plodos
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Posts posted by plodos
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I changed the location of unset($_REQUEST['wrong_code9']); and it is solved
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URL is coming from header("Location:".$_SERVER['HTTP_REFERER']."?wrong_code9=true");
http://aaaa.com/add_new_reviewer.php?wrong_code9=true
add_new_reviewer_save.php
<?php if(isset($_REQUEST['wrong_code9'])) { unset($_REQUEST['wrong_code9']); header("Location:".$_SERVER['HTTP_REFERER']."&wrong_code=true"); } else { header("Location:".$_SERVER['HTTP_REFERER']."?wrong_code=true"); } ?>URL is coming than if(isset($_REQUEST['wrong_code9'])) if that is true
unset($_REQUEST['wrong_code9']); than activate wrong_code=true
but unset is not working, WHY ?
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this one is not working
<?php <? if(isset($_GET['wrong_code25'])){ header( "refresh: 3; url=http://{$_SERVER['SERVER_NAME']}/index.php" ); ?> <table><tr><td> Thank you for registration.<br /> Wait, you are redirecting to login page.<br /> </td></tr></table> <? }?> ?>maybe i will change the algorithm
Thanks for everything.
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process.php
<?php if($result){ header("Location:".$_SERVER['HTTP_REFERER']."?wrong_code25=true"); } ?>registration.php
//HTML codes <table><tr><td> <?php if(isset($_GET['wrong_code25'])){ ?> Thank you for registration.<br /> Wait, you are redirecting to login page.<br /> <?php header("refresh 3; url=http://{$_SERVER['SERVER_NAME']}/index.php"); } ?> </td></tr></table> //HTML codesprocess.php sending the wrong_code25=true, than
registration.php is SET the wrong_code25 and showing the Thank you part.
But HEADER() part is not working:s and there is no error!. WHY ?
OR
Can any body give me a hint how to redirect with different ways?
Thanks in advance
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revraz, you know what are you doing
i dont know how many times you solved my problems
thank you one more time
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sql table
CREATE TABLE IF NOT EXISTS `paper` ( `id` int(11) NOT NULL auto_increment, `title` text collate latin1_general_ci NOT NULL, `abstract` text collate latin1_general_ci NOT NULL, `keywords` varchar(50) collate latin1_general_ci NOT NULL, `authors` varchar(50) collate latin1_general_ci NOT NULL, `status` varchar(50) collate latin1_general_ci NOT NULL, `ext` text collate latin1_general_ci NOT NULL, `user` int(11) NOT NULL, `statustext` varchar(50) collate latin1_general_ci NOT NULL, `datum` datetime NOT NULL, `comment` text collate latin1_general_ci NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 COLLATE=latin1_general_ci;
I have query and result is true
$now = time(); $date = date("d-m-Y H:i:s",$now); $q = "insert into paper set title='{$_REQUEST['title']}', abstract='{$_REQUEST['abstract']}', keywords='{$_REQUEST['keywords']}', authors='{$_REQUEST['authors']}', ext='$file_ext', user='{$_SESSION['id']}', status='new', datum='$date' ";output is :
insert into paper set title='aaaaaaaa', abstract='aaaaaaaa', keywords='aaaaaaaa', authors='aaaaaaaa', ext='.doc', user='20', status='new', datum='25-12-2008 18:49:06'
But when I check my PHPmyADMIN, i cant see my datum variable, the field is 000000000 there is no time, WHY?
datum (field)
0000-00-00 00:00:00
0000-00-00 00:00:00
0000-00-00 00:00:00
0000-00-00 00:00:00
0000-00-00 00:00:00
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im going to search "ternary operation" methods now.
thank you one more time
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Thanks for everything.
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Thanks for urgent reply.
Could you explain this code word by word,
what does it stand for ( ? : )
<?php (isset($_POST['search'])) ? $_POST['search'] : $_GET['search']; ?>
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If I POST variable with this method, where like = '%%' query is not working
<?php $var = $_POST['search'];
but if I post with like that where like = '%%' query is working (somebody give me this code)
<?php $search = (isset($_POST['search'])) ? $_POST['search'] : $_GET['search']; $search = trim(mysql_real_escape_string($search)); ?>
What is the meaning of this sentence ???
<?php (isset($_POST['search'])) ? $_POST['search'] : $_GET['search']; ?>
and what is the difference between these methods?
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you are right
when i change the code but i forgot to put session
thank you one more time revraz
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if($count==1){ $row = mysql_fetch_array($result); $_SESSION['loggedIn'] = $row['type']; $_SESSION['id'] = $row['id']; header("location:{$row['type']}.php?id={$row['id']}&type={$row['type']}"); }http://aaaa.com/reviewer.php?id=9&type=reviewer
ID is true, TYPE is true
BUT why this part is working FALSE, WHY header("location:index.php"); is working ???? Please help me
<?php include('dbconfig.php'); session_start(); if ($_SESSION['loggedIn'] != 'reviewer') { //check the registered user, if not go index.php if(!$_SESSION['id']) { header("location:index.php"); die(); //echo $_SESSION['id']; //echo "<br>".$_SESSION['loggedIn']; } else //if registered with different user type turn back to your page { echo " <script language='JavaScript'>history.go(-1);</script>"; } }else{ //page starts here ?> -
there are the errors when I try to login as a reviewer with reviewer information
Notice: Undefined index: loggedIn in /home/bbp/reviewer.php on line 6
Notice: Undefined index: id in /home/bbp/reviewer.php on line 8
Notice: Undefined index: id in /home/bbp/reviewer.php on line 12
Notice: Undefined index: loggedIn in /home/bbp/reviewer.php on line 13
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if I login the system as a reviewer, login_control.php must open the reviewer.php page
id username password email type
1 p p a@a reviewer
login_control.php
<?php $sql="SELECT * FROM user WHERE username='$myusername' and password='$mypassword'"; $result=mysql_query($sql); // Mysql_num_row is counting table row $count=mysql_num_rows($result); // If result matched table row must be 1 row if($count==1){ $row = mysql_fetch_array($result); $_SESSION['loggedIn'] = $row['type']; $_SESSION['id'] = $row['id']; header("location:{$row['type']}.php?"); } ?>but problem starts here. My username and password is true, and type is reviewer.
when I try to login the system as a reviewer, header("location:index.php"); is open the index page. WHY ?
reviewer.php
<?php include('dbconfig.php'); session_start(); if ($_SESSION['loggedIn'] != 'reviewer') { //check the registered user, if not go index.php if(!$_SESSION['id']) { header("location:index.php"); die(); } else //if registered with different user type turn back to your page { echo " <script language='JavaScript'>history.go(-1);</script>"; } } else { //open the secure page } ?> -
I add javascipt 100% working now
<?php else //if registered with different user type turn back to your page { echo " <script language='JavaScript'>history.go(-1);</script>"; }?> -
I add javascipt 100% working now
<?php else //if registered with different user type turn back to your page { echo " <script language='JavaScript'>history.go(-1);</script>"; }?> -
I got these errors:S
Notice: Undefined variable: HTTP_REFERER in /bbp/reviewer.php on line 18
Notice: Undefined index: HTTP_REFERER in bbp/reviewer.php on line 19
<?php echo $HTTP_REFERER; //line 18 echo $_SERVER['HTTP_REFERER']; //line 19 ?>
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that page is coming from www.aaaa.com/user.php or www.aaaa.com/blabla.php
but it is not giving any error or there is no action
this part is not working with header()
if I put header, problem starts here
<?php else { //header("Location:".$_SERVER['HTTP_REFERER'].""); exit(); } ?>What is the problem ? Why the header() is not working or is not giving any error
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<?php if ($_SESSION['loggedIn'] != 'reviewer') { //check the registered user, if not go index.php if(!$_SESSION['id']) { header("location:index.php"); die(); } else //if registered with different user type turn back to your page { echo $HTTP_REFERER; header("Location:".$_SERVER['HTTP_REFERER'].""); } } ?>this part is not working
else
{
echo $HTTP_REFERER;
header("Location:".$_SERVER['HTTP_REFERER']."");
}
but if I write like this it is working
else
{
exit();
}
What is the problem ?
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<?php if ($_SESSION['loggedIn'] != 'reviewer') { //check the registered user, if not go index.php if(!$_SESSION['id']) { header("location:index.php"); die(); } else //if registered with different user type turn back to your page { echo $HTTP_REFERER; header("Location:".$_SERVER['HTTP_REFERER'].""); } } ?>this part is not working
else { echo $HTTP_REFERER; header("Location:".$_SERVER['HTTP_REFERER'].""); }but if I write like this it is working
else { session_destroy(); exit(); }WHY header("Location:".$_SERVER['HTTP_REFERER'].""); is not working!!!!!
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I have another question
that code gives the current page
$pageURL ="http://";
$pageURL .= $_SERVER["SERVER_NAME"].$_SERVER['REQUEST_URI'];
how to redirect to previous page?
<?php if ($_SESSION['loggedIn'] != 'admin') { //check the registered user, if not go index.php if(!$_SESSION['id']) { header("location:index.php"); die(); } else //if registered with different user type, turn back to your page {//header("Location:".$_SERVER['HTTP_REFERER'].""); $pageURL ="http://"; $pageURL .= $_SERVER["SERVER_NAME"].$_SERVER['REQUEST_URI']; //echo $pageURL = www.aaaa.com/admin.php //but it must redirect to = previous page header("Location: $pageURL "); die(); } } ?> -
I forgot to put if ($_SESSION['loggedIn'] != 'admin')
you are right!
thank you
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i login with user account
id username password email type
10 pa pa a@aa user
than im going to user.php page.
but when I write admin.php also I can see the admin part
user mustnt see the admin part. what can be the problem?
if (!$_SESSION['loggedIn'] == 'admin') { header("location:login.php"); die (); } print_r($_SESSION); echo "<br />".$_SESSION['loggedIn']; //type is user but I can see the admin page -
MySQL code
CREATE TABLE IF NOT EXISTS `user` ( `id` int(11) NOT NULL auto_increment, `username` varchar(50) collate latin1_general_ci NOT NULL, `password` varchar(50) collate latin1_general_ci NOT NULL, `email` varchar(200) collate latin1_general_ci NOT NULL, `type` varchar(20) collate latin1_general_ci NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 COLLATE=latin1_general_ci;
id username password email type
1 p p a@a admin
login_control.php
$sql="SELECT * FROM user WHERE username='$myusername' and password='$mypassword'"; $result=mysql_query($sql); // Mysql_num_row is counting table row $count=mysql_num_rows($result); // If result matched table row must be 1 row if($count==1){ $row = mysql_fetch_array($result); $_SESSION['loggedIn'] = $row['type']; $_SESSION['id'] = $row['id']; header("location:{$row['type']}.php?"); }that part is not working, how can I control the correct type user
user.php (for users) admin.php (for admins)
only admin user must see that part. But HOW ?
Can any body give me a hint?
If there are guys or girls who has done similar things, please help me
Thanks in advance
admin.php
session_start(); if (!$_SESSION['loggedIn'] == 'admin') { header("location:login.php"); die (); } //page start here
[SOLVED] MySQL Update problem ( checkbox values )
in PHP Coding Help
Posted
reviewer_research_field table
when I try to update data which is coming from form with checkbox values
<?php foreach ($_POST['state'] as $newstate) { $write = "update reviewer_research_field as r set r.id='{$newstate}' where r.user='{$_SESSION['id']}' "; mysql_query($write) or die(mysql_error()); } ?>im selecting 3 different checkbox 5-8-9
but this query is only adding one number like
user id
22 9
22 9
22 9
but it must be
user id
22 5
22 8
22 9
What is the problem? How can I solve :s
Thanks in advance