richarro1234
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Posts posted by richarro1234
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Hey all,
i have this peice of code,
it was working fine untill i added the str_replace() command and now it doesnt work.
here is the code:
include("data.php"); mysql_connect($server,$anvandare, $losen); mysql_select_db($databas); $txt = str_replace(";", "<br>", $_POST['newinfo']); $query = mysql_query("UPDATE recipes SET $get = $txt WHERE id = $uid"); header ("Location: editrecipe.php?note=1"); die(); }Thanks
Rich
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yeah, i no the story.
always nowt on this time of day.
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Sweet,
Thanks for the speedy reply rarebit
.Thanks
Rich
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Hey all,
Just wondering.
How do i make a query so that data is pulled out of a mysql database and on the page it only shows the first few lines of an article, like say 2 or 3 lines, then there is a "more.." link that you can click that will load up a new page and show the rest of the article?
How do i go about doin that?
Thanks
Rich
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Oh dear, i could have saved myself alot of time if i had just looked t the databse, but i was certain that there was no other info prior to me making the database.
I feel so silly lol.
Thanks
Rich
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(couldnt find the edit button)
After abit of looking around through the code again and re-organising and changing of the database it finally works.
Thanks to everyone who helped me find the problem.
Thanks
Rich
P.S sorry i couldnt find the edit button.
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hey, i tried your code but it still doesnt show anything up on the page.
here is the link that it is supposed to show up on.
http://lilysretreat.richsprivatesite.com/recipe.php?id=1
Thats the link and this is what it is supposed to show.
http://lilysretreat.richsprivatesite.com/recipelist.php
I added it on there just so i can show you what it is meant to show up when using id 1.
I had sorted the code but i didnt read your sig so i didnt see it. i only posted it so you knew there was a syntax error (im sure you dont care that there is a syntax error, but i didnt think of that this morning either).
Thanks
Rich
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Parse error: syntax error, unexpected T_STRING in D:\wamp\www\mum\recipe.php on line 13
Thanks
Rich
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just tried your code and i got this msg.
"Parse error: syntax error, unexpected ';' in D:\wamp\www\mum\recipe.php on line 5"
Thanks
Rich
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<?php require("header.php"); include("data.php"); //include("funktioner.php"); mysql_connect($server,$anvandare, $losen); mysql_select_db($databas); $cid = $_GET['id']; $query = mysql_query("SELECT * from recipes WHERE id = '$cid'"); while ($rec = mysql_fetch_array($query)) { ?> <center> <?php =$note ?></center> <br> <div align="left"> <table border="1" cellpadding="0" cellspacing="1" style="border-collapse: collapse" width="95%" id="AutoNumber1" bordercolor="#000000" bgcolor="#252525"> <tr> <td width="95%"> <center> <center> <div align="center"> <center> <table border="1" cellpadding="0" cellspacing="0" style="border-collapse: collapse" bordercolor="#5D6765" width="75%" id="AutoNumber1" bgcolor="#131313"> <tr> <td width="100%" bgcolor="#000000" align="center"><font size="2"><b>All Recipes</b></font></td> </tr> <tr> <td width="100%"><br> <div align="left"> <center> <table bgcolor=333333 width=50%> <tr> <td width=50% class=trnext> <table border="1" cellpadding="0" cellspacing="0" style="border-collapse: collapse" bordercolor="#252525" width="100%" id="AutoNumber12"> <tr> <td width="25%" align="center">Name: </td> <td width="100%"><?php echo $rec['name']; ?></td> </tr> </table> <table border="1" cellpadding="0" cellspacing="0" style="border-collapse: collapse" bordercolor="#252525" width="100%" id="AutoNumber12"> <tr> <td width="25%" align="center">Ingrediants: </td> <td width="100%"><?php echo $rec['ingrediants']; ?></td> </tr> </table> <table border="1" cellpadding="0" cellspacing="0" style="border-collapse: collapse" bordercolor="#252525" width="100%" id="AutoNumber12"> <tr> <td width="100%" align="center">Method: </td> </tr> </table> <table border="1" cellpadding="0" cellspacing="0" style="border-collapse: collapse" bordercolor="#252525" width="100%" id="AutoNumber12"> <tr> <td width="100%"><?php echo $rec['method']; ?></td> </tr> </table> </td> </tr> </table> </center> </div><BR><BR> </td> </tr> </table> </center> </div> <?php } ?>Hey i tried your code and to start with it came up with an error sayin "
Parse error: syntax error, unexpected '=' in D:\wamp\www\mum\recipe.php on line 14
"
so i got rid of the <?php =$note ?> and that got rid of the msg, but it still didnt show up any of the results.
Thanks
Rich
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... i need your help again.
i have this piece of code tat is meant to get the id from the address bar and show the relevant info from the database.
It works on my other pages, but it doesnt work on this one, the code has been copied over and it still doesnt work.
it doesnt even show the empty grid where the text is meant to be.
i cant find the problem maybe someone on here can.
Here is the code:
<? require("header.php")?> <? include("data.php"); //include("funktioner.php"); mysql_connect($server,$anvandare, $losen); mysql_select_db($databas); $cid = $_GET['id']; ?> <? $query = mysql_query("SELECT * from recipes WHERE id = $cid"); while ($rec = mysql_fetch_array($query)) { ?> <center> <?=$note?></center> <br> <div align="left"> <table border="1" cellpadding="0" cellspacing="1" style="border-collapse: collapse" width="95%" id="AutoNumber1" bordercolor="#000000" bgcolor="#252525"> <tr> <td width="95%"> <center> <center> <div align="center"> <center> <table border="1" cellpadding="0" cellspacing="0" style="border-collapse: collapse" bordercolor="#5D6765" width="75%" id="AutoNumber1" bgcolor="#131313"> <tr> <td width="100%" bgcolor="#000000" align="center"><font size="2"><b>All Recipes</b></font></td> </tr> <tr> <td width="100%"><br> <div align="left"> <center> <table bgcolor=333333 width=50%> <tr> <td width=50% class=trnext> <table border="1" cellpadding="0" cellspacing="0" style="border-collapse: collapse" bordercolor="#252525" width="100%" id="AutoNumber12"> <tr> <td width="25%" align="center">Name: </td> <td width="100%"><?=$rec['name']?></td> </tr> </table> <table border="1" cellpadding="0" cellspacing="0" style="border-collapse: collapse" bordercolor="#252525" width="100%" id="AutoNumber12"> <tr> <td width="25%" align="center">Ingrediants: </td> <td width="100%"><?=$rec['ingrediants']?></td> </tr> </table> <table border="1" cellpadding="0" cellspacing="0" style="border-collapse: collapse" bordercolor="#252525" width="100%" id="AutoNumber12"> <tr> <td width="100%" align="center">Method: </td> </tr> </table> <table border="1" cellpadding="0" cellspacing="0" style="border-collapse: collapse" bordercolor="#252525" width="100%" id="AutoNumber12"> <tr> <td width="100%"><?=$rec['method']?></td> </tr> </table> </td> </tr> </table> </center> </div><BR><BR> </td> </tr> </table> </center> </div> <?}?>Thanks
Rich
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Oh yeah didnt think of doin it like that.
Thanks for the help roopurt18
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Hey all,
just wondering.
how do i make a text field with multiple words init that will be saved in the database with a <BR> after each word?
heres the plan:
i need a text field where i can seperate words by a ; and when i click submit it saves it in the database with <BR>.
OR
have the words seperated by ; again, but then show up on the website as a list.
so i could have something like:
bananas; oranges; apples; kiwi
and then it show on the webpage like:
bananas
oranges
apples
kiwi
(as a list)
How do i go about doin that?
Anyone able to help me?
Thanks in advanced
Rich
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excellent.
Once again. thanks for all the help MadTechie.
Rich
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It was, but i just noticed another problem.
Now when one is a certain percent, all the colors change to the specified color instead of just that one.
I.E If i do 100% on the kitchen and then go and change todo the study and do 30% on that, then all the %'ages goto green, instead of just the kitchen.
so kitchen should be green as its on 100% but the study should be orange as it is only 30%
Any ideas?
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Yeah, but i posted it like thatbecause i saw others that had solved on it, so i thought i would do that so people knew when it was solved.
but then i noticed at the bottom of the page there is a button that says "solved" so i guess you click it and it marks it as bein solved lol.
if that maks sense.
Rich
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Thanks,
When changing it you had missed abit out.
while ($r = mysql_fetch_array($query)) {I added that under the
$results= mysql_query("SELECT * FROM todo Order by percentage desc");and it works fine.
Thanks soo much for your help.
Rich
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Well what it is, is theres 8 rows in the database and i need to show all of them, thats what the loop is for, so that it shows all the info in the database (its a bit like a news section where you enter it and want to show all the news posted).
But it repreats the information 8 times instead of just once. i will upload it to my server and send the link so you can see exactly what i mean.
Thanks
Rich
EDIT: here is the link http://lilysretreat.richsprivatesite.com/lobby.php
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Hey all,
i have a problem with some code, what im trying to create is a color coded percentage.
so i fill in a field in a database with a number as a %'age of what i have done.
if its under 25% then the color is red under 50 it is orange under 75 it is yellow and 100 is green for file finished.
Now, in the code i have it pull the info out from the database and show it in a list so visitors can see how the files are coming along.
now everything was fine untill i added the code for the colors and if they were under or over a certain %'age, now it repeats the info in the database 8 times and the very last set has the right colors.
so it repeats everythin 7 times and on the 8th time it has the right colors for the right %'age.
Can anyone help me fix this code so that it will only show it once and not 8 times.
Thanks
Rich.
Here is the code: P.S i have already tried limit 1.
<link rel="stylesheet" type="text/css" href="stylenews.css"> <? include('data.php'); //include("funktioner.php"); mysql_connect($server,$anvandare, $losen); mysql_select_db($databas); $query = mysql_query("SELECT * from todo Order by percentage"); while ($r = mysql_fetch_array($query)) { ?> <? if ($r[$percentage] <= 25) { $fontcol=red; } if ($r[$percentage] >= 25) { $fontcol=orange; } if ($r[$percentage] >= 50) { $fontcol=yellow; } if ($r[$percentage] >=75) { $fontcol=green; } if ($r[$percentage] >=100) { $fontcol=green; } ?> <center> <?=$note?></center> <div align="center"> <center> <table border="0" cellpadding="0" cellspacing="0" style="border-collapse: collapse" bordercolor="#5D6765" width="95%" id="AutoNumber1"> <tr> <td width="100%"><br> <? $results= mysql_query("SELECT * FROM todo Order by percentage desc"); $id = "id"; $name = "name"; $description = "description"; $left_to_do = "left to do"; $percentage = "percentage"; echo mysql_error(); if (mysql_Numrows($results)>0) //if there are records in the fields { $numrows=mysql_NumRows($results); //count them $x=0; while ($x<$numrows){ //loop through the records $theid=mysql_result($results,$x,$id); $thename=mysql_result($results,$x,$name); $thedescription=mysql_result($results,$x,$description); $theltd=mysql_result($results,$x,$left_to_do); $thepercentage=mysql_result($results,$x,$percentage); ?> <table width="100%"> <tr> <th class="subcat" width="60%"> <font size="3"><?=$thename?>:</font> </th> <th class="subcat"> <font size="2">Done so far: <font color="<?=$fontcol?>"><?=$thepercentage?>%</font> </th> </tr> <tr> <td colspan="2" class="row2"> Design Page.<BR> <?=$theltd?></td> </tr> </table> <BR> <? $x++; } } else { ?> <center><b>There is nothing left to do !</b></center> <br> <? } ?> </td> </tr> </table> </center> </div> <?}?>
Can you look at this and tell me whats wrong please.
in PHP Coding Help
Posted
Hey sorry, i was thinking of the wrong command whilst adding it, i have changed it now.
Well it comes up with a msg saying that it has been added to the database (which i have added as a bit of code a bit further up the page) but it doesnt update the database.
As it work s it just doesnt update the database then theres no errors.
Thanks
Rich