_start(); $errorMessage = ''; if (isset($_POST['Submit'])) { $username=$_POST['username']; $passwd=$_POST['passwd']; include '../tracking/db_connx.php'; $sql = "SELECT * FROM webusers WHERE username = '$username' AND passwd = '$passwd'" or die("error 1"); $result = mysql_query($sql) or die('Query failed. ' . mysql_error()); $count=mysql_num_rows($result); if($count==1){ echo"Loged In"; /* UNCOMMENT THIS LATER $_SESSION['db_is_logged_in'] == true; header('Location:../indexin.php'); exit; */ } else { $echo = 'Sorry, wrong user id / password'; } } ?> <p> <form id="login" name="login" method="POST" action=""> <input type="text" id="username" name="username" value="User Name" /> <input type="password" id="passwd" name="passwd" value="Password"/> <input type="submit" id="submit" name=Submit value="Log In"/> </form> </p> -
Black?
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change the action="" to whatever it was...
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oh yeah...I also --selected * from table-- instead of just username
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I gave your submit button a name and used it for the isset
<?php session_start(); $errorMessage = ''; if (isset($_POST['Submit'])) { $username=$_POST['username']; $passwd=$_POST['passwd']; include '../tracking/db_connx.php'; $sql = "SELECT * FROM webusers WHERE username = '$username' AND passwd = '$passwd'" or die("error 1"); $result = mysql_query($sql) or die('Query failed. ' . mysql_error()); if (mysql_num_rows($result) == 1) { echo"Loged In"; /* UNCOMMENT THIS LATER $_SESSION['db_is_logged_in'] == true; header('Location:../indexin.php'); exit; */ } else { $echo = 'Sorry, wrong user id / password'; } } ?> <p> <form id="login" name="login" method="POST" action=""> <input type="text" id="username" name="username" value="User Name" /> <input type="password" id="passwd" name="passwd" value="Password"/> <input type="submit" id="submit" name=Submit value="Log In"/> </form> </p> -
Can you post the form code?
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What happen when you try to log in? Blank page, Error, etc...
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I have read throught the post and still don't know the problem. I see that some problems were made. What was the original problem?
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Absolutely 100%
I really need to know how to echo/print ---"ALBUMS/Holmes_Adams/P1040050.jpg"--- (within a foreach loop) from the two arrays.
http://www.rememberthetimephotos.com/ALBUMS/Holmes_Adams/P1040050.jpg <-- picture path
Don't mind the picture...It's kind of scary:)
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From a form.
if(isset($_POST['order_photo'])){ $picture_id = $_POST['file']; foreach($_POST as $key => $val){ $_SESSION[$picture_id][$key] = $val; } } -
I can see where the problem lies but cant find the answer.
Can anyone tell me why I can't see the pictures?
echo '<pre>$_SESSION:' . print_r($_SESSION,true) . '</pre>'; The Above Yeilds This In The Browser: $_SESSION:Array ( [P1040050.jpg] => Array ( [picture] => ALBUMS/Holmes_Adams/P1040050.jpg //<----PICTURE 1 LOCATION [file] => P1040050.jpg [s46] => 4 x 6 [QU46] => 10 [s57] => 5 x 7 [QU57] => 20 [s810] => 8 x 10 [QU810] => 30 [order_photo] => Order This Photo ) [P1040052.jpg] => Array ( [picture] => ALBUMS/Holmes_Adams/P1040052.jpg //<------PICTURE 2 LOCATION [file] => P1040052.jpg [s46] => 4 x 6 [QU46] => 30 [s57] => 5 x 7 [QU57] => 20 [s810] => 8 x 10 [QU810] => 10 [order_photo] => Order This Photo ) ) foreach ($_SESSION as $file => $val){ echo"<img src='" . $_SESSION['picture_id']['picture'] . "'>"; }I was expecting 2 pictures to show up based on the session variables...all I get is an unidentified picture.
I have been reading about this and can't pick up the answer anywhere.
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I just want to pull the information from the session --- $_SESSION['picture'] ---
and use it for the source of an image.
[SOLVED] Simple Validation
in PHP Coding Help
Posted
Do you have an example of str_word_count.
I am struggling to make it work.