DataSpy

Hello this is the first time I've ever used a function and was wondering if someone could please help me with a parse error. [code] <?php //<!-- mysql connection function --> function &dbconnection($host, $dbuser, $dbpass, $dbname) {    if (!dbconn = @mysql_connect($host, $dbuser, $dbpass)) {    <=== line 5     return false;   }   if (!@mysql_select_db($dbname)) {     return false;   }   return $dbconn; } //<!-- mysql config --> $host    = 'localhost'; $dbuser  = 'root'; $dbpass  = ''; $dbname  = 'cms'; $dbconn = &dbconnection($host, $dbuser, $dbpass, $dbname); ?> [/code] The error says: [quote] Parse error: parse error, unexpected '=' in C:\Program Files\xampp\htdocs\www\band\config.php on line 5 [/quote] Any help would be greatly appretiated, thanx in advance!

Yep, it was in the config file! Thanx!!! :)

All I'm trying to do is include a file and it says I have a parse error, I commented line #4 it out and the error went away.  But I don't think there is an error the way I include it, but obviously there is one :( . [code] <?php session_start(); ob_start(); include "config.php";  <=== line #4 ?> Any help greatly appretiated, thanx in advance! [/code]

Hello, what I'm trying to do is check to see what time and day someone views a page and then echo a responce. I know what i want to do but I've never worked with time before and was a little confused. example: if it's between 7:00 AM and 11:59 AM and Monday $shift = $monday_morning_shift; then echo out if $shift = $monday_morning_shift echo 'something'; Any help greatly appretiated, thanx in advance!