frobak
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Everything posted by frobak
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Hi Im trying to write a very simple script that creates a php file that logs a download in a database. Basically, the user will upload some audio and I want to use fopen to automatically create a download counter. I get the file created ok, but my $sql, $result & $connection are stripped and not written, so the queries wont run. Is there anyway to escape this, so it writes the variables. Heres the code: <?php $file = "downloads/pbz99.php"; $open = fopen($file, "w+"); fwrite($open,"<?php include ('functions/db_fws_connect.inc.php'); $sql = 'INSERT INTO `frobakco_fwsapps`.`downloadcount` (`downloadcountid`, `downloadid`) VALUES (NULL, '99')'; $result = @mysql_query($sql,$connection) or die(mysql_error());?> <html><head><title>DJ Neil S audio download page</title></head><body><a href='../mixes/.$filename.mp3'></a></body></html>"); ?> any ideas
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yeah sorry i solved it, my db include file was wrong, so it was looking at my old server and database!
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can you mark this as solved, im stupid!
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yes ive just copied the above table structure direct from phpmyadmin?
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but heres the table, copied directly from mysql? the columns there? customer_id int(15) No company_name varchar(20) Yes NULL address_line1 varchar(20) Yes NULL address_line2 varchar(20) Yes NULL City varchar(20) Yes NULL postcode varchar( Yes NULL contact_name varchar(25) Yes NULL emailaddress varchar(25) Yes NULL webaddress varchar(25) Yes NULL phone varchar(20) Yes NULL fax varchar(20) Yes NULL mobile varchar(20) Yes NULL
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thank but this still doesnt work, i am still getting the same error Unknown column 'company_name' in 'field list' surely this is something really simple?
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CREATE TABLE customers( customer_id INT(15), company_name VARCHAR(20), address_line1 VARCHAR(20), address_line2 VARCHAR(20), City VARCHAR(20), postcode VARCHAR(, contact_name VARCHAR(25), emailaddress VARCHAR(25), webaddress VARCHAR(25), phone VARCHAR(20), fax VARCHAR(20), mobile VARCHAR(20));
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Hi i have this simple php insert statement, but whatever i try it says: Unknown column 'company_name' in 'field list' all the column names are the same in my html documnt, this statement here and in my database table. Thsi is really simple and driving me mad <? if($_POST['add']) { include("includes/db_connect.inc.php"); $sql = ("INSERT INTO customers (company_name, address_line1, address_line2, city, postcode, contact_name, emailaddress, webaddress, phone, fax, mobile) VALUES ('$_POST[company_name]', '$_POST[address_line1]', '$_POST[address_line2]', '$_POST[city]', '$_POST[postcode]', '$_POST[contact_name]', '$_POST[emailaddress]', '$_POST[webaddress]', '$_POST[phone]', '$_POST[fax]', '$_POST[mobile]')"); $result = @mysql_query($sql,$connection) or die(mysql_error()); } ?> any help much appreciated. cheers
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Thsi file open a dialog box to open the index page and not the mp3 file. ANy idea why this happen? <?php include '../functions/db_connect.inc.php'; $sql = ("INSERT INTO downloadcount (downloadid) VALUES ('$_REQUEST[downloadreq]')"); $result = @mysql_query($sql,$connection) or die(mysql_error()); $filename = "milli.mp3"; $myFile = "/httpdocs/djneils/mixes/milli.mp3"; $mm_type="application/octet-stream"; header("Cache-Control: public, must-revalidate"); header("Pragma: hack"); // WTF? oh well, it works... header("Content-Type: " . $mm_type); header("Content-Length: " .(string)(filesize($myFile)) ); header('Content-Disposition: attachment; filename="'.$filename.'"'); header("Content-Transfer-Encoding: binary\n"); readfile($myFile); ?>
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Ive tried this but it opens the index page and not the mp3? <?php include '../functions/db_connect.inc.php'; $sql = ("INSERT INTO downloadcount (downloadid) VALUES ('$_REQUEST[downloadreq]')"); $result = @mysql_query($sql,$connection) or die(mysql_error()); $filename = "milli.mp3"; $myFile = "/mixes/milli.mp3"; $mm_type="application/octet-stream"; header("Cache-Control: public, must-revalidate"); header("Pragma: hack"); // WTF? oh well, it works... header("Content-Type: " . $mm_type); header("Content-Length: " .(string)(filesize($myFile)) ); header('Content-Disposition: attachment; filename="'.$filename.'"'); header("Content-Transfer-Encoding: binary\n"); readfile($myFile); header('Location: ../index.php'); ?>
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Hi Im making a real simple audio download page with a counter on each download, nothing fancy, just need the job done. So the basics are i want a user to click on a link, and i want it to update a database table, which works fine, but i want it to also open the audio file for download, which i cant get to work. The script im trying to run is as follows: <?php include '../functions/db_connect.inc.php'; $sql = ("INSERT INTO downloadcount (downloadid) VALUES ('$_REQUEST[downloadreq]')"); $result = @mysql_query($sql,$connection) or die(mysql_error()); $handle = fopen("../mixes/milli.mp3", "r"); <----------this not working?????????? header('Location: ../index.php'); ?> Am i barking up the wrong tree? or can i get this to work? any help appreciated. cheers fro
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[SOLVED] Assign a session variable from a posted form?
frobak replied to frobak's topic in PHP Coding Help
cheers -
[SOLVED] Assign a session variable from a posted form?
frobak replied to frobak's topic in PHP Coding Help
$sql = "UPDATE customers SET cust_firstname = '$_POST[cust_firstname]', cust_surname = '$_POST[cust_surname]', house_no = '$_POST[house_no]', streetname = '$_POST[streetname]', postcode = '$_POST[postcode]', emailaddress = '$_POST[emailaddress]', homephone = '$_POST[homephone]', mobphone = '$_POST[mobphone]', WHERE username = {$_SESSION['username']}"; why am i being told i have an sql error near my where clause? -
[SOLVED] Assign a session variable from a posted form?
frobak replied to frobak's topic in PHP Coding Help
cheers -
[SOLVED] Assign a session variable from a posted form?
frobak replied to frobak's topic in PHP Coding Help
This doesnt work though? $sql = "SELECT * FROM customers WHERE userid= $_SESSION['userid']"; it says: Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in C:\Inetpub\vhosts\frobak.co.uk\httpdocs\pages\show_cust_details.php on line 18 -
[SOLVED] Assign a session variable from a posted form?
frobak replied to frobak's topic in PHP Coding Help
excellent, cheers for your help guys! -
[SOLVED] Assign a session variable from a posted form?
frobak replied to frobak's topic in PHP Coding Help
So how would i use the variable say to update a table, ie UPDATE customers WHERE userid = ????????? -
[SOLVED] Assign a session variable from a posted form?
frobak replied to frobak's topic in PHP Coding Help
session_start(); if (isset($_POST['userid']) && isset($_POST['password'])) { $table_name = "customers"; include '../functions/db_connect.inc.php'; $userid = $_POST['userid']; $password = $_POST['password']; // check if the user id and password combination exist in database $sql = "SELECT * FROM customers WHERE userid= '$userid'"; $result = mysql_query($sql) or die('Query failed. ' . mysql_error()); if (mysql_num_rows($result) == 1) { // the user id and password match, // set the session $_SESSION['db_is_logged_in'] = true; $_SESSION[$userid] = $userid; // after login we move to the main page header('Location: ../pages/control_panel.php?$userid;'); exit; } else { $errorMessage = 'Sorry, wrong user id / password'; } } How do i get the posted value of userid to $_SESSION[$userid]? and then how do i call it in another script? -
Hi, im making a simple user control panel, the user logs in by entering a user id and passowrd, which is checked in a mysql database before displaying the control panel. from this control panel i want the user to be able to change user details, sign up for bits, register for stuff etc. When the user clicks on a link to update their user details for example, i want to use the user id originally posted with the login form. Is it possible to register a session variable from a posted field in a form, and then retreive and use throughout my control panel? Ive tried many different ways to pass variables but its not happening? Any ideas?