sungpeng

$sql = mysql_query("SELECT * FROM database where id=$id") while($do=mysql_fetch_array($sql)){ There are many rows that have the same id numbers. I need all to fetch out. Mysql error. Is it possible to echo out all ?

thk

Is there a shorter line for day = 1 to 4 instead of day=1 or day=2 or day=3 or day=4 ?

$.ajax({ success:function(html){ $('#msg').html(html); } }); <p id="msg"></p> Is it possible to extract the id="msg" results and put it in php variable or html for further command ?

How to fetch the data from another php page ? <script> $( "#search" ).autocomplete({ source: availableTags }); </script> <input type="text" id="search">

No not working also. <script type='text/javascript'> $(window).load(function(){ $('input[name="searchbox"]').on('change', function() { var val = $(this).val(), var dataString='varal='+ val; alert (dataString); }); }); <input type="text" name="searchbox">

Like key wording in www.google.com, we haven't completely key in the sentence there is always a dropdown box show the results before we press the search button.

Is it possible to change it to a search box text instead of a checkbox ? It seemed not working. $(window).load(function(){ $('input[name="searchbox"]').on('change', function() { var val = $(this).val(), var dataString='var='+ val; alert ('dataString'); <input type="text" name="searchbox">

First an input box form. When key in the letter, it will search the database and fetch result in a small dialogue box beside the input box. The result fetched is not display on the page itself but a small rectangle box beside the input box form. I need the small rectangle box. Like if you key in the input box on some page, some data will appear on a small pop up box of your past data that you have key in somewhere.

Hi I need a input box, and whenever i key in a letter in it will read the database and fetch result in a small dialogue box beside the form. The dialogue box will disappear if nothing is key in. Can someone help ?

thank you

I wish to add some text after the current string data in sale. Concat not working is there any problem with this code ? $title="addtext"; $update_status=mysql_query("update product set sale=CONCAT(sale,$title) ");

Solved Thank you. One question my friend told me to use html 5 instead of ajax as html 5 all browsers can support while ajax some browsers can't. Is it true ?

If i never put in the while loop, it works fine. But once in the while loop, click on the checkbox has no reaction. while($doing=mysql_fetch_array($sqlq)){ <input type='checkbox' name='checking[]' value='<?php echo $doing["pid"]; ?>' > }

I successfully send the checkboxValue to the checking1.php page but for the isCheckboxChecked, how am i going to send it over to checking1.php as well ? If i echo the $results at checking1.php they will give me an Array wording output. var dataString='sendcheck='+ checkboxValue;

Got the alert box working already but isCheckboxChecked value can't send over to checking1.php, any problem with ajax coding ? $.ajax({ type:"post", url:"checking1.php", data:dataString, cache:false, });

i got it. Thank you.

Not working also, the alert box never pop up as well. <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.6.2/jquery.min.js"> <script type="text/javascript"> $('input[name="checking"]').on('change', function() { var checkboxValue= $(this).val(), isCheckboxChecked = $(this).is(':checked') ? 'yes' : 'no'; alert (checkboxValue); $.ajax({ type:"post", url:"checking1.php", data:dataString, }); } </script> <input type='checkbox' name='checking' value='90' />

Being trying but don't seem to work. $('input[name="checking[]"]').on('change', function() { var checkboxValue = $(this).val(), isCheckboxChecked = $(this).is(':checked') ? 'yes' : 'no'; alert (isCheckboxChecked); $.ajax({ code here }); } <input type='checkbox' id='checking[]' value='4' onchange='chk(this.value)' />

How can i pass the "checked or not checked" with the "value" to ajax together ? $(document).ready(function(){ if ($(this).is(':not(:checked)')){ var checkboxValue = $(this).val(); $.ajax({ type:"post", url:"checking1.php", }); } <input type='checkbox' id='tickcheck' value='4' onchange='chk(this.value)' />

Follow up question is if number 2 is checked and number 1 is unchecked, can i bring the variable checked and unchecked to ajax to process ?

Thank You

How to auto go back to previous page without refreshing or pressing any button in php ?

http://forums.phpfreaks.com/topic/298242-php-ajax-loop-array-send-data/ I need to send data from PHP mysql loop to ajax using "form" onchange event. Can anyone help. Please follow the link.

It always send value 1 <input type='checkbox' id='checking[]' value='1' onchange='chk()' /> I need it to send value 2 etc if i click on value 2 checkbox using php loop to define value. <input type='checkbox' id='checking[]' value='2' onchange='chk()' />