Jump to content

helraizer

Members
 View Profile  See their activity

  • Posts

    401

  • Joined

  • Last visited

 Content Type 

Posts posted by helraizer

    getting X, Y values of text in string on image

    in PHP Coding Help

    Posted

    Ok, more information about the problem.

     

    Explanation: I have a main page for my shoutbox, which contains a form for a user to input a username, message, font(select menu), colour(select), which posts to itself and adds the information they just posted to the database, the image then takes this information and makes an image from it.

     

    In the main page there is an dynamically created image.

     

    showimage.php

     

    <?php
$user_id = mysql_real_escape_string(htmlspecialchars($_GET['uid']));

$sqls = "SELECT username FROM user WHERE user_id='$user_id'";

$results = mysql_query($sqls) or die("error in  sqls: " . mysql_error());
$rows = mysql_fetch_array($results);

$counts = mysql_num_rows($results);
$font = "palab.ttf";
    $user = $rows['username'];
    $_SESSION['user'] = $user;


$im = ImageCreate(230, 35);
$black_a = imagecolorallocate($im, 0, 0, 0);
$white_a = imagecolortransparent($im, $black);
$white = ImageColorAllocate($im, 255, 255, 255);
ImageFill($im, 0, 0, $white_a);
Imagettftext($im, 15, 0, 10, 30, $white, $font, $user . "'s Shoutbox");

$grin = imagecreatefromgif("icon_lol.gif");
$blark = ImageColorAllocate($grin, 0, 0, 0);


//$image = ImageCreate(660,240); // create the image canvas
$image = ImageCreateFromGIF("660x240background2.gif");
$blue = ImageColorAllocate($image, 200, 200, 255); // prepare some blueness
$black = ImageColorAllocate($image, 0, 0, 0); // ... and whiteness

$cur_line_y = 60; // This stores how far down the image the current line will print
$cur_line_x = 24; // This stores how far across the image the current line will print
$pagecharwidth = 75; // this is the maximum length of the line before it wraps;
$lineheight = 18; // This is how much to move down to print the next line
$pagelinelimit = 1; // This is the maximum number lines of text that can be displayed


//ImageString($image, 3, 15, $cur_line_y, trim(stripslashes($wordwrapped[0])), $black);

$numberOfLines = $pagelinelimit;


$sql = "SELECT * FROM user INNER JOIN tblcomments ON tblcomments.user_id=user.user_id INNER JOIN tblattributes ON tblcomments.id = tblattributes.id INNER JOIN tblip ON tblattributes.id = tblip.id  WHERE tblcomments.user_id='$user_id' AND tblattributes.user_id='$user_id' AND tblip.user_id='$user_id' ORDER BY tblcomments.`id` DESC LIMIT 0,10";

$result = mysql_query($sql) or die("error in  sql: " . mysql_error());

for ($i = 0; $i < $numberOfLines; $i++) {
    while ($row = mysql_fetch_array($result)) {


 $name = "[" . htmlspecialchars_decode($row['username']) . "] ";
        $font = $row['font'];
        $color = $row['color'];
        $line = htmlspecialchars_decode($row['comment']);



        if ($name == "[] ") {
            $name = "";

            $line = $name . $line;
        } else {

            $line = $name . $line;
        }

        if ($color == "white" || $color == "yellow" || $color == "green" || $color ==
            "orange" || $color == "aqua") {
            Imagettftext($image, 10, 0, $cur_line_x, $cur_line_y, getColor($color), getfont
                ($font), trim($line));


        } elseif ($color != "white" || $color != "yellow" || $color != "green" || $color !=
        "orange" || $color != "aqua") {
            Imagettftext($image, 10, 0, $cur_line_x, $cur_line_y, $white, getfont($font),
                trim($line));


        } elseif ($font == "fixedsys" || $font == "Courbd" || $font == "arial" || $font ==
        "timesnr" || $font == "calibri" || $font == "comicsans" || $font == "palab") {
            Imagettftext($image, 10, 0, $cur_line_x, $cur_line_y, getColor($color), getfont
                ($font), trim($line));


        } else {
            Imagettftext($image, 10, 0, $cur_line_x, $cur_line_y, $white, "courbd.ttf", trim
                ($line));


        }

        $cur_line_y += $lineheight;


    }


}


function getColor($color)
{
    global $image;

    switch ($color) {
        case "white":
            return ImageColorAllocate($image, 255, 255, 255);
        case "yellow":
            return ImageColorAllocate($image, 255, 255, 0);
        case "green":
            return ImageColorAllocate($image, 0, 255, 0);
        case "orange":
            return ImageColorAllocate($image, 255, 127, 36);
        case "aqua":
            return ImageColorAllocate($image, 0, 255, 255);
        default:
            return ImageColorAllocate($image, 255, 255, 0);

    }
}


function getfont($font)
{
    global $image;
    global $font;

    switch ($font) {
        case "fixedsys":
            return "fixedsys.ttf";
        case "Courbd":
            return "courbd.ttf";
        case "arial":
            return "arialbd.ttf";
        case "calibri":
            return "calibrib.ttf";
        case "comicsans":
            return "comicsans.ttf";
        case "palab":
            return "palab.ttf";
        default:
            return "palab.ttf";
    }
}

ImageCopyMerge($image, $im, 20, 0, 0, 0, 230, 50, 100);

header("Content-Type: image/gif"); // tell the browser what we're gonna give it
imagegif($image); // paint the image in browser
imagegif($image, "user/" . $user . ".gif"); //export as gif file
ImageDestroy($image); // clean up resources

?>

     

    This is the code for the image, on the main page if the posted comment contains =D, :D, :D or =d a session is started $_SESSION['smile'];

     

    For this in shoutbox.php:

    <?php // tag only for highlighting
$smiles = array('=D', "=d", "", "");
foreach($smiles as $smile) {
if (preg_match("/$smile/i", $text)) {
$_SESSION['smile'] = $smile;
}
}
?>

     

    I attempted to use, in showimage.php

     

    <?php
if (isset($_SESSION['smile'])) {

    $smile = $_SESSION['smile'];

    if (preg_match("/$smile/i", $line)) {
        list(, , , , , , ,$left, $top) = imagettfbbox(10, 0, getfont($font), $smile);

        imagecopymerge($image, $grin, $left, $top, 0, 0, 15, 15, 100);
    }

}
?>

     

    but to no avail, it didn't work; I even changed $left and $top in the imagecopymerge to 350 and 100, respectively. This would have shown if the image was being rendered ontop of the main image, but for some reason it didn't show up at all.. any ideas?

     

    Also, will that imagettfbbox(10, 0, getfont($font), $smile) return the coordinates for the '=D' in relation to its place in the line of text? If not, how would I get that to work?

     

    Hope that makes more sense,

    Sam

    getting X, Y values of text in string on image

    in PHP Coding Help

    Posted

    Hi folks,

     

    I have a script that pulls user comments from a database, which works fine.

     

    It's an image based script so I'm trying to now add emoticons, for such as =D or =)

     

    To do this I plan to use list(,,,,,,$left,$top) for the imagettfbox of where =D or =) can be found in the text..

     

    How would I get php to return the location of where the '=D' is in the text? Str_split wouldn't work well enough.

     

    How could I then, from getting the location of it, get it in a imagettfbbox to get the top left X and Y values for it in relation to the text?

     

    Hope that makes sense.

     

    Sam

    Desperate for help with web counter script

    in Third Party Scripts

    Posted

    From what I can see it's because you're using

     

    
$fp = fopen("./stats.txt","w");

     

    the "w" is what's causing it to reset, because as it says in the manual

    'w' - Open for writing only; place the file pointer at the beginning of the file and truncate the file to zero length. If the file does not exist, attempt to create it.

     

    You want to use "a", which appends the file, so adds all the new data to the end of the existing instead of overwriting.

     

    
$fp = fopen("./stats.txt","a");

     

    'a'  - Open for writing only; place the file pointer at the end of the file. If the file does not exist, attempt to create it.

    Sam

    Recommend a PHP Site Tracking Script

    in Third Party Scripts

    Posted

    It'd be very simple to write your own.

     

    Either flat file :

     

    php5

    <?php
$ip = $_SERVER['REMOTE_ADDR'];

$filename = "hits.txt";
file_put_contents($filename, $ip, FILE_APPEND);

$file = file("hits.txt");
$num = count($file);

echo "This page has been viewed $num times";
?>

     

    php4

    $ip = $_SERVER['REMOTE_ADDR'];
$filename = "hits.txt";

$fp = fopen($filename);

fwrite($fp, $ip);

fclose($fp);

$file = file($filename);
$num = count($file);

echo "This page has been viewed $num times";

     

    or with a database:

    assuming a table called hits with field IP(unique and primary key)

     

$ip=$_SERVER['REMOTE_ADDR'];

$sql = "REPLACE INTO `hits` (`IP`) VALUES ('$ip')";
$result = mysql_query($sql) or die("Error in sql: ".mysql_error());

$sql_a = "SELECT Count(ip) FROM `hits`";
$result_a = mysql_query($sql_a) or die("Error in sql_a: ".mysql_error());

$row  = mysql_fetch_array($result_a);
$num = $row['Count(ip)'];

echo "this page has been viewed $num times";

     

    Untested but should work. Only took maybe 3 minutes to write on the fly so just mess around with those. Unless you want an image based one..

     

    Hope that helps

    Sam

    JustShout! image based shoutbox

    in Beta Test Your Stuff!

    Posted

    Hi folks, I've implimented a number of new things for my shoutbox called JustShout!

     

    There is now a version called 'JustShout!Mini' that people can use on a standard myspace page with image and form.

     

    It does not require registration to post a comment but to get your own shoutbox you can register.

     

    Could you guys please beta test it for me?

     

    http://www.helraizer.co.uk/mychatbox/

     

    and

     

    http://www.helraizer.co.uk/mychatbox/mini/

     

    Thanks,

    Sam

    help and ideas needed

    in PHP Coding Help

    Posted

    Sorry for the double post.

     

    Fixed it now! Instead of using header() I sacrificed some speed and used a meta refresh to the redirect variable. So now it goes to my page, loads it - image and all, then goes back to their page, with the image all updated.

     

    Sam

    Echo

    in PHP Coding Help

    Posted

    If I've understood what you meant, you could use it like

     

    $myvar = "variables";

$var = <<<MYVARIABLE
This is my variable containing 'single' quotes and "double" quotes.
It also parses other $myvar

I can have any characters in this variable, then to end it like this!

MYVARIABLE;

echo $var;

     

    It can be used like that.

     

    Sam

    Echo

    in PHP Coding Help

    Posted

    It's known as HEREDOC and it is generally used for long strings with both single and double quotes and variables.

     

    It means you don't need to escape anything so no \' \" or anything.

     

    I use it for long amounts of text with particular formats, like emails etc...

     

    Hope that helps?

     

    Sam

    Shoutbox

    in Beta Test Your Stuff!

    Posted

    Back to the Beta Testing side of things, there is a big security flaw (XSS). You haven't protected any of your variabless so people can use executable scripts in the message field. Which could be potentially dangerous.

     

    Sam

    help and ideas needed

    in PHP Coding Help

    Posted

    Hi folks,

     

    I apologise for the thread title, couldn't think of a more suitable one.

     

    At the moment I have made a mini shoutbox that can be used on myspace, or similar. The image is then shown on the user's myspace and the form to post a comment can also be included too. As a hidden field they will put their myspace URL, which means that as soon as they post it goes to mysite but instantaneously redirects them to their myspace page.

     

    At the moment it does post the comment to the shoutbox... The problem I have is that on the site it posts to, normally holds/hosts the image (myspace_image.php) that pull the information from the database and adds it the shoutbox image (the image that is on their myspace). So since it doesn't load this picture before it is redirected when they post from myspace, their comment doesn't appear on the image until someone views/loads the myspace_image.php file even on the shoutbox page on my site..

     

    Does anyone know how I can get around this? It somehow needs to load the image before it/as it redirects to their myspace, so that the comment appears on it. 

     

    I tried

     

    <?php

$browser = new COM("InternetExplorer.Application");
$handle = $browser->HWND;
$browser->Visible = false;
$browser->Navigate("http://www.helraizer.co.uk/mychatbox/mypsace_image.php5?uid=".$user_id);

while ($browser->Busy) {
com_message_pump(4000);
}

$browser->Quit();


?>

     

    which should open up the page in a different browser/window, but that only works on a Windows server, mine is UNIX... so that doesn't work.

     

    Thanks for any suggestions,

    Sam

    UNEXPECTED T_STRING

    in PHP Coding Help

    Posted 

    <?php
$get_articles = "select id, alias, article from dirt_digger";
$get_articles_res = mysql_query($get_articles,$conn) or die(mysql_error());

while ($article_info = mysql_fetch_array($get_articles_res)) {
$alias = $article_info[alias];
$title = $article_info[title];
$article = $article_info[article];

$display_block .= "<h1 class="title">$title</h1><br /> $article <br /><br />Author:<br /><strong>$alias</strong><br /><br />"; //line 13
}

?>

     

    the reason is here

    "<h1 class="title">$title</h1>...

     

    You should either escape the quotes \" or use '  because your php variable is within "" - $display_block = "..."

     

    so when you came to the class you used "" again, which escaped the php variable..

     

    change it to

     

     <?php
$display_block .= "<h1 class='title'>".$title."</h1><br />". $article . "<br /><br />Author:<br /><strong>".$alias."</strong><br /><br />";
?>

     

    Sam

    UNEXPECTED T_STRING

    in PHP Coding Help

    Posted

    When all your code is on one line it's hard to find line 13 but it's because you have

     

    this

    <?php
$update_db = "insert into dirt_digger values ('', '$_POST[alias]', '$_POST[title]', '$_POST[article]') or die(mysql_error());
mysql_query($update_db,$conn) or die(mysql_error());
$msg = "Thanks for your dirt, <strong>$_POST[alias]</strong>. Your support and help wiht exposing Hempfield is appreciated!";
?>

     

    should be

    <?php
$update_db = "insert into dirt_digger values ('', '$_POST[alias]', '$_POST[title]', '$_POST[article]')" or die(mysql_error()); // added second/end quote marks.
mysql_query($update_db,$conn) or die(mysql_error());
$msg = "Thanks for your dirt, <strong>$_POST[alias]</strong>. Your support and help wiht exposing Hempfield is appreciated!";
?>

     

    Protect from Header injection?

    in PHP Coding Help

    Posted

    the possibilities of redirects you have should be limited so you can use an array

    <?php
$pages =  array("index.php", "login.php", "exit.php");
if(isset($_POST['redirect'])){
if(in_array($_POST['redirect'],$pages)){
header("location: ".htmlspecialchars($_POST['redirect']));
}
else{
header("location: ".$pages[0]);
}
?>

    simple idea

     

    That's an interesting idea and I'll keep it in mind but the user would have to decide then and there where they want to host the shoutbox on their site and post the URL for me to save it in an array. This limits things because then if they change the location they would have to repost the location and thus update the array each time.

     

    Sam

     

    Any other ideas?

    Protect from Header injection?

    in PHP Coding Help

    Posted

    Hi folks,

     

    I am setting up a form for users to post shouts for their shoutbox from their site (external from mine), so on their form there is a hidden field named "redirect". On my page I have this code.

     

    if(isset($_POST['redirect'])) {
$redirect = htmlspecialchars($_POST['redirect']);

header("Location:".$redirect);
exit;

} else {}

     

    but this leaves it open to XSS and Header Injection.. How can I protect against this effectively?

     

    Thanks,

    Sam

    Excel VBA help needed

    in Other Programming Languages

    Posted

    Hi folks,

     

    I am making a spreadsheet for a foreign exchange bureau, on the loading of the page it asks the operator to add the day's exchange rates.

     

    I have the following code in Excel VBA

     

    Private Sub Worksheet_Open()

Worksheets("Rates").Activate

'GBP to Euro

Dim varInput As String

varInput = InputBox("Please enter today's rates from GBP to EUR", "Exchange Rates", "e.g. 0.765")

Range("C11").Select

If(varInput = "") Then
Selection.Value = Range("C11").Value

Elseif(varInput = "e.g. 0.765") Then
MsgBox "Please enter a proper value.", vbOkOnly, "System Message"

Else

Selection.Value = varInput



'GBP to American Dollars

Dim varInput As String

varInputa = InputBox("Please enter today's rates from GBP to USD", "Exchange Rates", "e.g. 0.765")

Range("C12").Select

If(varInputa = "") Then
Selection.Value = Range("C12").Value

Elseif(varInputa = "e.g. 0.765") Then
MsgBox "Please enter a proper value.", vbOkOnly, "System Message"

Else

Selection.Value = varInputa


'GBP to Japanese Yen


Dim varInputb As String

varInputb = InputBox("Please enter today's rates from GBP to YEN", "Exchange Rates", "e.g. 0.765")

Range("C13").Select

If(varInputb = "") Then
Selection.Value = Range("C13").Value

Elseif(varInputb = "e.g. 0.765") Then
MsgBox "Please enter a proper value.", vbOkOnly, "System Message"

Else

Selection.Value = varInputb


'GBP to Canadian Dollars



Dim varInputc As String

varInputc = InputBox("Please enter today's rates from GBP to CAD", "Exchange Rates", "e.g. 0.765")

Range("C14").Select

If(varInputc = "") Then
Selection.Value = Range("C14").Value

Elseif(varInputc = "e.g. 0.765") Then
MsgBox "Please enter a proper value.", vbOkOnly, "System Message"

Else

Selection.Value = varInputc


'GBP to Australian Dollars



Dim varInputd As String

varInputd = InputBox("Please enter today's rates from GBP to AUD", "Exchange Rates", "e.g. 0.765")

Range("C15").Select

If(varInputd = "") Then
Selection.Value = Range("C15").Value

Elseif(varInputd = "e.g. 0.765") Then
MsgBox "Please enter a proper value.", vbOkOnly, "System Message"

Else

Selection.Value = varInputd

End Sub

     

    That works perfectly, but at the moment if the value is the default value of the InputBox ("e.g. 0.765") it just throws up the error message and then moves on to the next part.

     

    How would I make it so that, without having to repeat the first bit of code (inputbox code) each time, if the elseif statement is executed it gives the error message (msgbox) and then prompts them again to enter a value for the same rate?

     

    Hope that makes sense,

    Sam

    logout script help..

    in PHP Coding Help

    Posted

    Hi folks,

     

    I have a perfectly functioning login and logout script but it has one flaw... It is all done by sessions..

     

    I have this code

    login.php

    <?php
if (isset($_POST['submit'])) {
    if ($_POST['user'] == "" || $_POST['pass'] == "") {
        $errors[] .= _INCORRECT;

    } else {
    }

    $username = mysql_real_escape_string(htmlspecialchars($_POST['user']));
    $password = mysql_real_escape_string(md5(sha1($_POST['pass'])));
    $_SESSION['user'] = $username;
    $_SESSION['pass'] = $password;
$date = date("Y-m-d G:i:s");

    $sql = "SELECT * FROM `web86-chatbox-1`.`user` WHERE `user`.`username`='$username' AND `user`.`password`='$password'";

    $result = mysql_query($sql);
    
    $row = mysql_fetch_array($result);
    
      $count = mysql_num_rows($result);

    if ($count == 1) {
  if($row['active'] == 0) {
	echo ('<div class="ddgb_entrybox">
	<table width="100%" border="0" cellspacing="8" cellpadding="0">
	<tr>
    <td width="42%" align="right" valign="top"></td>
	<td align="center" valign="top">
            <h2> ' . _ERROR . '</h2><ul>
             
              <li> ' . _INACTIVE . '</li>
            
            </ul>
            <br><br><br>
</td>
	</tr>
	</table>
	</div>');
} else {
        $sqli = "UPDATE user SET user.logged_in = 1 WHERE username='$username' AND password='$password'";

        $resulti = mysql_query($sqli);

	$sqlx = "UPDATE user SET last_login = '$date' WHERE username='$username' AND password='$password'";
	$resultx = mysql_query($sqlx);

	unset($_SESSION['logged']);
        $_SESSION['login'] = 1;
        session_register("user");
        session_register("pass");
        $_SESSION['user'] = $username;
        $_SESSION['pass'] = $password;
        header("Location: index.php5");
        exit();

}
    } else {
        echo ('<div class="ddgb_entrybox">
	<table width="100%" border="0" cellspacing="8" cellpadding="0">
	<tr>
    <td width="42%" align="right" valign="top"></td>
	<td align="center" valign="top">
            <h2> ' . _ERROR . '</h2><ul>
             
              <li> ' . _LOGIN . '</li>
            
            </ul>
            <br><br><br>
</td>
	</tr>
	</table>
	</div>');
    }

    if (isset($_POST['submit']) && $errors[0] != null) {
        echo '    <div class="ddgb_entrybox">
	<table width="100%" border="0" cellspacing="8" cellpadding="0">
	<tr>
    <td width="42%" align="right" valign="top"></td>
	<td align="center" valign="top">';
        echo "<h2>" . _ERROR . "</h2><ul>";
        foreach ($errors as $f) {
            echo "<li>" . $f . "</li>";
        }
        echo "</ul>";
        echo '<br><br><br>
</td>
	</tr>
	</table>
	</div>';

    }

}

?>

     

    and with logout.php

    <?php

if(isset($_SESSION['login'])) {
$username = $_SESSION['user'];
$password = $_SESSION['pass'];
$_SESSION['logged'] = 1;

$sqli = "UPDATE user SET user.logged_in = 0 WHERE username='$username' AND password='$password'";	

$resulti = mysql_query($sqli) or die("Error with sql: ".mysql_error());

unset($_SESSION['login']);

echo ('<div class="ddgb_entrybox">
	<table width="100%" border="0" cellspacing="8" cellpadding="0">
	<tr>
    <td width="42%" align="right" valign="top"></td>
	<td align="center" valign="top">
            <h2> '. _SUCCESS . '</h2><ul>
             
              <li> '. _LOGGED_OUT . '</li>
            
            </ul>
            <br><br><br>
</td>
	</tr>
	</table>
	</div>');




} else {
die('<div class="ddgb_entrybox">
	<table width="100%" border="0" cellspacing="8" cellpadding="0">
	<tr>
    <td width="42%" align="right" valign="top"></td>
	<td align="center" valign="top">
            <h2> '. _ERROR . '</h2><ul>
             
              <li> '. _LOGGED_IN . '</li>
            
            </ul>
            <br><br><br>
</td>
	</tr>
	</table>
	</div>');
}
?>

     

    At the bottom of each page I have 

    <?php
$user = $_SESSION['user'];
$pass = $_SESSION['pass'];

$sql_f = "SELECT COUNT(logged_in) FROM user WHERE logged_in='1'";
$result_f = mysql_query($sql_f) or die("Error in part sql_f: ".mysql_error());
$row = mysql_fetch_array($result_f); 

$online = $row['COUNT(logged_in)'];

$sql_g = "SELECT COUNT(user_id) FROM user";
$result_g = mysql_query($sql_g) or die("Error in part sql_g: ".mysql_error());
$rows = mysql_fetch_array($result_g);

$total = $rows['COUNT(user_id)'];

if ($online == 1 ) {
echo "<div align='left'><center>There is currently ". $online . " user online.</center></div>";
}
else {
echo "<div align='left'><center>There are currently ". $online . " users online.</center></div>";	
}
if ($total == 1 ) {
  echo "<div align='left'><center>There is currently ". $total . " user registered.</center></div>";
}
else {
  echo "<div align='left'><center>There are currently ". $total . " users registered.</center></div>";	
}
?>

     

    The problem is that when the user logs in, the value 'logged_in' on the database is set to 1, so the bottom of the page says "there is currently 1 user online", which is fine.

     

    But only when they go to 'logout.php' does it change 'logged_in' back to 0, so if the user closes the window before going to logout.php the database is still set to 1, but they have been logged out.. so the bottom still says "there is currently 1 user online", even though no one is logged in.

     

    How would I make it that if $_SESSION['login'] is unset on any page, then 'logged_in' is set back to 0?

     

    I can imagine it's

     

    if(!isset($_SESSION['login']) {

$sql = "UPDATE user SET user.logged_in = 0";
$result = mysql_query($sql) or die("Error in SQL part 1: ".mysql_error());
}

     

    but how would I form the WHERE claus? I can't use $_SESSION['user'] and $_SESSION['pass'] because they won't be set...

     

    Any ideas?

     

    Thanks,

    Sam

    Php Help!!

    in PHP Coding Help

    Posted

    ??? Im Stuck! I been stuck for  a long time  :'(

     

    Okay im trying to add keywords/categories.

     

    Right Now i got a Multi upload image hoster. When you upload images it gose to a page that displays links. On that page i am trying to put a box with Keyword input box and a List box with the categories. When a user uploads more than one image code below is just repeted.

     

    I finished the part to search the database but i cant add the keywords to the database i keep failing.

     

    The Database is called

     

    mmh_file_storage

          -file_id 

    -filename

    -gallery_id

    -album_id

    -file_title

        -keyword

        -categories

     

    <if="is_file($mmhclass->info->root_path.$mmhclass->info->config['upload_path'].$mmhclass->funcs->thumbnail_name("<# FILENAME #>")) == false && preg_match("/links|viewer/", $mmhclass->input->server_vars['php_self']) == false && $mmhclass->templ->templ_globals['extension'] != "bmp" && $mmhclass->templ->templ_globals['extension'] != "ico"">
<div style="text-align: center;">
<b>Notice</b>: Failed to generate thumbnail for file <b><# FILENAME #></b> because of an internal error.
<br /><br />
</div>
</endif>
<if="preg_match("/viewer/", $mmhclass->input->server_vars['php_self']) == false">
<div style="text-align: center;">
<a href="viewer.php?file=<# FILENAME #>" class="button1">View Full Image</a>
</div>
<br />
</endif>
<table cellpadding="5" cellspacing="0" width="100%">
<tr>

<td style="width: 80%;">
<table width="100%" border="0" cellspacing="1" cellpadding="0">
<tr>
<td><input readonly="readonly" class="input_field" onclick="javascript:highlight(this);" type="text" style="width: 310px" name="option" value="<# BASE_URL #><# UPLOAD_PATH #><# FILENAME #>" /></td>
<td>Direct Link</td>
</tr>
<tr>
<td><input readonly="readonly" class="input_field" onclick="javascript:highlight(this);" type="text" style="width: 310px" name="option" value="<a href="<# BASE_URL #>viewer.php?file=<# FILENAME #>"><img src="<# THUMBNAIL #>" border="0" alt="<# FILENAME #>" /></a>" /></td>
<td>Thumbnail for Websites</td>
</tr>
<tr>
<td><input readonly="readonly" class="input_field" onclick="javascript:highlight(this);" type="text" style="width: 310px" name="option" value="[url=<# BASE_URL #>viewer.php?file=<# FILENAME #>][img=<# THUMBNAIL #>][/url]" /></td>
<td>Thumbnail for forums</td>
</tr>
<tr>
<td><input readonly="readonly" class="input_field" onclick="javascript:highlight(this);" type="text" style="width: 310px" name="option" value="Thanks to <# SITE_NAME #> for <a href="<# BASE_URL #>">Free image hosting</a>" /></td>
<td>Link to us</td>
</tr>
<tr>
<td><input readonly="readonly" class="input_field" onclick="javascript:highlight(this);" type="text" style="width: 310px" name="option" value="[url=<# BASE_URL #>][img=<# BASE_URL #><# UPLOAD_PATH #><# FILENAME #>][/url]" /></td>
<td>Hotlink for forums</td>
</tr>
<tr>
<td><input readonly="readonly" class="input_field" onclick="javascript:highlight(this);" type="text" style="width: 310px" name="option" value="<a href="<# BASE_URL #>"><img src="<# BASE_URL #><# UPLOAD_PATH #><# FILENAME #>" border="0" alt="<# SITE_NAME #>" /></a>" /></td>
<td>Hotlink for Websites</td>
</tr>
</table>
</td>
</tr>
</table>

     

    Why on Earth have you used all your php in < > tags? <if=.. </endif>.. i've never seen that syntax before... that could just be me but still..

     

    To add the keywords in php use

     

     <?php
$sql = "INSERT INTO (`file_id`,`filename`,`gallery_id`,`album_id`,`file_title`,`keyword`,`categories`) VALUES (NULL,'$filename','$gallery_id','$album_id','$file_title','$keyword','$category')"; //NULL assuming the id is auto_increment 

$result = mysql_query($sql) or die("Error in sql: ".mysql_error());
?>

     

    Sam

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.