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quillspirit

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Posts posted by quillspirit

  1. Actually I came across a little script somewhere that allows you to enter a .php url into a form, and you can view the unparsed source of any .php page, remotely hosted... it IS possible. Kinda freaked me out when I saw how easy it was. Looks like Zend is my best option, as I can't afford to pay out of pocket for that other one. I just need to figure out how to use it.
  2. How can I secure my db.php (I have it named something else) page so if somebody finds it, they can't just view source and see the database login information? Is there a way to easily encrypt it? I've heard of Zend, and know it is enabled on my server, but I have NO clue as to how to use it. Please give me some suggestions. Thanks!
  3. It is important that you don't have any kind of output before session_start(); - except for coments. A space between php open and session_start(); will killl you.

    correct:

    [code]
    <?
    session_start();

    session_destroy();
    ?>[/code]

    Incorrect:
    [code]
    <?

    session_start();

    session_destroy();
    ?>[/code]
  4. Have you checked that your form is actually posting employeenumber?
    On that previous page, after the form is submitted, try something like this...
    [code]if (isset($empcode))
    {
    echo "Employee: $empcode";
    } else { echo "Null"; }[/code]

    If it returns as Null, then your problem is in the form.

    Also, when setting your session variable... session_register

    [code]               
    session_register('empcode');
    $_SESSION['empcode'] = $empcode;[/code]
  5. [quote author=ober link=topic=107125.msg429329#msg429329 date=1157559486]
    I assume you set $_SESSION['empcode'] on another page?

    $_SESSION['empcode'] = "blah";

    That should be on a previous page.  Also, make sure you're not using the "back" button in your browser to go back and reset the value.

    You can also try print_r($_SESSION) to look at what is in the session array.
    [/quote]

    Thanks for that... I've been trying to figure out how to see what is in the session array. You gave me a parse error though... don't forget the blessed ; !!

    print_r($_SESSION);
  6. I need to pull up all [b]distinct[/b] userid_numbers out of [i]table1[/i] (To see who is online and in that location, excluding duplicate results), and then query [i]table2[/i] for each userid_number to get profile information, and then display in a table on the website.

    So basically, I need to join these two queries...

    [code]$query1 = "SELECT DISTINCT usernumber FROM table1 WHERE useronline_location='$location'";[/code]

    to get the list of usernumbers (in an array?)... then run the following query in a loop, so it gets the information for each usernumber...

    [code]$query2 = "SELECT * FROM table2 WHERE uidnum='$usernumber'";

    // Display table here

    [/code]



    Can somebody assist? Thanks
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