Jump to content

PHP Nubsauce

Members
  • Posts

    42
  • Joined

  • Last visited

    Never

Everything posted by PHP Nubsauce

  1. date1 and date store the date. I'm not trying to be a smart guy here but..doesen't the data convert I posted twice now tell you this? Honestly, I'm not sure. I did not write this code.
  2. Okay, what exactly do you need from me to help me? :-\
  3. I don't understand how I am doing things poorly, everything works mint. I see how your query would work, but whats the problem with mine.. ??? Anyways, here is my whole query <?php $links2 = @mysql_query("SELECT * FROM ".$mysql_pretext."_calendar "); if (!$links2) { echo("Error retrieving calendar from the database!<br>Error: " . mysql_error()); exit(); } while ($link = mysql_fetch_array($links2)) { $id = $link["ID"]; $title1 = $link["title"]; $date1 = $link["date"]; $date = dateconvert($date1, 2); $dateday = date('d', strtotime($date1)); $description = $link["description"]; $shortdescription = $link["short_description"]; once again, here is my data input for Date } function dateconvert($date,$func) { if ($func == 1){ //insert conversion list($day, $month, $year) = split('[/.-]', $date); $date = "$year-$month-$day"; return $date; } if ($func == 2){ //output conversion list($year, $month, $day) = split('[-.]', $date); $date = "$month/$day/$year"; return $date; } } Month, Day, and Year are all inserted originally as raw numbers, 1 2 3 4 and so on. ??? My only issue is it pulls up all scheduled events on the calandar, rather then just the month i want to display.
  4. Hey Guys, What I'm trying to do is only select scheduled events from the calandar for a certain month. <?php $links2 = @mysql_query("SELECT * FROM ".$mysql_pretext."_calendar "); How can I select only June? This is the data convert I use at the top of the page. } function dateconvert($date,$func) { if ($func == 1){ //insert conversion list($day, $month, $year) = split('[/.-]', $date); $date = "$year-$month-$day"; return $date; } if ($func == 2){ //output conversion list($year, $month, $day) = split('[-.]', $date); $date = "$month/$day/$year"; return $date; } } any help would be much appriciated nubsauce
  5. Thank you for the help, both of you. Both ways worked. Ray you're the man bro.
  6. If I close my if statement at the end, it displays all my info but with a new table for each one. If I close it like shown, it only displays one object from the database. I need all my info to be displayed in one table box. Can anybody help me please? $links = @mysql_query("SELECT * FROM ".$mysql_pretext."_documents WHERE document_type_id = '2'"); if (!$links) { echo("Error retrieving student life documents from the database!<br>Error: " . mysql_error()); exit(); } $number = 0; while ($link = mysql_fetch_array($links)) { $ids1 = $link["ID"]; $titles1 = $link["title"]; $type = $link["type"]; $date = $link["date"]; $filename = $link["name"]; $addedby = $link["added_by"]; $number++; } ?> <td height="30" colspan="2" bgcolor="#A0C4EC" class="search"><span class="style1">Student Life Library</span></td> </tr> <tr> <td width="6%" height="30" valign="middle"><img src="images/pdf_icon.png" width="20" height="20" /></td> <td width="94%" height="30" valign="middle" class="text"><a href="getdocument.php?id=<?php echo($ids1); ?>"><?php echo($filename); ?></a> - <?php echo($titles1); ?></td> </tr> <tr>
  7. i figured that lemmin, as ray was posting, i was doing what u told me to do on the one of them to all of them
  8. No this did not work, but thanks for trying ! php nubsauce
  9. Can anybody tell me why my slideshowid isent pushing through right? It's sitting in the actual URL just fine. $query = "INSERT INTO slideshow_images (max_image_name, max_image_size, max_image_type, max_image_content, request_id, side_caption, photo_caption, for_sale, approved, slideshow_id) ". "VALUES ('$thumbfileName', '$thumbfileSize', '$thumbfileType', '$thumbcontent', '$_POST[requestid]', '$_POST[sidecaption]', '$_POST[photocaption]', '$_POST[forsale]', 'no', '$_GET[slideshowid]')"; Any help would make me jump with joy. Thanks, Nubsauce.
  10. My problem is that everything works just fine, but if a referrer has no payment, he doesent show up on the referrers list. Referrers that do have payments, show up just fine. I need a referrer to show up even if they do not have a payment.. Any help would be awesome! I'm pretty sure its me closing with } at the wrong times. But if I mess with the close brackets, things get REALLY REALLY wacked out. If theres no payment, is there a way to put "None", making the referrer still show up? Thanks, Nubsauce. <span class="textDkGrayBold"><strong> <a href="add.php">Add a Referrer</a></strong></span> <br> <br> <table width="68%" border="0" cellspacing="0" cellpadding="3"> <tr> <td width="17%" bgcolor="#66CCCC" class="bold"><strong>Name</strong></td> <td width="17%" bgcolor="#66CCCC" class="bold"><strong>Amount Due </strong></td> <td width="17%" bgcolor="#66CCCC" class="bold"><strong>Last Payment Date</strong></td> <td width="18%" bgcolor="#66CCCC" class="bold"><strong>Last Payment Amount</strong></td> <td width="18%" bgcolor="#66CCCC" class="bold"><strong>Phone</strong></td> <td width="18%" bgcolor="#66CCCC"> </td> </tr> <?php $links = @mysql_query("SELECT * FROM ".$mysql_pretext."_referrers ORDER BY company ASC"); if (!$links) { echo("Error retrieving referrers from the database!<br>Error: " . mysql_error()); exit(); } while ($link = mysql_fetch_array($links)) { $id = $link["ID"]; $firstname = $link["first_name"]; $lastname = $link["last_name"]; $email = $link["email"]; $homephone = $link["home_phone"]; $cellphone = $link["cell_phone"]; $workphone = $link["work_phone"]; ?> <?php $expectedtotal = 0; $realtotal = 0; $links34 = @mysql_query("SELECT * FROM ".$mysql_pretext."_customers WHERE referrer_id = '$id'"); if (!$links34) { echo("Error retrieving projects from the database!<br>Error: " . mysql_error()); exit(); } while ($link = mysql_fetch_array($links34)) { $customerid = $link["ID"]; $clientcompany = $link["company"]; ?> <?php $links33 = @mysql_query("SELECT * FROM ".$mysql_pretext."_customer_payments WHERE customer_id = '$customerid' ORDER BY date DESC"); if (!$links33) { echo("Error retrieving customer payments from the database!<br>Error: " . mysql_error()); exit(); } ?> <?php while ($link = mysql_fetch_array($links33)) { $customerpaymentid = $link["ID"]; $customerid = $link["customer_id"]; $amountreceived = $link["amount_received"]; $paymentdate1 = $link["date"]; $paymentdate = dateconvert($paymentdate1, 2); $realtotal = $realtotal + $amountreceived; $commissions = $amountreceived * 0.1; } ?> <?php $links47 = @mysql_query("SELECT * FROM ".$mysql_pretext."_referrer_payments WHERE referrer_id = '$id' ORDER BY date DESC LIMIT 1"); if (!$links47) { echo("Error retrieving referrer payments from the database!<br>Error: " . mysql_error()); exit(); } while ($link = mysql_fetch_array($links47)) { $paymentid = $link["ID"]; $amountpaid = $link["amount_paid"]; $paymentdate1 = $link["date"]; $paymentdate = dateconvert($paymentdate1, 2); ?> <?php $totalcommissionpaid = 0; $links11 = @mysql_query("SELECT * FROM ".$mysql_pretext."_referrer_payments WHERE referrer_id = '$id' ORDER BY date DESC"); if (!$links11) { echo("Error retrieving referrer payments from the database!<br>Error: " . mysql_error()); exit(); } while ($link = mysql_fetch_array($links11)) { $paymentid2 = $link["ID"]; $amountpaid2 = $link["amount_paid"]; $realrealtotal = $realtotal * 0.1; $realexpectedtotal = $expectedtotal * 0.1; $totalcommissionpaid = $totalcommissionpaid + $amountpaid2; $totalcommissiondue = $realrealtotal - $totalcommissionpaid; } ?> <tr> <td class="text" valign="top"><a href="referrer.php?id=<?php echo($id); ?>"><?php echo($firstname); ?> <?php echo($lastname); ?></a></td> <td class="text" valign="top">$<?php echo(number_format($totalcommissiondue,2)); ?></a></td> <td class="text" valign="top"><font color="#000000" nowrap class="text"> <?php if($paymentdate1 != '0000-00-00'){ echo($paymentdate); } else { echo('None'); } ?> </font></td> <td class="text" valign="top">$<?php echo(number_format($amountpaid, 2)); ?></td> <td class="text" valign="top"> <?php if($homephone != ''){ ?> h: <?php echo($homephone); ?><br> <?php } ?> <?php if($cellphone != ''){ ?> c: <?php echo($cellphone); ?><br> <?php } ?> <?php if($workphone != ''){ ?> w: <?php echo($workphone); ?> </td> <td valign="top" class="text"><div align="center"> <a href="addreferrerpayment.php?id=<?php echo($id); ?>">Record a Payment<br> <br> </a><a href="edit.php?id=<?php echo($id); ?>">edit</a> - <a href="<?php echo($PHP_SELF); ?>?delete=<?php echo($id); ?>" onClick="return confirm('Are you sure you want to delete this referrer?');">delete</a></p> </div></td><?php } } } } ?> </tr>
  11. This is what I have - if (mysql_query($sql)) { } else { ?> <p class="text">Error: <?php echo(mysql_error()); ?></p> <?php } } else { ?> <p class="text">Error: You have not selected a document to upload.</p> <?php } } ?> this is what I get, even though the items are uploading correctly - Error: You have not selected a document to upload. Can anybody help? I'm new to this =p Thanks, Nubsauce.
  12. Ok, I was at work, forgive me, I could not copy and paste my code. $username = $_SESSION['loggedin']; $firstname = $t['first_name']; $lastname = $t['last_name']; $addedby = $firstname. " " .$lastname; This all works fine. All I'd like to do is replace "addedby" with "username" if both firstname and lastname are blank. Thanks for your patience.
  13. i have $username = user_name $firstname = first_name $lastname = last_name addedby = $firstname' . '$lastname Yeah, sorry i was unclear, If firstname and lastname are both blank, I'd like addedby to be username. Thanks.
  14. Hi, I have $username = user_name $firstname = first_name $lastname = last_name addedby = $firstname' . '$lastname How can I make it so if firstname and lastname are blank, it uses username instead? Any help would be appriciated! Thanks, Nubsauce.
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.