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bravo14

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Posts posted by bravo14

    javascript function and PHP

    in PHP Coding Help

    Posted

    Thanks, I've changed it to that, but now when changing the value in the select field I get the following error

    TypeError: document.getElementsByName(...).style is undefined

     

    The javascript function says

     

     

    <script>
  function test() {
    if (document.getElementsByName('points[]').value == 'F2') {
        document.getElementsByName('subpts[]').style.display = '';
    } else {
        document.getElementsByName('subpts[]').style.display = 'none';
    }
}</script>

     

    and the  php says

     

    <tr><td><img src="images/gate_<?php echo $rider_row['colour'];?>.png"/>
  <input name="id[]" type="hidden" value="<?php echo $rider_row['id'];?>"/></td><td><input readonly="readonly" name="rider[]" value="<?php echo $rider_row['rider_name'];?>" class="txtfield"/><br />
  <select name="substitute[]" class="txtfield" style="display:none">
  <option value="">-----------------</option>
<?php
foreach($reserves as $key=> $value):
echo '<option value="'.$value.'">'.$value.'</option>'; //close your tags!!
endforeach;
?>
  </select></td><td><select name="points[]" class="txtfield" onchange="test();">
  <option value="">-----------------</option>
<?php
foreach($scoring as $key=> $value):
echo '<option value="'.$key.'">'.$value.'</option>'; //close your tags!!
endforeach;
?>
  </select><br/>
  <select name="subpts[]" class="txtfield" style="display:none">
  <option value="">-----------------</option>
<?php
foreach($scoring as $key=> $value):
echo '<option value="'.$key.'">'.$value.'</option>'; //close your tags!!
endforeach;
?>
  </select>
  </td></tr>

     

    the style is set in the php as display:none

    javascript function and PHP

    in PHP Coding Help

    Posted

    Hi

     

    I am using the following PHP code to create a table for a form

     

     

     
<tr><td><img src="images/gate_<?php echo $rider_row['colour'];?>.png"/>
  <input name="id[]" type="hidden" value="<?php echo $rider_row['id'];?>"/></td><td><input readonly="readonly" name="rider[]" value="<?php echo $rider_row['rider_name'];?>" class="txtfield"/><br />
  <select name="substitute[]" class="txtfield" style="display:none">
  <option value="">-----------------</option>
<?php
foreach($reserves as $key=> $value):
echo '<option value="'.$value.'">'.$value.'</option>'; //close your tags!!
endforeach;
?>
  </select></td><td><select name="points[]" class="txtfield" onchange="test();">
  <option value="">-----------------</option>
<?php
foreach($scoring as $key=> $value):
echo '<option value="'.$key.'">'.$value.'</option>'; //close your tags!!
endforeach;
?>
  </select><br/>
  <select name="subpts[]" class="txtfield" style="display:none">
  <option value="">-----------------</option>
<?php
foreach($scoring as $key=> $value):
echo '<option value="'.$key.'">'.$value.'</option>'; //close your tags!!
endforeach;
?>
  </select>
  </td></tr>

     

    On changing the value in the field called points[], if certain values are selected then two other fields are to be displayed, I am using the following function

     

     

     
<script>
  function test() {
    if (document.getElementByName('points[]').value == 'F2 || E || N') {
        document.getElementByName('substitute[]').style.display = '';
document.getElementByName('subpts[]').style.display = '';
    } else {
        document.getElementByName('substitute[]').style.display = 'none';
document.getElementByName('subpts[]').style.display = 'none';
    }
}</script>
 
I am getting an error saying getElementByName is not a function, I know I can do this by getElementById, but the fields do not have ID and not sure how I can give them a unique ID when echoing them from the database.
 
If someone could just give me some pointers I would be very grateful

    is_numeric()

    in PHP Coding Help

    Posted

    I have changed the submit code to 

     

     

     
<?php
if(isset($_POST['submit-scores'])){
$heat=$_POST['heat'];
$next_heat=$_POST['nextheat'];
$card=$_POST['card'];
 for($i=0;$i<4;$i++){
 //set rider variables
 $id=$_POST['id'];
 $points=$_POST['points'];
 echo $points;
 if($points=='3'){
 $pts = 3;
 $DNF = NULL;
 }
 elseif($points=='2'){
 $pts = 2;
 $DNF = NULL;
 }
 elseif($points == '1'){
 $pts = 1;
 $DNF = NULL;
 }
 elseif($points == '0'){
 $pts = 0;
 $DNF = NULL;
 }
 else{
 $pts = 0;
 $DNF = $points;
 }
 
 $rider=$_POST['rider'];
 if(isset($_POST['substitute'])){
 $sub=$_POST['sub'];
 $subpts=$_POST['subpts'];
 }
 else{
  $sub=NULL;
 $subpts=NULL;
 }
 //update database
 $sql1="UPDATE tbl_heat SET rider_name='$rider[$i]', points='$pts[$i]', DNF= '$DNF[$i]', substitute='$sub[$i]', sub_points='$subpts[$i]' WHERE id='$id[$i]'";
 echo $sql1.'<br/>';
 //$result1=mysql_query($sql1)or die(mysql_error());
 }
 //update card info
 $sql="Update tbl_card SET next_heat = $next_heat where `card_id` = $card";
 //$result=mysql_query($sql)or die(mysql_error());
 //header ('Location: score-card.php?card='.$card.'#'.$nextheat);
 }
?>

     

    but I am now getting

     

    ArrayUPDATE tbl_heat SET rider_name='Chris Harris', points='', DNF= '3', substitute='', sub_points='' WHERE id='853'
    ArrayUPDATE tbl_heat SET rider_name='Kenneth Bjerre', points='', DNF= '2', substitute='', sub_points='' WHERE id='854'
    ArrayUPDATE tbl_heat SET rider_name='Martin Smolinski', points='', DNF= '1', substitute='', sub_points='' WHERE id='855'
    ArrayUPDATE tbl_heat SET rider_name='Chris Holder', points='', DNF= 'F', substitute='', sub_points='' WHERE id='856'

     

    I still cant get it to update the points with a value

    is_numeric()

    in PHP Coding Help

    Posted

    I have corrected that, however the problem is occurring before the query line, because if the value is numeric then the posted value should be the value of the $pts variable and not the $DNF variable

    is_numeric()

    in PHP Coding Help

    Posted

    Hi

     

    Using the array below I am populating a select field

     

     

     
$scoring=array(
'3' =>  'First',
'2' =>  'Second',
'1' =>  'Third',
'0' =>  'Fourth',
'R' =>  'Retired or mechanical failure',
'F' => 'Fell',
'FN'=> 'Fell and non-starter in re-run of race',
'N2'=> 'Exclusion for exceeding two minute time allowance',
'E' => 'Exclusion for starting infringement',
'FX'=> 'Fell and excluded from re-run of race',
'X' =>  'Other exclusion',
'N' => 'Replaced by a reserve, or non-starter',
'-'=> 'No ride');

     

     

     
<select name="points[]" class="txtfield">
  <option value="">-----------------</option>
<?php
foreach($scoring as $key=> $value):
echo '<option value="'.$key.'">'.$value.'</option>'; //close your tags!!
endforeach;
?>
  </select>

     

    on submit I then use the following code, checking if the value of `points` is numeric, and if not set pts to be 0 and add the posted value to a different field.

     

     

     
<?php
if(isset($_POST['submit-scores'])){
$heat=$_POST['heat'];
$next_heat=$_POST['nextheat'];
$card=$_POST['card'];
 for($i=0;$i<4;$i++){
 //set rider variables
 $id=$_POST['id'];
 $points=$_POST['points'];
 if(is_numeric($points)){
 $DNF = NULL;
 $pts=$points;}
 else{
 $pts=0;
 $DNF = $points;
 }
 $rider=$_POST['rider'];
 if(isset($_POST['substitute'])){
 $sub=$_POST['sub'];
 $subpts=$_POST['subpts'];
 }
 else{
  $sub=NULL;
 $subpts=NULL;
 }
 //update database
 $sql1="UPDATE tbl_heat SET rider_name='$rider[$i]', points='$pts[$i]', DNF= '$DNF[$i] ', substitute='$sub[$i]', sub_points='$subpts[$i]' WHERE id='$id[$i]'";
 echo $sql1.'<br/>';
 //$result1=mysql_query($sql1)or die(mysql_error());
 }
 //update card info
 $sql="Update tbl_card SET next_heat = $next_heat where `card_id` = $card";
 //$result=mysql_query($sql)or die(mysql_error());
 //header ('Location: score-card.php?card='.$card.'#'.$nextheat);
 }
?>

     

    when I echo the query I get the following result

     

    UPDATE tbl_heat SET rider_name='Chris Harris', points='', DNF= '3 ', substitute='', sub_points='' WHERE id='853'
    UPDATE tbl_heat SET rider_name='Kenneth Bjerre', points='', DNF= '2 ', substitute='', sub_points='' WHERE id='854'
    UPDATE tbl_heat SET rider_name='Martin Smolinski', points='', DNF= '1 ', substitute='', sub_points='' WHERE id='855'
    UPDATE tbl_heat SET rider_name='Chris Holder', points='', DNF= 'F ', substitute='', sub_points='' WHERE id='856'

     

    it appears to be adding a space to the end of each of the array keys, therefore saying that 3 is not numeric etc, so a cople of things, why is the space being added, secondly is this the best way to achieve the result?

    array problem

    in PHP Coding Help

    Posted

    Hi

     

    I am using the code below to generate an array

     

     
$sql="SELECT * 
FROM `tbl_heat` 
WHERE `heat` =21 AND `points` >= 2 
OR `heat` = 22 AND `points` >=2 
AND `card_id` = 2";
 
//echo $sql;
 
$result=mysql_query($sql) or die(mysql_error());
while($row=mysql_fetch_assoc($result)){
$riders[] = $row['rider_name'];
print_r ($riders);

     

    However the array comes out like this when printed

     

    Array ( [0] => Chris Harris ) Array ( [0] => Chris Harris [1] => Kenneth Bjerre ) Array ( [0] => Chris Harris [1] => Kenneth Bjerre [2] => Martin Smolinski ) Array ( [0] => Chris Harris [1] => Kenneth Bjerre [2] => Martin Smolinski [3] => Chris Holder )

     

    I want it to come out like this 

     

    Array ( [0] => Chris Harris [1] => Kenneth Bjerre [2] => Martin Smolinski [3] => Chris Holder )

     

    What am I doing wrong?

    FUNCTION COUNT does not exist.

    in MySQL Help

    Posted

    Hi

     

    I am trying to a query that has countif in  the query is to find the top 8 riders based on ponts scored then number of wins (where points = 3), number of 2nd places (points = 2 etc)

     

     

     
 
SELECT  COUNT( `points` ) AS `rides`, SUM( `points` ) AS `pts`, COUNT (IF(`points`=3,1,0)) AS `wins`, COUNT (IF(`points`=2,1,0)) AS `2`, COUNT (IF(`points`=1,1,0)) AS `1`, COUNT (IF(`points`=0,1,0)) AS `0`,  rider_name
FROM tbl_heat
WHERE card_id = $card
GROUP BY `rider_name` 
ORDER BY pts DESC
LIMIT 8
 

    Elrte not converting special characters

    in Javascript Help

    Posted

    Hi

     

    I am using the HTML editor elrte from elrte.org, it is simple in its setup and use, the only issue I have is at any special characters like £ are not being converted to the HTML so when I echo them from the database, the characters are shown as squares with question marks in. Is there a way I can do this with PHP. I have tried using htmlentities() and htmlspecialchars() but they convert every item including the <> around the tags

    Array Warning: addslashes() expects parameter 1 to be string, array given

    in PHP Coding Help

    Posted

    Hi Guys

     

    I have a script that I have used before without any issues based on a tutorial.  However when I do Update Cart get the following error

     

    Array Warning: addslashes() expects parameter 1 to be string, array given in /home/sites/starkeracing.co.uk/public_html/library/config.php on line 5

     

    The form is made up of the following code

    <form action="/cart.php?action=update" method="post" name="frmCart" id="frmCart">

 <table width="780" border="0" align="center" cellpadding="5" cellspacing="1" class="entryTable">

  <tr class="entryTableHeader">

   <td colspan="2" align="center">Item</td>

   <td align="center">Unit Price</td>

   <td width="75" align="center">Quantity</td>

   <td align="center">Total</td>

  <td width="75" align="center"> </td>

 </tr>

  <tr class="content">

  <td width="80" align="center"><a href="main.php?c=2&p=1"><img src="img/product/f9bf45f907835051aa131dde0ec00ef8.jpg" border="0"></a></td>

  <td><a href="main.php?c=2&p=1">Soft Shell Jacket</a></td>

   <td align="right">£40.00</td>

  <td width="75"><input name="txtQty[]" type="text" id="txtQty[]" size="5" value="1" class="box" onKeyUp="checkNumber(this);">

  <input name="hidCartId[]" type="hidden" value="15">

  <input name="hidProductId[]" type="hidden" value="1">

  </td>

  <td align="right">£40.00</td>

  <td width="75" align="center"> <input name="btnDelete" type="button" id="btnDelete" value="Delete" onClick="window.location.href='/cart.php?action=delete&cid=15';" class="box">

  </td>

 </tr>

  <tr class="content">

  <td colspan="4" align="right">Sub-total</td>

  <td align="right">£40.00</td>

  <td width="75" align="center"> </td>

 </tr>

<tr class="content">

   <td colspan="4" align="right">Shipping </td>

  <td align="right">£5.00</td>

  <td width="75" align="center"> </td>

 </tr>

<tr class="content">

   <td colspan="4" align="right">Total </td>

     <td align="right">£45.00</td>

  <td width="75" align="center"> </td>

 </tr>  

 <tr class="content">

  <td colspan="5" align="right"> </td>

  <td width="75" align="center">

<input name="btnUpdate" type="submit" id="btnUpdate" value="Update Cart" class="box"></td>

 </tr>

</table>

</form>

    The following function is called

    if (!get_magic_quotes_gpc()) {

    if (isset($_POST)) {

        foreach ($_POST as $key => $value) {

        echo $value;

            $_POST[$key] =  trim(addslashes($value));

        }

    }

    

    if (isset($_GET)) {

        foreach ($_GET as $key => $value) {

            $_GET[$key] = trim(addslashes($value));

        }

    }    

}

    It appears as I have echoed the $value from the get_magic_quotes function that no values are being posted.

     

    The following notice is also displayed

    1 Notice: Uninitialized string offset: 0 in /home/sites/starkeracing.co.uk/public_html/library/cart-functions.php on line 133 Notice: Uninitialized string offset: 0 in /home/sites/starkeracing.co.uk/public_html/library/cart-functions.php on line 136

    Below is the updateCart function that is generating the error above.

    function updateCart()

{

    $cartId     = $_POST['hidCartId'];

    $productId  = $_POST['hidProductId'];

    $itemQty    = $_POST['txtQty'];

    $numItem    = count($itemQty);

    $numDeleted = 0;

    $notice     = '';

    

    for ($i = 0; $i < $numItem; $i++) {

        $newQty = (int)$itemQty[$i];

        if ($newQty < 1) {

            // remove this item from shopping cart

            deleteFromCart($cartId[$i]);    

            $numDeleted += 1;

        } else {

            // check current stock

            $sql = "SELECT pd_name, pd_qty

                    FROM tbl_product

                    WHERE pd_id = {$productId[$i]}";

            $result = dbQuery($sql);

            $row    = dbFetchAssoc($result);

            

            if ($newQty > $row['pd_qty']) {

                // we only have this much in stock

                $newQty = $row['pd_qty'];



                // if the customer put more than

                // we have in stock, give a notice

                if ($row['pd_qty'] > 0) {

                    setError('The quantity you have requested is more than we currently have in stock. The number available is indicated in the "Quantity" box. ');

                } else {

                    // the product is no longer in stock

                    setError('Sorry, but the product you want (' . $row['pd_name'] . ') is no longer in stock');



                    // remove this item from shopping cart

                    deleteFromCart($cartId[$i]);    

                    $numDeleted += 1;                    

                }

            }

                            

            // update product quantity

            $sql = "UPDATE tbl_cart

                    SET ct_qty = $newQty

                    WHERE ct_id = {$cartId[$i]}";

                

            dbQuery($sql);

        }

    }

    

    if ($numDeleted == $numItem) {

        // if all item deleted return to the last page that

        // the customer visited before going to shopping cart

        header("Location: $returnUrl" . $_SESSION['shop_return_url']);

    } else {

        header('Location: cart.php');    

    }

    

    exit;

}

    jQuery ui Tabs Vertical but with text rotation

    in Javascript Help

    Posted

    Hi

     

    I am using the jquery ui tabs, but with the tabs down the right and the text rotated 270 degrees.  The problem I then have is the tabs all sit on top of one another but I can't figure out which css property to amend.

     

    Below is the initialisation of the tabs and the vertical tabs css

     

     

    <script>
$(function() {
$( "#tabs" ).tabs().addClass( "ui-tabs-vertical ui-helper-clearfix" );
$( "#tabs li" ).removeClass( "ui-corner-top" ).addClass( "ui-corner-right" );
});
</script>
 <style>
.ui-tabs-vertical { width: auto; }
.ui-tabs-vertical .ui-tabs-nav { padding: .2em .1em .2em .2em; float: right; width: 12em; }
.ui-tabs-vertical .ui-tabs-nav li { clear: right; width: auto; border-bottom-width: 1px !important; border-right-width: 0 !important; margin: 0 -1px .2em 0; /* Safari */
-webkit-transform: rotate(-90deg);

/* Firefox */
-moz-transform: rotate(-90deg);

/* IE */
-ms-transform: rotate(-90deg);

/* Opera */
-o-transform: rotate(-90deg);

/* Internet Explorer */
filter: progid:DXImageTransform.Microsoft.BasicImage(rotation=3);  }
.ui-tabs-vertical .ui-tabs-nav li a { display:block; }
.ui-tabs-vertical .ui-tabs-nav li.ui-tabs-active { padding-bottom: 0; padding-right: .1em; border-right-width: 1px; border-right-width: 1px; }
.ui-tabs-vertical .ui-tabs-panel { padding: 1em; float: left; width: 40em;}
</style>

     

    The URL it is on is http://79.170.44.132/emmagrayphotography.co.uk/wedding.html

     

    Any help would be fantastic.

    .htaccess prevent image download

    in Apache HTTP Server

    Posted

    Hi Guys

     

    I am in the world of trying to prevent copyrighted images being downloaded and have entered the following line into my .htaccess file

     

    RewriteRule \.(gif|jpg|js|txt|png)$ /messageforcurious [L]

     

    It works in the fact that I cannot enter the image name into the address bar, but it also prevents pages from downloading the images, is it possible to prevent the user downloading the images using .htaccess?

    Query not working in PHP but does in Workbench

    in PHP Coding Help

    Posted · Edited by bravo14

    The query now works, althoughn not displaying the results I was expecting, results below.  I wanted the photo number to to display the incrementing number 1-20 as I am limiting it to 20, is there anyway I can have the photo_number generated after the sort?

     

    photo_number photo_filename   124 124.jpg 46 46.jpg 55 55.jpg 87 87.jpg 6 6.jpg 21 21.jpg 42 42.jpg 112 112.jpg 18 18.jpg 86 86.jpg 69 69.jpg 108 108.jpg 4 4.jpg 107 107.jpg 93 93.jpg 41 41.jpg 65 65.jpg 11 11.jpg 13 13.jpg 24 24.jpg

    Query not working in PHP but does in Workbench

    in PHP Coding Help

    Posted

    Hi Guys

     

    I am using the following query

     

     

     
SET @serial=0;
 
SELECT 
   @serial := @serial+1 AS `photo_number`, 
   `photo_filename`
FROM 
   `gallery_photos`
ORDER BY RAND()
LIMIT 20

     

    When I run the query in MySQL Workbench, I have a set of results, when I run it on a PHP page the query does not run I get the following error displayed

     

    You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'SELECT @serial := @serial+1 AS `photo_number`, `photo_filename` FROM ' at line 3

     

    Any ideas why this would happen?

    Javascript not working

    in Javascript Help

    Posted

    I have a couple of functions as shown below

     

     
function displayTrackingNumber()
{
if (document.getElementById('cboOrderStatus').value == 'Shipped') {
        document.getElementById('txtTrackingNumber').style.display = '';
document.getElementById('txtTrackingNumber').focus();
    } else {
        document.getElementById('txtTrackingNumber').style.display = 'none';
    }
}
 
function blankTrackingNumber()
{
if(this.value =='Tracking Number') {
this.value ='';
}
}
function checkTrackingNumber()
{
if(this.value =='Tracking Number') {
alert("Please enter a Tracking Number!");
}
if(this.value =='') {
alert("Please enter a Tracking Number!");
}
}

     

    They are implemented on the page as shown here

     

    <input name="txtTrackingNumber" id="txtTrackingNumber" value="Tracking Number" style="display:none" onkeydown='blankTrackingNumber()' onblur='checkTrackingNumber()' />

     

    But when I leave the field nothing is happening and there is nothing appearing in the console and when I press a key on the keyboard the value 'Tracking Number is staying in the field.  

    font download not working in Firefox

    in CSS Help

    Posted

    Hi 

     

    I have a font that I need to download via CSS it works fine in Safari, but in the Console in Firefox I get the following error

     

    downloadable font: download failed (font-family: "Dancing" style:normal weight:normal stretch:normal src index:0): bad URI or cross-site access not allowed source: http://www.remyweavesandbraids.com/files/fonts/DancingScript-Regular.ttf

     

    The css used is as follows

     

     
@font-face {
 font-family: Dancing;
 src: url(../files/fonts/DancingScript-Regular.eot); /* EOT file for IE */
}
@font-face {
 font-family: Dancing;
 src: url(../files/fonts/DancingScript-Regular.ttf); /* TTF file for CSS3 browsers */
 }

     

    What do I need to do in order for Firefox to display it properly

    Functioned undefined

    in Javascript Help

    Posted

    I have a .js file that is referenced in the page, but when I try and run the functions from it the debugger says that the function is undefined.

     

    the HTML to load the js file is

     

    <script language="JavaScript" type="text/javascript" src="http://www.starkeracing.co.uk/fullthrottle/library/club.js"></script>

     

     

    the call to the function in the HTML

     

    <a href="javascript:modifyClub(5);">Modify</a>

    and the JavaScript file is

     

    function modifyClub(clubId)
{
function code here
}

     

    I don't understand why it is saying the function is undefined.

    zero updating as NULL

    in PHP Coding Help

    Posted

    I have trued to use NULLIF() in the following way.

     

    $points=NULLIF($_POST['points'], '');

    I get the following error

     

    Fatal error: Call to undefined function NULLIF() in /home/sites/starkeracing.co.uk/public_html/admin/edit-fixture.php on line 19

     

    Any ideas?

     

    zero updating as NULL

    in PHP Coding Help

    Posted

    I have a site that records a riders score, and occasionally I will need to record 0.  If I update with 0, the database shows NULL instead.

     

    The snippets of code below show the declaration of the variable and then the adding to an array for an update query

     

     

    if(empty($_POST['points'])){$points=NULL;} else {$points=$_POST['points'];}

     

     

    $columns[] = "points = " . ($points === null ? "NULL" : "'$points'");

     

    My question is how do I update 0 and not NULL

    Background to fill 100% of screen

    in CSS Help

    Posted

    I am working on a site that has a background that changes, on top of that I have put a background image that has a means I can still see the background images but can also see the text on top.  The problem I have is that the black background image doesn't fill the entire screen.

     

    The URL of the site is http://http://217.199.187.69/starkeracing.co.uk/

     

    The CSS file in use is attached

     

    I can't see why the image bg_black.png isn't filling the entire screen.

     

     

    paulstarke.css

    Create flickr url from simplexml

    in PHP Coding Help

    Posted

    I am trying to create a flickr url using the XML file from the site

     

    the code I am using is as follows

     

     
<?php
$file="http://api.flickr.com/services/rest/?method=flickr.photosets.getList&api_key=7952c4f1e6dfd2ae1420aec860616f6e&user_id=93306691%40N08&format=rest&auth_token=72157636755071086-2072507680111a83&api_sig=8032afd164bff4d17c4574ae246ce92b";
$sets=simplexml_load_file($file);
 
foreach($sets->xpath('//photoset') as $set){
echo '<a><li><img src="http://farm'.$set{farm-id}.'.staticflickr.com/'.$set{server-id}.'/'.$set{id}.'_'.$set{secret}.'.jpg"/><h3>'.$set->title.'</h3></li></a>';
}
//print_r($sets);
?>

     

    The XML is laid out as below

     

    <photosets cancreate="1" page="1" pages="1" perpage="13" total="13">
    <photoset id="72157634817057978" primary="9378217918" secret="66a440b8e3" server="3753" farm="4" photos="28" videos="0" needs_interstitial="0" visibility_can_see_set="1" count_views="34" count_comments="0" can_comment="1" date_create="1374935118" date_update="1374954932">
        <title>Coventry v Birmingham - 26-07-13</title>
        <description>Photos of the occasion when the Birmingham Brummies ascended to the top of the Elite League table.</description>
    </photoset>
</photosets>

     

    But I am getting the following error displayed

     

    • Notice: Use of undefined constant farm - assumed 'farm' in /home/sites/birminghambrummies.co/public_html/library/flickr_sets.php on line 6 Notice: Use of undefined constant id - assumed 'id' in /home/sites/birminghambrummies.co/public_html/library/flickr_sets.php on line 6 Notice: Use of undefined constant server - assumed 'server' in /home/sites/birminghambrummies.co/public_html/library/flickr_sets.php on line 6 Notice: Use of undefined constant id - assumed 'id' in /home/sites/birminghambrummies.co/public_html/library/flickr_sets.php on line 6 Notice: Use of undefined constant id - assumed 'id' in /home/sites/birminghambrummies.co/public_html/library/flickr_sets.php on line 6 Notice: Use of undefined constant secret - assumed 'secret' in /home/sites/birminghambrummies.co/public_html/library/flickr_sets.php on line 6

    The parameters I need are within the photoset tag and not tags on their own.

     

    Any help would be great

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