PravinS

May 29, 2014

you can use PHP time zone instead of javascript time zone

May 28, 2014

remove the back ticks (``) from VALUES of INSERT query and use single quotes (' ')

$query = "INSERT INTO user(user,pass,priv,mail,avatar,date) VALUES('$user','$pass','$priv','$mail','$avatar','$date')";

may this works for you

May 26, 2014

check the SQL query, whose resource id is passed to mysql_fetch_array() function at mentioned line or else show us the code of C:\xampp\htdocs\index.php

May 21, 2014

use this updated javascript function

function checkForm()
{
	var obj = document.getElementsByName('dest[]');
	var destCount = obj.length;
	var destSel   = false;
	for(var i = 0; i < destCount; i++)
	{
		if(obj[i].checked == true)
			destSel = true;
	}
	if(destSel == false)
	{
		alert('Select one or more destinations');
	}
	return destSel;
}

May 21, 2014

use this code


<html>
<head>
<script language="javascript">
function checkForm(){
var obj = document.getElementsByName('dest[]');
var destCount = obj.length;
var destSel   = false;
for(i = 0; i < destCount; i++){
if(obj.checked == false){
destSel = true;
break;
}
}

if(!destSel){
alert('Select one or more destinations');
}
return destSel;
}
</script>
</head>
<body>
Select at least one destination
<form action="" method="post">
<input id="cx" type="checkbox" name="dest[]" value="CX" />   <label for="cx">Cox's Bazar</label><br />
<input id="su" type="checkbox" name="dest[]" value="SU" />   <label for="su">Sundarban</label><br />
<input id="sy" type="checkbox" name="dest[]" value="SY" />   <label for="sy">Sylhet</label><br />
<input id="ch" type="checkbox" name="dest[]" value="CH" />   <label for="ch">Chittagong</label><br />
<br />
<input type="submit" name="Go" value="  Go  "  onclick="return checkForm();"/>
</form>
</body>
</html>

also check the jsfiddle

May 21, 2014

Just remove onsubmit="return checkForm(this);" from form tag and add it to button as onclick="return checkForm(this);"

Use this

<form action="" method="post">
<input id="cx" type="checkbox" name="dest[]" value="CX" />   <label for="cx">Cox's Bazar</label><br />
<input id="su" type="checkbox" name="dest[]" value="SU" />   <label for="su">Sundarban</label><br />
<input id="sy" type="checkbox" name="dest[]" value="SY" />   <label for="sy">Sylhet</label><br />
<input id="ch" type="checkbox" name="dest[]" value="CH" />   <label for="ch">Chittagong</label><br />
<br />
<input type="submit" name="Go" value="  Go  "  onclick="return checkForm(this);"/>
</form>

May 17, 2014

your php code should be like this

<?php
    // Always try to connect and select the DB before anything else
    $con = mysql_connect("localhost", "jingleko_reload", "*******") or die("Couldnt Connect to DB - ".mysql_error());
    mysql_select_db("jingleko_reloader", $con) or die("Couldnt Select a DB - ".mysql_error());

    // Set post var
    $Epost = trim(addslashes(strip_tags($_POST['Epost'])));
    if (isset($_POST['Epost']))
    {
        // Look for it in DB
        $query = "SELECT Epost FROM newsletter WHERE Epost='".$Epost."'";
        $result = mysql_query($query);
        //If found, do next thing
        if (mysql_num_rows($result) > 0)
        {
            mysql_query("DELETE FROM newsletter WHERE Epost='$Epost'") or die(mysql_error());
            echo "<div align=\"center\"><img src=\"Pics/Vlaamse Leeuw.jpg\" width=\"114\" height=\"127\" border=\"0\"></div>";
            echo "<p align=\"center\"><b>Thank you, you are now removed from the list.</b></p><br>";
            echo "<p align=\"center\"><a href=\"index.htm\"><img src=\"Pics/begin.gif\" width=\"95\" height=\"30\" border=\"0\"></a></p>";
        }
        else
        {
            echo "<div align=\"center\"><b><font color=\"red\">This address does not exist</font></b></div><br>";
            echo "<div align=\"center\"><a href=\"eruit.htm\"><img src=\"Pics/herbegin.gif\" width=\"95\" height=\"30\" border=\"0\"></a>";
            echo "<a href=\"index.htm\"><img src=\"Pics/begin.gif\" width=\"95\" height=\"30\" border=\"0\"></a></div>";
        }        
    }
    mysql_close($con);
?>

May 8, 2014

you can use isset() function to check if $_FILES['image'] is set of not like

if (isset($_FILES['image']))
{
     // your code here
     var_dump($_FILES['image']);
     // your code here
}

may this will help you

May 8, 2014

you can check it like this

if (is_array($_POST['interest']) && count($_POST['interest']) > 0)
{
       // code here
}

Generate PHP profile page with PHP data · May 8, 2014

do you know URL rewriting?

check : http://httpd.apache.org/docs/2.0/misc/rewriteguide.html

April 19, 2014

i think your code should be like this

$event = array("Flash Flood Watch", "Flash Flood Warning", "Severe Thunderstorm Watch", "Severe Thunderstorm Warning", "Torndao Watch", "Torndao Warning");
$searchvalue = "Flash Flood Watch"; //as example

if (in_array($searchvalue, $event))
{
    echo "Match found";
}

also go through in_array() function properly

http://www.php.net/in_array

March 21, 2014

use php explode() function

http://www.php.net/manual/en/function.explode.php

March 11, 2014

give name as array for each field, as

<?php
      foreach ($items as $item)
      {
         echo'<div class="items-row">
              <label for="name_'.$item['item_id'].'">'.$item['item_name'].'</label>
               <div class="item_input"><input type="text" name="quantity[]" id="'.$item['item_name'].'" value="0"></div>
               <input type="hidden" name="item_ids[]"  value="'.$item['item_id'].'">
               <input type="hidden" name="user_ids[]"  value="'.$moving_basics_id.'">
               </div>'; 
      }
?>

March 8, 2014

your function should return the value like

<?php 
   function test()
   {
        $response = "hello";
        return $response;
   }
?>

and then you can call the function like this

<input type="textbox" name="xx"  value="<?php echo test(); ?>" />

March 6, 2014

can you show us the actual code

March 3, 2014

thanks mate. its solve. it work perfectly on live server but its appearing "no database found" when running it offline. the database.php also include in the folder.

it means you haven't created database on your local machine or the database connection in database.php is not correct

March 3, 2014

at this line add mysql_error() like this and check what is the issue

$data=mysql_query("SELECT OT.nostaf, OT.otl_tkh_m, OT.otl_tkh_y ,OT.otl_jum_jam, OT.otl_jabatan FROM ot_line OT") or die(mysql_error());

February 11, 2014

mysql_select_db("ahamdabad_vpn_ip$", $dbc);

$sql = "select main_system from ahamdabad_vpn_ip$";

"ahamdabad_vpn_ip$" is you database or table name?

also it is not good practice to use "$" in database of table name

February 10, 2014

use urlencode() and urldecode() functions

February 10, 2014

echo the SQL query and execute it in phpmyadmin

also write mysql_close($con); at the end the bottom of the code

February 10, 2014

check you SQL query, remove space between FROM and table name from SQL query

$query ="SELECT * From Section order by sectCode ASC";

February 8, 2014

your form method is post, so use POST while getting variable data

$destinationCode=$_POST['destinationcode'];
$numberofadults=$_POST['numberofadults'];
$numberofchildren=$_POST['numberofchildren'];
$startdate=$_POST['stardate'];
$enddate=$_POST['enddate'];

February 5, 2014

you can check this example

http://www.w3schools.com/php/php_ajax_database.asp

January 22, 2014

try uncommenting the if condition

<?php
//$ab=1;
$ab = '';
if(isset($_GET['id'])) 
      $ab= $_GET['id'];
echo $ab;
?>

January 21, 2014

check

http://www.phpclasses.org/package/5927-PHP-Display-an-hierarchic-menu-stored-in-a-MySQL-table.html

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PravinS

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Posts posted by PravinS

timezone offset

Insert function not working

mysql connection file

checkbox validation on click

checkbox validation on click

checkbox validation on click

There is a mistake somewhere....

Notice: Undefined index: image

is_array

Generate PHP profile page with PHP data

Problem with Array

Convert comma seperated strings into array

Adding Values from looped input fields

Output to textbox from within a function

PHP Arrays

Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given

Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given

problem in my program

& problem in URL

Warning: mysql_fetch_row() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\Exer10\prtSect.php on line 20

Warning: mysql_fetch_row() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\Exer10\prtSect.php on line 20

get variables not working

ajax with php

Query string error: Undefined index: id

Dropdown php

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