joesaddigh

Hi, I am currently running PHP 5.4.12 and cannot find a compatible php_win32service.dll to download. All the ones that I have seen seem to be for PHP 5.2/5.3? When trying to use the dll made for these versions, I get the following error message: PHP Warning: PHP Startup: Unable to load dynamic library 'ext\php_win32service.dll' - The specified module could not be found. It is worth pointing out that I have put the dll in the correct place along with the other extensions! Please can somebody give me any advice on where to go from here? Thanks in advance. Joe

Hi, This is probably a really basic question but I really can't find the answer. Once I have configured and downloaded Nginx and PHP how do I actually run a PHP script, i.e. I create a simple index.php page and I want to open it in a browser and ensure the PHP code is run. My dir structure is as follows: C:\nginx C:\nginx\php My nginx.conf file is: #user nobody; worker_processes 1; #error_log logs/error.log; #error_log logs/error.log notice; #error_log logs/error.log info; #pid logs/nginx.pid; events { worker_connections 1024; } http { include mime.types; default_type application/octet-stream; #log_format main '$remote_addr - $remote_user [$time_local] "$request" ' # '$status $body_bytes_sent "$http_referer" ' # '"$http_user_agent" "$http_x_forwarded_for"'; #access_log logs/access.log main; sendfile on; #tcp_nopush on; #keepalive_timeout 0; keepalive_timeout 65; #gzip on; server { listen 80; server_name localhost; #charset koi8-r; #access_log logs/host.access.log main; location / { root html; index index.html index.htm; } #error_page 404 /404.html; # redirect server error pages to the static page /50x.html # error_page 500 502 503 504 /50x.html; location = /50x.html { root html; } # proxy the PHP scripts to Apache listening on 127.0.0.1:80 # #location ~ \.php$ { # proxy_pass http://127.0.0.1; #} # pass the PHP scripts to FastCGI server listening on 127.0.0.1:9000 # #location ~ \.php$ { # root html; # fastcgi_pass 127.0.0.1:9000; # fastcgi_index index.php; # fastcgi_param SCRIPT_FILENAME /scripts$fastcgi_script_name; # include fastcgi_params; #} location ~ .php$ { root html; fastcgi_pass 127.0.0.1:9000; fastcgi_index index.php; fastcgi_param SCRIPT_FILENAME c:/nginx/html/$fastcgi_script_name; include fastcgi_params; } # deny access to .htaccess files, if Apache's document root # concurs with nginx's one # #location ~ /\.ht { # deny all; #} } # another virtual host using mix of IP-, name-, and port-based configuration # #server { # listen 8000; # listen somename:8080; # server_name somename alias another.alias; # location / { # root html; # index index.html index.htm; # } #} # HTTPS server # #server { # listen 443; # server_name localhost; # ssl on; # ssl_certificate cert.pem; # ssl_certificate_key cert.key; # ssl_session_timeout 5m; # ssl_protocols SSLv2 SSLv3 TLSv1; # ssl_ciphers HIGH:!aNULL:!MD5; # ssl_prefer_server_ciphers on; # location / { # root html; # index index.html index.htm; # } #} } I have created a batch file for starting and stopping the php service and this seems to work (I run tasklist /svc) and I see the php-cgi.exe service appear and disappear. Although when I run the start service: @ECHO OFF c:\nginx\nginx.exe c:\nginx\php\php-cgi.exe -b 127.0.0.1:9000 -c c:\nginx\php\php.ini ping 127.0.0.1 -n 1>NUL echo Starting nginx echo . echo . echo . ping 127.0.0.1 >NUL EXIT It gives me an error "nginx: [alert] could not open error log file: CreateFile() "logs.error.log" failed (3: The system cannot find the path specified) even though I have added a file at this level: C:\nginx\logs\error.log Please any suggestions would be very much appreciated! Joe

Hi, I have managed to debug my PHP application using XDebug and Eclipse - This is like a dream as I am used to the luxury of a debugger :-) However I have a few problems... 1) It will only stop at any of my breakpoints if I start the debug session from index.php - Used to work on other pages too but since I tried to uncheck the Break at first line this problem arose? I only want it to stop at my breakpoints which is why i fiddled with these settings in the first place.. 2) In the PHP debugger section it seems to think I am using the Zend Debugger - I don't even have this installed (why does it work?) I originally set it up with the Xdebug as this choice? 3) How do you simply import an existing php file into your project? I did it by using windows explorer view and dragging the files I wanted to use in to eclipse which seemed to add them to the library. However when I later did a create new file selection and then debugged it didn't find the file. I then created the new file manually and drag and dropped it in and it worked fine? my php.ini settings are as follows: [XDebug] zend_extension = "C:\xampp\php\ext\php_xdebug.dll" xdebug.remote_enable=1 xdebug.remote_host=localhost xdebug.remote_port=9001 xdebug.remote_handler=dbgp xdebug.profiler_enable=0 xdebug.remote_mode=req xdebug.remote_autostart=0 Image attached to show relevant settings in Eclipse: Please any advise would be greatly received. Thanks, Joe 17236_.doc 17237_.doc

Yeah that's how I have got along so far. Going to give setting up zend another go as it makes itso much quicker being able to debug. Thanks for your help.

That' excellent. Looking forward to creating some useful classes that I can re-use. One more thing if you don't mind. What do you use to debug PHP and is this easy to setup (know of any tutorials). I have tried setting up Zend studio before but not had a lot of luck so am using Dreamwever for now which means that I simply echo variable contents as and when I need to debug. Sorry that this is unrelated but would appreciate any help on this. Thanks again!

Ah yess.. What an idiot I am. I want to try and put some of the common tasks that I perform regarding DB functions into a class which I can just create and use all over the place. The thing I am finding difficult to get used to is not having to specify data types and knowing what a function like: mysql_query mysql_fetch_array returns? Also when you declare a function within a class you dont say perhaps: ReturnType function NameOfFunction( param1, 2, 3 ) { return something; } You can simply do this: function NameOfFunction( param1, 2, 3 ) { return something; } So if I wanted to return the result of a mysql_fetch_array from a function that takes sql as a param and then use this in the caller of the func how woud I loop through the result that I would expect to be returned? Thanks for your help.

Hi, I have decided to try and write some OO php. I have a simple class with one function. I am trying to instantiate an object of that class using the new operator but get an error. Parse error: syntax error, unexpected T_OBJECT_OPERATOR in C:\wamp\www\School\addcourse.php on line 38 <?php $CDBController = new CMasterDataController; //THIS IS LINE 38 CMasterDataController->PerformQuery("SOME SQL HERE"); ?> I am including the file that contains this class (CMasterDataController) in this file (addcourse.php). The version of PHP i am using is 5.3.8. Does anybody know what I am missing? Thanks, Joe

Perfect thanks for your help. It was the DB that was messing it all up for me. The code posted now works perfectly.

hi, It was the DB field being stored as a Date. Changed to a string so will have a play now. Getting better results. Thanks for your help

I had the code like that at some point. the output of that was this: 2020-10-11 00:00:00?? What am I doing wrong? Thanks,

Nothing its declared and assigned in the same statement $DateAndTime = date('d-m-y', strtotime($DateAndTime)); All I want is the current date in the format DD-MM-YYYY followed by the time. This must be a simple task?

Hi, When I do this the result is a date of zeros? $DateAndTime = date('d-m-y', strtotime($DateAndTime)); All I want is a date in format of DD0MM-YYY and the Time in HH:MM::SS Any help would be great! I know it is basic, Thanks in advance

That makes sense I can see the good reason for this. Cheers

Excellent Thanks! I thought that the $conn would still be in scope? Joe

Hi, I have some code which works but when I created a function and call this same code it doesn't. The error I get is as follows: Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource in /home/fhlinux010/l/languageschoolsuk.com/user/htdocs/admin/email.php on line 42 Error retrieving schools The code function CreateSchoolCheckboxes() { echo '<div style="height:400px;width:400px;font:16px/26px Georgia, Garamond, Serif;overflow:scroll;">'; $querySchools = "SELECT * FROM school"; $result = mysql_query($querySchools, $conn) or die ("Error retrieving schools ".mysql_error()); while($row = mysql_fetch_array($result)) { $schoolname = $row['name']; echo '<input type="checkbox" name="school" value="'.$schoolname.'">'; echo $schoolname . '<br>'; } echo '</div>'; } Im sure that this is probably something simple but any suggestions would be much appreciated. Thanks, Joe