EchoFool

works a treat! Thankyou !

Thanks MadTechie. The if statement doesn't seem to come out as true though anymore: <?php $Message = $row['Message']; //hiiide quote if (preg_match('%(.*\b\[/quote\])(.*)%si', $Message, $regs)) { { $Var1 = $regs[1]; // "[ quote] [ quote] test [/quote] why are you testing[/quote]" $Var2 = $regs[2]; // " because i want to!" } }Else{ Echo 'failed'; } The failed is being echo'd. Why could that be?

Thankyou for your response. It works a treat! Although to cover all eventualities of a forum post.... it is very common for a message to contain: <?php $Message = $MainMessage = '[ quote] [ quote] test [/quote] why are you testing[/quote] because i want to!'; ?> They may even have more quotes than that. And so at this stage it wouldn't split the message correctly as i just tried it, it cuts the first end quote then nothing after that. Though I still require it to cut into two $vars only no matter how many [ /quote ] tags are invovled. It should end up like: <?php $message[0] = '[ quote] [ quote] test [/quote] why are you testing[/quote]' // the quotes $message[1] = 'because i want to!' // the post Any ideas? Thanks for your response.

I am getting an offset error with my string, and am unsure on how to fix it as i don't totally know what is wrong in the first place..... this is what i have: <?php $MainMessage = '[quote] Hey there![/quote] Hello world!'; //hiiide quote $message = explode('[/quote]', $MainMessage); $quote_times = count($message) - 1; for($m=0;$m<$quote_times - 1;$m++){ $lastpart .= $message[$m].'[/quote]'; } $message[0] = $lastpart.$message[$quote_times - 1].'[/quote]'; $message[1] = $message[$quote_times]; ?> The error: The "real outcome" should be that: $message[0] = '[quote] Hey there![/quote]' $message[1] = 'Hello world!' Not sure why the lastpart variable is not being set? I do also have a question, will this script cause an error when ever the $MainMessage has no [ quote] tags. And also will it double crash if there was a message like: $MainMessage = '[quote] [quote] test [/quote] why are you testing[/quote] because i want to!'; Would this still result as: $message[0] = '[quote] [quote] test [/quote] why are you testing[/quote]' $message[1] = 'because i want to!' Or it will crash it due to more than one tag? I have yet to get it working at all but need to know If i am on the right lines?

Bump

Close to that but the two variables should be become like this: $Var1 = $regs[1]; // [24]Test[25] Thank you for reading![/quote] $Var2 = $regs[2]; // Response 14455. So everything before the last char of " " which is the ] is in one var... and everything after the ] goes to the second var. The original string is: [24]Test[25]Thank you for reading![/quote] Response 14455.

Replace? I'm not trying to convert or replace anything how ever...im not sure if i have misunderstood you, or you have misunderstood me lol. Just to sure, let me simplify it with a simple example say a string has: Hello there! And i wanted to "cut" this string so it become: $Var1 = Hello $Var2 = there! Only for my real situation i need to cut the string "after" the last char of : [/ QUOTE] So "everything" after the ] char from [/ QUOTE] Will go to $Var2 and everything before the ] include the ] itself goes to $Var1. If i were to replace it I would loose tags. The tags need to remain otherwise when echo'd for later use it won't process in the BBCode.

Yeh the tags will be the same every time. I just need to split that paragraph into two variables. Rather than one.

No no. Just to break the string apart From the the first char to the last char of Then to the end of the string.

I am getting lost on how to "extract" part of a variable's string leaving only what needs to be seen. I tried using explode function but that was not allowing it to save the tags around the text with it. This is the paragraph im processing: [24]Test[25]Thank you for reading![/quote] Response 14455. Now this whole paragraph above is in a variable as $Message But i want to forward the message but to stop the user "editing" what is being quoted i want to some how extract the quote. So from [24] to [/ QUOTE] it needs to take. So it then assigns it to a new variable so the new variable will become: [24]Testing[25]Thank you for reading![/quote] Leaving only for the main variable: Response 14455. Can php do this? I know how to explode a string but explodes don't take the symbol that separates the information. I need this to also take the tags with it.

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> I have this at top of my page if that is what you mean ?

For some unknown reason, when I echo a £ symbol related to money it comes out like this: Its a simple echo '£'.$Money; What causes this sort of thing, I have no idea where to begin to look with fixing this problem ???

Thank you for your replies guys! I will give your suggestion a try Ken. Thank you.

I have two time stamps one from a database and one which is "now". I was wondering if there was a way to compare the two to find out if the gap between them is greater than 20 minutes. These are the two fields <?php $Date = $row['SkipDate']; // from database $Date2 = date("Y-m-d H:i:s",time()); // now time ?> Is it a possible thing to do ?

If there is an automated script which creates an array but there is no parametres that match to create this "array" is there a way to check that the array is in simple words... blank? Because at the moment after my while loop which creates the array i have: $_SESSION['MissionID'] = $a[0]; But if the array wasn't greated because all the rows have been used which can happen then obviously $a[0]; won't exist. So i end up with: Notice: Undefined offset: 0 in C:\xampp\htdocs\test.php on line 6431 So was wondering if there was a way to "check" if the array is blank and if it is then skip it. I tried this: <?php If($a[0]>0){ // do it }Else { // do not } Didn't work though. Any suggestions? But that didn't work.

Oh i see. So array's start at [ 0 ] not [1] that would explain why I couldn't grab the value! Thanks Ken. wildteen88 - is array_Shift similar to my shuffle function?

I see so that produces: Array ( [0] => 25 ) Is there a way to extract the 25 to process with that ID?

Changed : $ID = $row['ID']; $a[] = $ID; to $a[] = $row['ID']; Though when i shuffle($a); Then Echo $a; I get "Array" as the response rather than the id. Why could that be?

Argh i fixed my error. Thank you!

Sure here it is: <?php $Find = mysql_query("SELECT ID FROM users") Or die(mysql_error()); If(mysql_num_rows($Find)>0){ $a = array(); While($row = mysql_fetch_assoc($Find)){ $ID = $row['ID']; $a[] = $ID; // this is where the error is } shuffle($a); $_SESSION['MissionID'] = $a; } ?> Thank you for replying

Oh i see thankyou for pointing me in the right direction. With your suggestion Ken, i produce this error: Fatal error: Cannot use [] for reading in C:\xampp\htdocs\missioninclude.php on line 426 Which relates to $a[] = $row['ID'];.

Not sure if i understand this correctly but im getting an error to do with my array syntax.... the idea is it creates a list of id's then picks one at random, but i cannot get it to work... any help is much appreciated. Parse error: syntax error, unexpected '[', expecting ')' in C:\xampp\htdocs\name.php on line 427 Im unsure on what i have done wrong. This is what i got: <?php $SELECT = mysql_query("SELECT ID FROM users") Or die(mysql_error()); $a = 0; While($row = mysql_fetch_assoc($Find)){ $ID = $row['ID']; Array ( [$a] => $ID; ) $a = $a + 1; } shuffle($a); $_SESSION['MissionID'] = $a; ?>

The output which has <div class etc Won't be detected as CSS or HTML because of the functions before it... so itll always come out as a block of chars and nothing else. So if i put [Q] to html ... the html will just come out as just chars .like it is already right? I can't get my head around this properly =/

I do have that.. if a user puts [Q] it converts to : <div class='quotetop'>QUOTE <span class=PositiveMoney> </span></div><div class='quotemain'><span class=NegativeMoney><?=$Message?> And [/Q] converts to: </span></div> But as you can see from above it won't allow it through.. unless im misunderstanding what you mean ?

Bump, any thoughts?