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slj90

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About slj90

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  1. $username = "user1"; $result = single_row_prepared($username); echo $username . " - " . $country . " - " . $about . " - " . $age; It says the variables are undefined. How do I echo them out? function single_row_prepared($username) { global $connect; $sql = "SELECT profile_username, profile_country, profile_about, profile_age "; $sql .= "FROM profiles "; $sql .= "WHERE profile_username = ?"; $stmt = mysqli_prepare($connect, $sql); mysqli_stmt_bind_param($stmt, 's', $username); mysqli_stmt_execute($stmt); mysqli_stmt_bind_result($stmt, $username, $country, $about, $age); mysqli_stmt_fetch($stmt); mysqli_stmt_close($stmt); } [06-Dec-2017 08:19:54 UTC] PHP Notice: Undefined variable: country in /home/buysnapchats/public_html/examples/prepared_statement_single_row.php on line 13 [06-Dec-2017 08:19:54 UTC] PHP Notice: Undefined variable: about in /home/buysnapchats/public_html/examples/prepared_statement_single_row.php on line 13 [06-Dec-2017 08:19:54 UTC] PHP Notice: Undefined variable: age in /home/buysnapchats/public_html/examples/prepared_statement_single_row.php on line 13
  2. Say I had a website which uses GET to gather an ID from the URL. This ID is then used to retrieve data for page, such as the title, description and other page contents. Will Google still be able to find and display these pages in search results when the base page has no content? Do I need to do anything imparticular for Google and other search engines to be able to find these pages? If its not possible are there any solutions to this other than each page being its own unique page/file? Thanks,
  3. slj90

    If number not a date

    Hello, The user enters a 4 digit number as a date. Some examples: 0101 = 1st January 1902 = 19th Feb 2412 = 24th December Is there a way I can perform an if function to tell if the number isn't a date? For exampe if the user enters the number e.g 0001, 4112, 0199? I already make sure that it is a 4 digit number and not over 3112. Thanks,
  4. Hello, Here is the structure of my website: website.com/events/page1?date=1224 website.com/events/page2?date=0101 website.com/events/page3?date=1105 There are lots of different pages all of which I would like to use the $_Get 'date' on. I want to rewrite the URL using htaccess so that they can be loaded like this: website.com/events/page1/1224 website.com/events/page2/0101 website.comevents/page3/1105 Is this possible without having to create a separate rule for each page? Thanks in advance!
  5. function DeleteItemByID(elm) { var deleteid = elm.id; $.post('../action/deleteitem.php',{item:deleteid},function(e){ deleteidalpha = deleteid.replace(/\D/g,''); var itemdiv = "#itemdiv" + deleteidalpha $(itemdiv).hide(); }); } The above code works fine in chrome and firefox but doesn't work properly in IE. In IE it only hides itemdiv but doesn't send the data to the php file. What do I need to change for IE compatibility? Thanks,
  6. There are 2 parts to my question. Firstly, To view a users profile on my site you can type this: www.website.com/username I now want to do the same thing with the gallery page. Like this: www.website.com/gallery/username My question is, do I need to put the gallery.php page in a folder called 'gallery' or do I just need to have the gallery.php page in the htdocs main folder? My .htaccess currently reads RewriteCond %{REQUEST_FILENAME}\.php -f RewriteRule ^(.*)$ $1.php RewriteRule ^([a-zA-Z0-9_-]+)$ profile.php?username=$1 RewriteRule ^([a-zA-Z0-9_-]+)/$ profile.php?username=$1 What do I need to add to it so that gallery works too? Thanks
  7. slj90

    Resize Image

    I am using the following code to save an image if($_SERVER['REQUEST_METHOD'] == "POST") { // location to save cropped image $url = 'saved12223.jpg'; // remove the base64 part $base64 = base64_decode(preg_replace('#^data:image/[^;]+;base64,#', '', $_POST['string'])); // create image $source = imagecreatefromstring($base64); // save image imagejpeg($source, $url, 100); } But how can I resize the width and height before saving the image. I'm not sure if I should be resizing the source or the string? Please could someone point me in the right direction. Thanks,
  8. Trying to combine 2 vars and use them as an ID.. var x = "#inputList"; var y = 2; $(add_button).click(function(e){ e.preventDefault(); alert([x+y]); $([x+y]).css('display', 'inline'); y = y + 1; The alert displays #inputList2 but the line below doesn't work. Any ideas? Thanks
  9. slj90

    Vertical Range Select Messes Up Buttons Above

    I solved it by adding a width/height to the class
  10. On my page I have a vertical range selector. However, the button above where the range selector is don't work properly. It's almost as if the range selector is for some reason over the button and therefore making it unclickable. It's weird because about 1/4 of the button works properly but when it gets to the part that is inline with the range it doesn't function.. I tried using z-index with no luck. I am using the following to rotate it... The image is also rotated .v { transform: rotate(-90deg); } .v img { transform: rotate(90deg); } Any ideas? I have attached a picture to help explain Thanks
  11. I'm using PHP to echo out a button within a loop along with other data. ... <input id="delete' . $row[item_generated_id] . '" type="button" class="btn btn-danger" value="Delete" onclick="DeleteItemByID()"'; echo '">... I then want the function to alert the buttons ID... function DeleteItemByID() { var deleteid = $(this).attr('id'); alert(deleteid); } However, it is currently only alerting 'undefined'. What's wrong? Having the button alert it's ID is obviously not my final objective but it will help me. Thanks!
  12. Maybe this will help you http://jsfiddle.net/qrn0p43k/ This line gets the column number of the cell that was clicked... var column_num = parseInt( $(this).index() ) + 1; And this line tells the css which column to change table th:nth-child(" + column_num + "), table td:nth-child(" + column_num + ") This line changes the css $(code).addClass('pink');
  13. I have managed to solved this, here is how. $('#pos').on('change', function() { var topleft = "topleft"; var option = $(this).find('option:selected').val(); if(option == topleft){ alert("Top Left") } });
  14. I'm not sure exactly what you mean but I have jjust changed to alert( this.val ); Which alerts "undefined", which is why it isn't working. When the user selects the "Top Left" option I want the function to run. Thanks
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