-
Posts
242 -
Joined
-
Last visited
Posts posted by ankur0101
-
-
I have re-written the whole code
index.php - The page where student will search for his result by entering roll number in text box
<?php // Connection to database //require_once ("includes/settings.php") $hostname = "localhost"; $database = "phpresult"; $username = "root"; $password = "demojoomla"; $conn = mysql_connect($hostname, $username, $password); mysql_select_db($database,$conn); if(isset($_POST['submit'])) { $roll_number = $_POST['roll_no_textbox']; $sql1 = mysql_query("SELECT roll_no FROM result-table WHERE roll_no = $roll_number"); $row1 = mysql_num_rows($sql1); if($row1 == 0) { echo 'Error, ID does not exist'; } else { header('Location: result.php?roll_no='.$roll_number); } } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html> <head> </head> <body> <table width="664" height="260" border="0"> <tr> <td height="88"> </td> </tr> <tr> <td><p> </p> <form id="form1" name="form1" method="post" action="result.php"> <div align="center"> <label>Roll Number : <input type="text" name="roll_no_textbox" id="roll_no_textbox" /> </label> <label> <input type="submit" name="button" id="button" value="search" /> </label> </div> </form> <p align="center"> </p> <p> </p></td> </tr> <tr> <td> </td> </tr> </table> </body> </html>
result.php - The page of result
<?php $hostname = "localhost"; $database = "phpresult"; $username = "root"; $password = "demojoomla"; $conn = mysql_connect($hostname, $username, $password); mysql_select_db($database,$conn); $roll_number = $_GET['roll_no_textbox']; $sql1 = mysql_query("SELECT * FROM result_table WHERE roll_no = $roll_number"); $row1 = mysql_fetch_array($sql1); //$exam1 = $row1['exam1']; //$exam2 = $row1['exam2']; $result_name = $row1['name']; $result_roll_number = $row1['roll_no']; $result_accounts_l = $row1['accounts-l']; $result_accounts_ll = $row1['accounts-ll']; $result_accounts_lll = $row1['accounts-lll']; $result_mpp = $row1['mpp']; $result_economy = $row1['economy']; $result_taxation = $row1['taxation']; $result_computer = $row1['computer']; ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <table width="664" height="260" border="0"> <tr> <td height="88"> </td> </tr> <tr> <td><p align="center">Your Result is here ...</p> <table width="649" height="189" border="0"> <tr> <td colspan="4">Name : <?php echo $result_name ?></td> </tr> <tr> <td colspan="2">Roll Number : <?php echo $result_roll_number ?></td> <td colspan="2"> </td> </tr> <tr> <td width="156"><div align="right">Accounts I : </div></td> <td width="160"><?php echo $result_accounts_l ?></td> <td width="160"><div align="right">Economics : </div></td> <td width="155"><?php echo $result_economics ?></td> </tr> <tr> <td><div align="right">Accounts II : </div></td> <td><?php echo $result_accounts_ll ?></td> <td><div align="right">MPP : </div></td> <td><?php echo $result_mpp ?></td> </tr> <tr> <td><div align="right">Accounts III : </div></td> <td><?php echo $result_accounts_lll ?></td> <td><div align="right">Taxation : </div></td> <td><?php echo $result_taxation ?></td> </tr> <tr> <td colspan="2"> </td> <td colspan="2"> </td> </tr> </table> <div align="center"></div> <p align="center"> </p> <p align="center"> </p> <p> </p></td> </tr> <tr> <td> </td> </tr> </table> </body> </html>
When I search for roll number 1 , its giving error on top of result.php
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in D:\xampp\htdocs\PHPresult\result.php on line 11
Whats the problem ? I think its there in
$row1 = mysql_fetch_array($sql1);
I am confused .. :-[
-
Hi friends,
So finally I am again here, after so many months
I was out of town and I am back on my project of phpresult
-
Hi friends,
I am a PHP student. Yesterday night, i came with an idea that how to create a search engine like www.torrentz.com
Actually on this site, there are no files, but it searches files from other torrent sites and shows like
Same with http://rapidshare-search-engine.com/
this website doesn't contains files but it shows files from rapidshare.com
How can i do that for www.download.com or softpedia.com ?? ???
Can anybody help me ? :)
-
Thank you sir
-
Hi,
I have made one form with following elements
Name :
Age :
IP : hidden field
Date : hidden field.
How can i do that ?
I am using dreamweaver Cs3
I know everything about forms with mySQL surface.
But i am having problem in hidden elements IE IP and DATE
PLease anybody, help me ...
-
Well,
How can i combine them in 1 page ?
Like at the top, there is a Search box with Submit button
after that there will be a result.
How to do that ? In 1 page ?
-
Yes and 1 more question,
Suppose i have only 5 students data that means 1,2,3,4,5 roll no.s are only stored in database.
When i type show_result?roll_no=8 ( Roll No. 8 doesn't exist in database )
Its shows me page with only
Name =
Marks =
I want to do it as there should an error with text "Invalid Roll No."
What i have to do for that ?
-
Yes Sir ,
Now its working fine....
Thank you very much :)
-
Its easy
Download Dreamweaver CS3 or 8
In the application field, there is inbuilt program for login page
-
Code of search.php
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <?php $hostname_php_result_conn = "localhost"; $database_php_result_conn = "phpresult"; $username_php_result_conn = "root"; $password_php_result_conn = "demoxampp"; $php_result_conn = mysql_connect($hostname_php_result_conn, $username_php_result_conn, $password_php_result_conn); mysql_select_db($database_php_result_conn,$php_result_conn); if(isset($_POST['submit'])) { $roll_no = $_POST['roll_no']; $sql1 = mysql_query("SELECT roll_no FROM result_table WHERE roll_no = $roll_no"); $row1 = mysql_num_rows($sql1); if($row1 == 0) { echo 'Error, ID does not exist'; } else { header('Location: show_result.php?roll_no='.$roll_no); } } ?> <html> <head> <title>Search</title> </head> <body> <form action="search.php" method="post"> <input name="roll_no" type="text" id="roll_no" /> <input type="submit" name="submit" value="search" /> </form> </body> </html>
Code of show_result.php
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <?php $hostname_php_result_conn = "localhost"; $database_php_result_conn = "phpresult"; $username_php_result_conn = "root"; $password_php_result_conn = "demoxampp"; $php_result_conn = mysql_connect($hostname_php_result_conn, $username_php_result_conn, $password_php_result_conn); mysql_select_db($database_php_result_conn,$php_result_conn); $roll_no = $_GET['roll_no']; $sql1 = mysql_query("SELECT * FROM result_table WHERE roll_no = $roll_no"); $row1 = mysql_fetch_array($sql1); $name = $row1['name']; $marks = $row1['marks']; ?> <html> <head> <title>Show Results</title> </head> <body> <?php echo 'Name = '.$name.'<br /> Marks = '.$marks; ?> </body> </html>
That's it...
-
Hello John Sir,
Its working fine but 1 error
Error in search.php
I am using Dreamweaver 8
Warning: Cannot modify header information - headers already sent by (output started at D:\xampp\htdocs\phpresult\search.php:2) in D:\xampp\htdocs\phpresult\search.php on line 19
I am using show_result.php instead of showresult.php
So i modified my code
if(isset($_POST['submit'])) {
$roll_no = $_POST['roll_no'];
$sql1 = mysql_query("SELECT roll_no FROM result_table WHERE roll_no = $roll_no");
$row1 = mysql_num_rows($sql1);
if($row1 == 0) {
echo 'Error, ID does not exist';
} else {
header('Location: show_result.php?roll_no='.$roll_no);
But show_result.php is working fine.
-
thank you sir
i will tell you after i make it
-
but how to do that ?
-
Hi friends,
I am new in PHP MySQL.
I am making one script of php exam results.
I have following pages
register.php
search.php
showresult.php
Register.php - > A form where marks will be entered in database.
I have done that.
Search.php -> A search box with "Search" button where students will enter their roll number.
showresult.php - > A page where results will be displayed according to the roll number entered in search.php page.
The page showresult.php should work as follows .....
showresult.php?id=56
That means this will show the result of that student who's roll number is 56
,,
How can i do that ?
-
Hi friends,
I would like to know how can i store the file in mySQL ?
I have seen many sites where download link goes to >>
http://www.site.com/download.php?id=2556
Is the file is uploaded with php form and stored in database ?
How to do that ?
Please can anybody help me ?
-
i want to make website with forum.
And the users should have facility to upload their files .
just like www.mobile9.com
Please tell me is there any such instant script available ?? :-* :-* :-\
[SOLVED] Exam Results script. Please help me ..........
in PHP Coding Help
Posted
Ok
but in which page should i replace it ?
in index.php or result.php ?
or in both ?