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phpretard

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Posts posted by phpretard

    [SOLVED] Date Funtion

    in PHP Coding Help

    Posted

    I am trying to display the date like - 08-01-2009 by calling a function with a var.

     

    I know the code below is wrong but it's what I'm working with.

     

     

    
<?php

function myDate($startdate){

    echo "The date is ". $startdate;

	$startdate="2009-08-01 07:27:40";
	$predate=explode(' ', $startdate);
	$splitdate=explode('-', $predate[0]);
	$redeemDate="$splitdate[1]-$splitdate[2]-$splitdate[0]";
	$new_date="$startdate";
	    
}

myDate($new_date);

?>

     

    Thank you!

    if in a where

    in PHP Coding Help

    Posted

    One loop is $title the other is $stitle

     

    I have narrowed it down and this doesn't even work...

     

    - I am checking a row in the DB for zero or one.

    - if it's 0 it should display a div.

    - else it should display the other div.

     

    I am sure the tables are setup right because if I change:

     

    $title['sub_cat'] == 0 - TO - $title['sub_cat'] == 1

     

    It displays the TEST but not the other...

     

    
$page_title = mysql_query("select * from category where id='".intval($_GET['c'])."' ");
while($title = mysql_fetch_assoc($page_title))
{
if ($title['sub_cat'] == 0){ // ZERO CHECK
echo"<div>".$title['long_name']."</div>";

             }else{echo"<div>TEST</div>";}

}

mysql_free_result($page_title);

    if in a where

    in PHP Coding Help

    Posted

    Why doesn't tis work???

     

    
connect();

$page_title = mysql_query("select * from category where id='".intval($_GET['c'])."' ");
while($title = mysql_fetch_assoc($page_title))
{
if ($title['sub_cat'] == 0){
	echo"<div style=\"color:#A00201; font-style:italic; padding-top:5px;; font-size:22px; font-weight:bold;\">".$title['long_name']."<hr /></div>";
}else{
	$sub_title = mysql_query("select * from category_sub where cat_id='".$title['id']."' ") or die(mysql_error());
	while($stitle = mysql_fetch_assoc($sub_title));
		{
		echo"<div style=\"color:#A00201; font-style:italic; padding-top:5px;; font-size:22px; font-weight:bold;\">".$stitle['sub_name']."TEST<hr /></div>";
		}
	mysql_free_result($sub_title);		
	}
}

mysql_free_result($page_title);

     

    Its driving me mad!!!

    [SOLVED] Wanna Date

    in PHP Coding Help

    Posted

    I need to print out the time but I cant figure???

     

    
$calls['stamp']="2009-07-26 12:02:53";

$startdate=$calls['stamp'];
$predate=explode(' ', $startdate);
$splitdate=explode('-', $predate[0]);
$Date="$splitdate[1]-$splitdate[2]-$splitdate[0]";

This prints out "07-26-2009";

     

    I need the time as well.  Any help?

    Click on the button for limited times

    in PHP Coding Help

    Posted

    Not tested but should give you an idea...

     

    
<?php
if (isset($_POST['submit'])){

//connect to the DB

$get_ip=mysql_query("select * from ip_table where ip='".$_POST['clicker']."' ");

$num_rows = mysql_num_rows($get_ip);

   if ($num_rows > 19){
      $disable="disabled";
      $alert="<script>alert('You are hurting my clicker')</script>";

   }else {
       // $count_a=query the db for the ip and the count
       $count=$count_a + 1;
       $insert=mysql_unbuffered_query("update ip_table set count='$count' where ip='".$_SERVER['REMOTE_ADDR']."' ");

}

mysql_free_result($get_ip);

}
?>

<form>
<input type="hidden" name="clicker" value="<? echo $_SERVER['REMOTE_ADDR']; ?>" />
<input type="submit" name="submit" <? echo $disable; ?> />
</form>

<?
echo $alert;
?>

    [SOLVED] Keep a check box checked

    in PHP Coding Help

    Posted

    I am validating a form with PHP and it contains check boxes, text, radios etc...

     

    The short logic is:

    -At least one check box has to be checked

    -At least one radio has to be ticked

    -And one text box has to be filled

     

    If I check a box and tick a radio but do not fill in the text box it validates fine but the check box becomes "un-checked" afterwards.

     

    So my question is what is the recommended way keep check boxes checked and radios ticked while validating the rest of the form?

     

    I know the hard way to do it but I was hoping for some advise on it.

     

    <input type="checkbox" name="referred[]" value="Internet" /> Internet
<input type="checkbox" name="referred[]" value="Radio" /> Radio
<input type="checkbox" name="referred[]" value="Television" /> Television
<input type="checkbox" name="referred[]" value="Billboard" /> Law Talk
<input type="checkbox" name="referred[]" value="" /> Billboard
<input type="checkbox" name="referred[]" value="Newspaper" /> Newspaper
<input type="checkbox" name="referred[]" value="Phone Book" /> Phone Book
<input type="checkbox" name="referred[]" value="Attorney Referral" /> Attorney Referral
<input type="checkbox" name="referred[]" value="Friend" /> Friend

     

     

    Thanks.

    Opening Email

    in PHP Coding Help

    Posted

    I send newsletters through a service and they provide a report of how many people opened the email.  I was perplexed as to how they could tell until I discovered a 1X1 blank gif at the bottom of the newsletter.

     

    <img src="http://app.streamsend.com/v/1477632/pqBnIm6/d5Fs"/>

     

    any ideas as to how that picture could ("insert into...?

     

    I would like to track who opens email as well.

     

    Thank you!

    OS Commerse Anyone?

    in Applications

    Posted

    When I click "modules >> payment" instead showing me the different modules it just prints:

     

    Module Directory: DIR_FS_CATALOGincludes/modules/payment/

     

    I see all the moldules in that folder but it doesn't show them.

     

    Any suggestions?

    [SOLVED] Simple Date question

    in PHP Coding Help

    Posted

    Thank you very much.

     

    
echo $first_day = date("Y-m-d h:i:s", strtotime("1 ". date("F Y")));
echo '<br />';
echo $last_day = date("Y-m-d h:i:s", strtotime(date("t F Y ")));

above outputs:
2009-06-01 12:00:00
2009-06-30 12:00:00

I dont quite understand: "strtotime(date("t F Y ")));"

Where can I adjust to output?:
2009-06-01 12:00:00
2009-06-30 11:59:59

     

    Thanks again :)

    [SOLVED] Simple Date question

    in PHP Coding Help

    Posted

    I would like to display the current month's 1st and last day.

     

    It has to be simple I just cant figure it out based on php.net's site

     

    
$First=date('Y-m-d h:i:s');
$Last=date('Y-m-d h:i:s');

echo $First should be "2009-6-1 12:01"
echo $Last should be "2009-6-30 11:59"

     

    Thank you for looking.

    [SOLVED] Numbers To Text

    in PHP Coding Help

    Posted

    Look what I found:

     

    
<?
function convertNumber($num)
{
   list($num, $dec) = explode(".", $num);

   $output = "";

   if($num{0} == "-")
   {
      $output = "negative ";
      $num = ltrim($num, "-");
   }
   else if($num{0} == "+")
   {
      $output = "positive ";
      $num = ltrim($num, "+");
   }
   
   if($num{0} == "0")
   {
      $output .= "zero";
   }
   else
   {
      $num = str_pad($num, 36, "0", STR_PAD_LEFT);
      $group = rtrim(chunk_split($num, 3, " "), " ");
      $groups = explode(" ", $group);

      $groups2 = array();
      foreach($groups as $g) $groups2[] = convertThreeDigit($g{0}, $g{1}, $g{2});

      for($z = 0; $z < count($groups2); $z++)
      {
         if($groups2[$z] != "")
         {
            $output .= $groups2[$z].convertGroup(11 - $z).($z < 11 && !array_search('', array_slice($groups2, $z + 1, -1))
             && $groups2[11] != '' && $groups[11]{0} == '0' ? " and " : ", ");
         }
      }

      $output = rtrim($output, ", ");
   }

   if($dec > 0)
   {
      $output .= " point";
      for($i = 0; $i < strlen($dec); $i++) $output .= " ".convertDigit($dec{$i});
   }

   return $output;
}

function convertGroup($index)
{
   switch($index)
   {
      case 11: return " decillion";
      case 10: return " nonillion";
      case 9: return " octillion";
      case 8: return " septillion";
      case 7: return " sextillion";
      case 6: return " quintrillion";
      case 5: return " quadrillion";
      case 4: return " trillion";
      case 3: return " billion";
      case 2: return " million";
      case 1: return " thousand";
      case 0: return "";
   }
}

function convertThreeDigit($dig1, $dig2, $dig3)
{
   $output = "";

   if($dig1 == "0" && $dig2 == "0" && $dig3 == "0") return "";

   if($dig1 != "0")
   {
      $output .= convertDigit($dig1)." hundred";
      if($dig2 != "0" || $dig3 != "0") $output .= " and ";
   }

   if($dig2 != "0") $output .= convertTwoDigit($dig2, $dig3);
   else if($dig3 != "0") $output .= convertDigit($dig3);

   return $output;
}

function convertTwoDigit($dig1, $dig2)
{
   if($dig2 == "0")
   {
      switch($dig1)
      {
         case "1": return "ten";
         case "2": return "twenty";
         case "3": return "thirty";
         case "4": return "forty";
         case "5": return "fifty";
         case "6": return "sixty";
         case "7": return "seventy";
         case "8": return "eighty";
         case "9": return "ninety";
      }
   }
   else if($dig1 == "1")
   {
      switch($dig2)
      {
         case "1": return "eleven";
         case "2": return "twelve";
         case "3": return "thirteen";
         case "4": return "fourteen";
         case "5": return "fifteen";
         case "6": return "sixteen";
         case "7": return "seventeen";
         case "8": return "eighteen";
         case "9": return "nineteen";
      }
   }
   else
   {
      $temp = convertDigit($dig2);
      switch($dig1)
      {
         case "2": return "twenty-$temp";
         case "3": return "thirty-$temp";
         case "4": return "forty-$temp";
         case "5": return "fifty-$temp";
         case "6": return "sixty-$temp";
         case "7": return "seventy-$temp";
         case "8": return "eighty-$temp";
         case "9": return "ninety-$temp";
      }
   }
}
      
function convertDigit($digit)
{
   switch($digit)
   {
      case "0": return "zero";
      case "1": return "one";
      case "2": return "two";
      case "3": return "three";
      case "4": return "four";
      case "5": return "five";
      case "6": return "six";
      case "7": return "seven";
      case "8": return "eight";
      case "9": return "nine";
   }
}
?>

$Spell=convertNumber("395.00");

echo $Spell;

     

     

    Email Problem

    in PHP Coding Help

    Posted

    All the variable print so I don't know what the problem is.

     

    Do you see any issues?

     

    
// message
$message = '<html><body>
<p>Greetings '.$appraiser['FirstName'].' '.$appraiser['LastName'].',</p>

</body></html>';

// To send HTML mail, the Content-type header must be set
$headers  = 'MIME-Version: 1.0' . "\r\n";
$headers .= 'Content-type: text/html; charset=iso-8859-1' . "\r\n";

// Additional headers
$headers .= 'To: '.$appraiser['Company'].' <'.$appraiser['Email'].'>\r\n';
$headers .= 'From: '.$broker['Company'].' <'.$FromEmail.'>\r\n';

// Mail it
$send=mail($appraiser['Email'], "New Appraisal Order", $message, $headers);

     

    Thanks!

    [SOLVED] Add minutes or hours to time

    in PHP Coding Help

    Posted

    This did it.

     

    I insert it in mysql as the expired time and compair against it.

     

    
connect();

$get_time_limit=mysql_query("select time1 from preferences");
$timelimit=mysql_fetch_assoc($get_time_limit);

$exp=time() + (1 * $timelimit['time1'] * 60 * 60);
$expired=date('Y-m-d H:i:s', $exp);

mysql_free_result($get_time_limit);

     

    Thank you for looking at it.

    [SOLVED] Add minutes or hours to time

    in PHP Coding Help

    Posted

    I am trying to add minutes or hours to $current.

     

    This time should expire after $var hours.

     

    So I need this to compare now() to $expired

     

    
$current="2009-05-30 09:32:23";

$exired="2009-05-30 09:32:23" + $hours;



if ($expired >= now()){
  times up

}else{
  your still good
        }

     

    any suggestion?

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