DanPri

thank you, both worked

Here it is <?php $first_name = $_POST['first_name']; $last_name = $_POST['last_name']; $nick_name = $_POST['nick_name']; $ass = $_POST['ass']; $height = $_POST['height']; $weight = $_POST['weight']; $from = $_POST['from']; mysql_connect ("localhost", "cwreaves_fd", "fd") or die ('Error: ' . mysql_error()); mysql_select_db ("cwreaves_fd"); [b]$query = "INSERT INTO fighter_info(first_name, last_name, nick_name, ass, height, weight, from) VALUES ('$first_name','$last_name','$nick_name','$ass','$height','$weight','$from')";[/b] mysql_query($query) or die ('Error updating Database'); echo "Database updated with: ".$id."".$first_name."".$last_name." ; ?>

I am now getting this error Parse error: syntax error, unexpected $end can anyone help please

thank you and thanks for such a quick reply

Hi Guys I know this is a regular question but i have seached everywhere for the answear. I get this error : Parse error: syntax error, unexpected T_VARIABLE on line 13 <?php $first_name = $_POST['first_name']; $last_name = $_POST['last_name']; $nick_name = $_POST['nick_name']; $ass = $_POST['ass']; $height = $_POST['height']; $weight = $_POST['weight']; $from = $_POST['from']; mysql_connect ("localhost", "cwreaves_fd", "fd") or die ('Error: ' . mysql_error()); mysql_select_db ("cwreaves_fd") [b]$query = "INSERT INTO fighter_info(first_name, last_name, nick_name, ass, height, weight, from) VALUES ('$first_name','$last_name','$nick_name','$ass','$height','$weight','$from')";[/b] mysql_query($query) or die ('Error updating Database'); echo "Database updated with: ".$id."".$first_name."".$last_name." ; ?> if any one can help I would be very greatfull