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Posts posted by PravinS

  1. your php code should be like this

        // Always try to connect and select the DB before anything else
        $con = mysql_connect("localhost", "jingleko_reload", "*******") or die("Couldnt Connect to DB - ".mysql_error());
        mysql_select_db("jingleko_reloader", $con) or die("Couldnt Select a DB - ".mysql_error());
        // Set post var
        $Epost = trim(addslashes(strip_tags($_POST['Epost'])));
        if (isset($_POST['Epost']))
            // Look for it in DB
            $query = "SELECT Epost FROM newsletter WHERE Epost='".$Epost."'";
            $result = mysql_query($query);
            //If found, do next thing
            if (mysql_num_rows($result) > 0)
                mysql_query("DELETE FROM newsletter WHERE Epost='$Epost'") or die(mysql_error());
                echo "<div align=\"center\"><img src=\"Pics/Vlaamse Leeuw.jpg\" width=\"114\" height=\"127\" border=\"0\"></div>";
                echo "<p align=\"center\"><b>Thank you, you are now removed from the list.</b></p><br>";
                echo "<p align=\"center\"><a href=\"index.htm\"><img src=\"Pics/begin.gif\" width=\"95\" height=\"30\" border=\"0\"></a></p>";
                echo "<div align=\"center\"><b><font color=\"red\">This address does not exist</font></b></div><br>";
                echo "<div align=\"center\"><a href=\"eruit.htm\"><img src=\"Pics/herbegin.gif\" width=\"95\" height=\"30\" border=\"0\"></a>";
                echo "<a href=\"index.htm\"><img src=\"Pics/begin.gif\" width=\"95\" height=\"30\" border=\"0\"></a></div>";
  2. you can use isset() function to check if $_FILES['image'] is set of not like

    if (isset($_FILES['image']))
         // your code here
         // your code here

    may this will help you

  3. i think your code should be like this

    $event = array("Flash Flood Watch", "Flash Flood Warning", "Severe Thunderstorm Watch", "Severe Thunderstorm Warning", "Torndao Watch", "Torndao Warning");
    $searchvalue = "Flash Flood Watch"; //as example
    if (in_array($searchvalue, $event))
        echo "Match found";

    also go through in_array() function properly


  4. give name as array for each field, as

          foreach ($items as $item)
             echo'<div class="items-row">
                  <label for="name_'.$item['item_id'].'">'.$item['item_name'].'</label>
                   <div class="item_input"><input type="text" name="quantity[]" id="'.$item['item_name'].'" value="0"></div>
                   <input type="hidden" name="item_ids[]"  value="'.$item['item_id'].'">
                   <input type="hidden" name="user_ids[]"  value="'.$moving_basics_id.'">
  5. mysql_select_db("ahamdabad_vpn_ip$", $dbc);

    $sql = "select main_system from ahamdabad_vpn_ip$";



    "ahamdabad_vpn_ip$" is you database or table name?


    also it is not good practice to use "$" in database of table name

  6. your form method is post, so use POST while getting variable data

  7. try replacing this code

    <form action="add_bk_insert.php">
    Name <input type="text"  name="name"/><br />
    E-mail <input type="text"  name="email" /><br />
    Contact <input type="text"  name="contact" /><br />
    Requirement <input type="text"  name="requirement" /><br />
    <input type="submit" value="Submit" name="btnSubmit"/>
    if (isset($_POST['btnSubmit']))
    	$name = isset($_POST[name]) ? $_POST[name] : '';
    	$email_id = isset($_POST[email_id]) ? $_POST[email_id] : '';
    	$contact = isset($_POST[contact]) ? $_POST[contact] : '';
    	$requirement = isset($_POST[requirement]) ? $_POST[requirement] : '';
    	$order = "INSERT INTO sal2 (name,email_id, contact,requirement) VALUES('".$name."','".$email_id."','".$contact."','".$requirement."')";
    	$result = mysql_query($order); 
    	 echo "Inserted";   
    	} else{
    		echo("<br>Input data is fail");
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