cauca
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Everything posted by cauca
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Ok now I'll left the code more strong. You came to Rio de Janeiro, is a beautiful place to visit, but have a lot of beautiful beach in other states of Brasil , for exemple BOMBINHAS - Santa Catarina, or SALVADOR - Bahia, in NORDESTE'S beach in so beautiful too ! Thank's for all, God Bless you and your wife ! see you in the forum Paulo Cauca
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yessss I fund where are wrong : The select was missing this $query = "SELECT user_img [b]from user[/b] WHERE user_id = '{$_GET['user_id']}'"; yess Thank's man for all I'm lunch now srsrs God Bless Paulo Cauca
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ok !!! here is the code: index.php <html> <head> <script language="javascript"> var xmlHttp = false; try { xmlHttp = new ActiveXObject("Msxm12.XMLHTTP") } catch (e){ try { xmlHttp = new ActiveXObject("Microsoft.XMLHTTP") } catch (E){ xmlHttp = false } } if (!xmlHttp && typeof XMLHttpRequest != 'undefined') { xmlHttp = new XMLHttpRequest () } function teste(){ document.getElementById('ret_teste').innerHTML = "<div align='center'><img src='./loader.gif'></div>"; var inp_val = frm.inp_cont.value; var url="teste.php?action=users&teste="+inp_val; xmlHttp.open("GET",url,true); xmlHttp.onreadystatechange=stateChanged_r; xmlHttp.send(null); function stateChanged_r(){ if (xmlHttp.readyState==4 || xmlHttp.readyState=="complete"){ document.getElementById("ret_teste").innerHTML = xmlHttp.responseText; } } } function inserir(){ var ins_name = insert_values.ins_name.value var ins_file = insert_values.ins_file.value var url="insert.php" url=url+"?ins_name="+ins_name+"?ins_file"+ins_file url=url+"&sid="+Math.random() xmlHttp.open("GET",url,true) xmlHttp.onreadystatechange=stateChanged_i xmlHttp.send(null) function stateChanged_i() { document.getElementById('ret_insert').innerHTML = "<img src='./loader.gif'>"; if (xmlHttp.readyState==4 || xmlHttp.readyState=="complete") { document.getElementById("ret_insert").innerHTML=xmlHttp.responseXML('Content-Type',"text/xml") } } } </script> </head> <body> <table align="center"> <tr> <td> <form name="insert_values" action="up.php" method="post"> Nome:<input type="text" name="ins_name"> Arquivo:<input type="file" name="ins_file"> <input type="submit" value="enviar""> </form> </td> </tr> <tr> <td><div id="ret_insert"</div> </td> </tr> <tr> <td colspan="2" align="center"> <form name="frm"> Procurar:<input type="text" name="inp_cont" onkeyup="teste(this)"><br> </form> </td> </tr> </table> <div id="ret_teste" align="center"></div> </body> </html> teste.php <?php include_once("conectadb.php"); if ($_GET['action']=="img"){ $query = "SELECT user_img WHERE user_id = '{$_GET['user_id']}'"; $result = mysql_query($query); $row = mysql_fetch_assoc($result); echo $row['user_img']; } else{ $teste = $_GET['teste']; $query="select user_id from user where user_name like '%$teste%'"; $select = mysql_query($query); while ($linha = mysql_fetch_assoc($select)){ $user = $linha['user_id']; echo "<image src='teste.php?action=img&user_id=$user'>"; } } ?> Thank's God Bless man Paulo
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ok ! I changed de code ... But now don't show de image ... Thank's God Bless Paulo
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Hello, good morning ... I put the code online in de web visit please: www.barahinformatica.com.br/testimgfile/ Try type in "Procurar:" the names above: Paulo Roberto Patricia Renata Patrick Teste Cristina Oliveira Margarida Flor If you starting type letter "P" the function need return Paulo's image, Patricia's image and Patrick's image. Than´k God Bless PauloCauca Corin Falador
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Ok thank´s F1Fan! I tried it but didn´t have success !!! when I call the function the php don´t return the image ! God Bless Paulo Cauca
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The table : user_id int(11) Não auto complet user_name varchar(30) Não user_img longblob Não Is this? God Bless Paulo Cauca
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I found the # button in the next code I´ll put it Paulo Cauca
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sorry for the large code, sorry too because I can´t find a #button ! Thank´s for the help, I try you code and the result is ok ! I take you code and put only this "<img src='"+url+"'>"; the result was the same result. Both return only one image at a time! I have in the DataBase personals name. I call the DB with LIKE %user_name% I want return for example every images that name start with PA. God Bless Paulo Cauca
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Thank´s for read the topic ! //Code php include_once("conectadb.php"); $teste = $_GET['teste']; $query="select * from user where user_name like '%$teste%'"; $select = mysql_query($query); while ($linha = mysql_fetch_array($select)){ $img = $linha['user_img']; echo $img; } ?> //CODE AJAX function teste(){ var inp_val = frm.inp_cont.value var url="teste.php" url=url+"?teste="+inp_val url=url+"&sid="+Math.random() xmlHttp.open("GET",url,true) xmlHttp.onreadystatechange=stateChanged_r xmlHttp.send(null) function stateChanged_r() { document.getElementById('ret_teste').innerHTML = "<div align='center'><img src='./loader.gif'></div>"; if (xmlHttp.readyState==4 || xmlHttp.readyState=="complete") { document.getElementById("ret_teste").innerHTML = "<img src='teste.php'>"; } } // the html code <form name="frm"> Procurar:<input type="text" name="inp_cont" onkeyup="teste(this)"><br> </form> THANKS GOD BLESS PAULOCAUCA
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Hello, Fist i want introduce myself, My name´s Cauca I live in Brasil; I`m a student (Devoloped sistem to Internet). I want help this forum with ask and question ! Thi first I have ask ;-) ! I´m trying loader a image with code bellow: -> I have a image in BLOB format in MySQL; -> I recover this img in a variable with php and show it with echo ! EX: I have a select ... echo $img; If I access this page direct by localhost , the img is showed with no error, But what I want is: thi img be showed by the innerHTML I tray document.getElementById("ret_teste").innerHTML = "<img src='teste.php'>"; and document.getElementById("ret_teste").innerHTML = xmlHttp.responseText off course that I have a Ajax connection with all function ok, I´m having a problem to mount a img in this parameters; Thank´s for help me God Bless us Cauca