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cybernet

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Posts posted by cybernet

    need help ? else please take a look : thank you

    in PHP Coding Help

    Posted

    1st of all i'm sorry for the ironic title

    i would've name it " i need help with this $statement ", the only problem is that i don't know the name cause i would've  :rtfm:

     

    so let's cut to the chase

     

    i have this if and else statement

     

    $status = '';
if ( !isset($_POST[ $x ]) || empty($message) || empty($email) )
	$status = $lang['error'];

  else  {
		$status = $lang['success'];
		mail($to, $subject, $body, $headers);
	}

    the i have this

    $no_p = '';
$yes_p = "<p style='color:red'>".$status."<br /></p>";
$show_status = (isset($status)) ? $no_p : $yes_p; // this is the function i don't know the name of it // this ? and : sign;

     

    what i'm trying to do is

     

    1st of all if and else statement are executed only if the html form is submitted due to a swich case function

    in the html part i have the $show_status variable which i want to show NULL if the form wasn't submitted

    and if the form was submitted i want that $show_status to show either $lang['error'] OR $lang['success']

     

    this is the only function i know to do this job, but the problem is that i got stuck :shrug:

     

    this is how i arranged the code

    switch ($pageID) 
{

    case 'submit':
foreach( array('lastname','firstname','email', 'message', 'phone') as $x )
    	{
      ${$x} = $_POST[ $x ];
    	}

if ( !isset($_POST[ $x ]) || empty($message) || empty($email) )
	$status = $lang['error'];

  else  {
		$status = $lang['success'];
		mail($to, $subject, $body, $headers);
	}
$no_p = '';
$yes_p = "<p style='color:red'>".$status."<br /></p>";
$show_status = (isset($status)) ? $no_p : $yes_p;
        break;
}

    the simplest thing in the world fails / LOL

    in PHP Coding Help

    Posted

    every site on the server has

    include /etc/nginx/fastcgi_params;

    and the file contains

    fastcgi_param	QUERY_STRING		$query_string;
fastcgi_param	REQUEST_METHOD		$request_method;
fastcgi_param	CONTENT_TYPE		$content_type;
fastcgi_param	CONTENT_LENGTH		$content_length;

fastcgi_param	SCRIPT_FILENAME		$request_filename;
fastcgi_param	SCRIPT_NAME		$fastcgi_script_name;
fastcgi_param	REQUEST_URI		$request_uri;
fastcgi_param	DOCUMENT_URI		$document_uri;
fastcgi_param	DOCUMENT_ROOT		$document_root;
fastcgi_param	SERVER_PROTOCOL		$server_protocol;

fastcgi_param	GATEWAY_INTERFACE	CGI/1.1;
fastcgi_param	SERVER_SOFTWARE		nginx/$nginx_version;

fastcgi_param	REMOTE_ADDR		$remote_addr;
fastcgi_param	REMOTE_PORT		$remote_port;
fastcgi_param	SERVER_ADDR		$server_addr;
fastcgi_param	SERVER_PORT		$server_port;
fastcgi_param	SERVER_NAME		$server_name;

fastcgi_param	HTTPS			$server_https;

# PHP only, required if PHP was built with --enable-force-cgi-redirect
fastcgi_param	REDIRECT_STATUS		200;

    the simplest thing in the world fails / LOL

    in PHP Coding Help

    Posted

    You likely have a .htaccess rewrite rule that is not passing the get parameters. What is in any .htaccess files that are present?

     

    nginx as webserver so .htaccess is useless even if it existed ( but doesn't )

     

    Ara you sure that your comp is free of malicious software?

     

     

    i use centos 6  :D

     

    Notice: Undefined index: id in /home/postlist/x/view_post.php on line 12
    :confused:

     

    line 12

    $id = intval($_GET['id']);

    the simplest thing in the world fails / LOL

    in PHP Coding Help

    Posted

    url

    /view_post.php?post_id=88

     

    full source

    <?php

// plm

// require_once (dirname(__FILE__) . "/inc/main.php");

// $lang = load_language('view_post');
echo '<pre>' . print_r($_GET,true) . '</pre>';
if(!isset($_GET["post_id"])) echo "1/id is not set\n";
$post_id = intval($_GET['post_id']);
if ( $post_id >= 1 ) {
echo "2/yo good";
}
else {
echo "$post_id\n";
die ("3/no id specified");
}
?>

     

    output

    Array

    (

    )

    1/id is not set 0 3/no id specified

    the simplest thing in the world fails / LOL

    in PHP Coding Help

    Posted

    full source

    <?php

// plm

// require_once (dirname(__FILE__) . "/inc/main.php");

// $lang = load_language('view_post');
if(!isset($_GET["post_id"])) echo "1/id is not set\n";
$post_id = intval($_GET['post_id']);
if ( $post_id >= 1 ) {
echo "2/yo good";
}
else {
echo "$post_id\n";
die ("3/no id specified");
}
?>

     

    output

    1/id is not set 0 3/no id specified

     

    error.log

    2012/01/25 17:16:16 [error] 24454#0: *11049871 FastCGI sent in stderr: "PHP Notice:  Undefined index: post_id in /home/postlist/x/view_post.php on line 9" while reading response header from upstream, client: 127.0.0.1, server: google.ro, request: "GET /view_post.php?post_id=88 HTTP/1.1", upstream: "fastcgi://unix:/var/run/php-fastcgi/php-fastcgi.socket:", host: "google.ro"

    the simplest thing in the world fails / LOL

    in PHP Coding Help

    Posted 

    <?php

// plm

require_once (dirname(__FILE__) . "/inc/main.php");

$lang = load_language('view_post');

$id = intval($_GET['id']);
if ( $id >= 1 ) {
dbconn();
// la la la
}
else {
echo "$id\n"; // for debugging
die ("no id specified");
}
?>

    when it's executed of curse i get "0 no id specified"

    1. i dont get why i get 0 as a result even if the url is /x.php?id=204

    2. in error.log i get

    PHP Notice:  Undefined index: id in x.php

     

    i intend to inform that formerly the script was running smoothly on lighttpd webserver, now i use nginx

    :wtf: ( so i wont use words )

    i know that are people with more complicated things around here ... but still i'm struggling for 1 hour with this xxx

    thanks in advance 8)

    btw : php version 5.3.x

    smarty $_POST help

    in Other Libraries

    Posted 

    $postlist = new Smarty;
...
case 'submit':
foreach(explode(":","desc:title") as $v) {

      if (!isset($_POST[$v]))

        $postlist->display('no_posted_data.tpl');

    }

     

    post.tpl

    <form action="post.php?action=submit" method="post">
<legend>..title..</legend>
  <table border="1">
    <tr>
      <td>{$post_form.title}:</td>
      <td>
        <input type="text" name="title" size="40">
      </td>
    </tr>
    <tr>
      <td valign="top">{$post_form.desc}:</td>
      <td><textarea name="desc" cols="80" rows="10"></textarea></td>
    </tr>
    <tr>
      <td colspan="2" align="center">
        <input type="submit" value="Submit">
      </td>
    </tr>
  </table>

     

    the only problem is that if i submit the form empty is still get processed

     

    any help please ? :D

     

    i have even tried in a template

    {if !isset($_POST['title']) }
   die?
{/if}

    smarty-> submit form

    in Other Libraries

    Posted

    i would like to create a posting page just like this form i'm writing now

    including return ( <br/> ) pagination, and language codes ( php mysql c++ c# ... etc  without affecting site security )

     

    are there any good tutorials i can follow or any advice ?

    i'm very new to smarty and i have only basic php knowledge

     

    to prove that i'm not lazy and i read the documentation this is what i got so far

     

    <?php


require('../dev0_inc/smarty/Smarty.class.php');
require('../dev0_inc/config/ride_mysql.php');


$smarty = new Smarty;
$smarty->error_reporting = E_ALL & ~E_NOTICE;

// $smarty->debugging = true;
$smarty->caching = false;
$smarty->cache_lifetime = 120;
// setConfig for *.conf files
$smarty->setConfigDir('../dev0_inc/config');

// $smarty->

// sqL

$result = mysql_query("SELECT * FROM posts ORDER BY `id` DESC LIMIT 0 , 50") or die(mysql_error());
// For each result that we got from the Database
while ($line = mysql_fetch_assoc($result))
{
$value[] = $line;
}

// Assign this array to smarty...
$smarty->assign('posts', $value);

$config['cyber_date'] = '%d %b %y, %T';

$smarty->assign('config', $config);


$smarty->display('index.tpl');

?>

     

    and i'm using phpmyadmin to insert data

     

    so far i read from documentation that i have to escape the assign values, but i don't know if it's secure :shy:

    using smarty 3.1.1, thanks for reading - cybernet

    array issues

    in PHP Coding Help

    Posted

    i don't think you understood me

    index.php is flawless ( i think )

    if on index.php i select Bauturi alcoolice on post page i wanna get Bauturi alcoolice

     

    this code is good

    <?php 
error_reporting(E_ALL);

$drop = $_REQUEST['bauturi']; 
echo $drop;
?>

    but as result i get bauturi_alcoolice instead of the value that is equal with it

    array issues

    in PHP Coding Help

    Posted

    i have two pages

    form and submit page

    index.php

    <?php 
error_reporting(E_ALL);
$bauturi = array('bauturi_alcoolice'=>'Bauturi alcoolice','sucuri'=>'Sucuri','bauturi_racoritoare'=>'Bauturi racoritoare'); 
echo '<form action="post.php" method="post">';

echo'<select name="bauturi">'; 

foreach($bauturi as $let=>$word){ 
    echo'<option value="'.$let.'">'.$word.'</option>'; 
} 
echo'</select>';
echo '<INPUT type="submit" value="show me money">

</form>';
?>

    post.php

    <?php 
error_reporting(E_ALL);

$drop = $_REQUEST['bauturi']; 
echo $drop;
?>

    if i select Bauturi alcoolice on post.php page i get bauturi_alcoolice

    but i want to get Bauturi alcoolice as result

     

    i tried to use foreach like this

    <?php 
error_reporting(E_ALL);

$drop = $_REQUEST['bauturi']; 
$bauturi = array('bauturi_alcoolice'=>'Bauturi alcoolice','sucuri'=>'Sucuri','bauturi_racoritoare'=>'Bauturi racoritoare'); 
foreach($bauturi as $drop=>$word){ 
echo $word;
echo "<br/>";
unset($word);
}
?>

     

    but i get all the values in the form

    i only want to show the selected value from the form in post.php page

     

    thanks in advance

    mouseover transparency

    in CSS Help

    Posted

    thanks for the reply

    this is the output of the mouseover ( without you're modification )

     

    jpu83p.jpg

     

    that background is #0e0d0b but i don't wanna change that, i just wanna make it transparent

     

    like this ( i modified the image with gimp )

    xfswzq.png

    mouseover transparency

    in CSS Help

    Posted

    i have this to files

    http://code.google.com/p/cyby/source/browse/trunk/js/cyber.js and

    http://code.google.com/p/cyby/source/browse/trunk/css/cyber.css

     

    i know this has 2 different topic for each one but together they create a usefull mouseover

     

    what i'm trying to do is to make the mouseover transparent where can i change that

     

    after a google search i know that "opacity:0.4;filter:alpha(opacity=40)" will do the trick but i have no idea where to edit

    any help will be appreciated 

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