Aiiron

I have to in order to generate the ID (it fetches functions from another file) -- any clue how to echo a variable in a variable, though?

anyone?

Hey guys, I am new here (and somewhat new to coding in general, though I am getting the hang of it). I searched php help forums on Google and ended up here. ANYWAY... I really hope you guys can help me out, I'd love to contribute to this forum every day Okay, on to my question... Is there any way that I can ECHO a variable into another variable? I don't mean like $var = $var2 (that would be pointless), I mean something like $var = echo $var2. Is there a function for that? The reason that I need to do this is... My variable contains javascript, like so: $url='http://www.esnips.com/nsdoc/'. $file .'<script type="text/javascript"> document.write("/?id=" + new Date().getTime() + "")</script>'; The javascript is to generate "id". I want to include that variable in another function like include($url); and similar situations without it literally showing the javascript. If I run the include command for this I get: http://www.esnips.com/nsdoc/XXXXXXXXX/<script type="text/javascript"> document.write("/?id=" + new Date().getTime() + "")</script> But if I echo it I get: http://www.esnips.com/nsdoc/XXXXXXXXX/?id=XXXXXXXX (which is how it should be) So is there any way I can ECHO the variable into an include situation or another variable without it taking the javascript literally? Thanks so much in advance.