aashcool198

hey ! thanks a lot..it worked... But selected doesn't work in radio buttons for that what do i have to do?

can you show me by writing 1-2 lines please.

I have created a program in which user can create his profile and edit it. There is one dropdown box. <select name="dep" > <option value ="">Please Select</option> <option value ="Devlopers">Devlopers</option> <option value ="web">Web</option> </select> What i want that when the user clicks on edit profile. In edit page the value shown in combo-box should be same as what he filled in previously. using database (where the previous value is stored) how can i do this? Please help!

Thanks to all of you. you are wonderful!

Dates are stored in database in this format want that when i retrieve the data to my page the date should look like please help!

can please anyone help me with this?

yes.. basically i want to submit a form. The thing is little complex. I am making a form which looks like this: this form is result of a for loop retrieving data from database. that means .Net 1.0 .Net 2.1 all are stored in database.along with their levels (i.e. intermidate, expert etc.) Now when user clicks on submit i want to update that table i.e. the level corresponding to each skill will be updated. How can i do that.

hi.. I want to pass two arrays to the next page when next page is called. I don't think it can be done using sessions. please help.

can you post the part of the code you are using? will be easier to figure out.

This code gives me a table which stores a parent skill and its children skills in a row. like this This is just one row of table. This code would create as many columns as there are number of major skills but i want the major skill coming after MVC should automatically go in next row. Basically i don't want more than four columns. How can put this condition in code? <table align = "center" border = "1" cellspacing = "10"> <tr> <?php while($row = mysql_fetch_array($result)) { $skill_id = $row['skill_id']; $result2 = mysql_query("SELECT * FROM skills where skill_id = $skill_id && parent = 'm'"); while ($row2 = mysql_fetch_array($result2)) { $result1 = mysql_query("SELECT * FROM skills where parent = $skill_id"); ?> <td> <a href="#" class="menu1" "><b><?php echo $row2['skill'] ?></a><br> <div id="123" > <?php while ($row1 = mysql_fetch_array($result1)){ ?> <a href="#" class="submenu"><?php echo $row1['skill'] ?> </a> <?php } ?> </div> </td> <?php } } ?> </tr>

This code prints skills in hierarchical form means Parent skill its child skill its child skill its child skill Parent skill its child skill its child skill its child skill . . . . . so on.. Now the list can be any long. Now i want to insert one parent and its children on a specified place in my html page. basically i want one set to be shown in one column of html table and other set in next column. Can i use $html = file_get_contents("test.html"); $replaceThis = array( '{NAME}', '{JS}'); $replaceWith = array( $name,'<script language="JavaScript" >') $html = str_replace($replaceThis, $replaceWith, $html); echo $html; if yes then how for this dynamically changing content. <?php $conn = mysql_connect('localhost', 'root', '') or die(mysql_error()); mysql_select_db('Sumeru Skills', $conn); $result = mysql_query("SELECT * FROM person_skills"); while($row = mysql_fetch_array($result)) { $skill_id = $row['skill_id']; $result2 = mysql_query("SELECT * FROM skills where skill_id = $skill_id && parent = 'm'"); while ($row2 = mysql_fetch_array($result2)){ echo $row2['skill']." ".$row['lev_exp']."</br>"; } $result1 = mysql_query("SELECT * FROM skills where parent = $skill_id"); while ($row1 = mysql_fetch_array($result1)){ echo $row1['skill']."</br>"; } } ?>

thanks a lot! That was it!

hey thanks! it was a complete new thing you taught me..

No.. i want to publish the php script results on specified places in html page.

I have made a page in html. now i want to display things using php scrip. Do i have to echo whole html code? if yes than do i have to put backslash before every double quote character of html code?

I have made a page in html. now i want to display things using php scrip. Do i have to echo whole html code? if yes than do i have to put backslash before every double quote character of html code?

na ..it doesnt work...

well.. in any mail login when we enter incorrect password they show a message just below password field. how do we do that?

i have written a php login. Now when password or user name is wrong i want to display error at a certain position. How can i do it? i mean php script and html forms are on the same page but they are different. how can i send something from php code to html table?

don't put single quote mark while writing table or column's name e.g. INSERT INTO users (id, username, password.....etc)

please tell me how should i store password during registration and how should i match it during login?

49f68a5c84 is the registered password.. but at the time of login the password was 49f68a5c8493ec2c0bf489821c21fc3b if you see arefully the first digits a maching.. from where came the extra digits.

<?php // Open a connection to the DB $conn = mysql_connect('localhost', 'root', '') or die(mysql_error()); mysql_select_db('Sumeru Skills', $conn); // Start the session (DON'T FORGET!!) session_start(); // Check if user wants to login (GET info) if(isset($_GET['try'])) { // That's nice, user wants to login. But lets check if user has filled in all information If(empty($_POST['username']) OR empty($_POST['password'])) { // User hasn't filled it all in! echo 'Please fill in all the required fields!'; } else { // User filled it all in! // Make variables save with addslashes and md5 $username = $_POST['username']; $password = md5 ($_POST['password']); // Search for a combination $query = mysql_query("SELECT login_id FROM login WHERE username = '" . $username . "' AND password = '" . $password . "' ") or die(mysql_error()); // Save result list($user_id) = mysql_fetch_array($query); // If the user_id is empty no combination was found if(empty($user_id)) { echo 'No combination of username and password found.'; } else { // the user_id variable doesn't seem to be empty, so a combination was found! // Create new session, store the user id $_SESSION['user_id'] = $user_id; // Redirect to userpanel.php header('location: userpanel.php'); } } } ?> <form action="login.php?try=true" method="post"> Username: <input type="text" name="username"><br> <br> Password: <input type="password" name="password"><br> <br> <input type="submit" value="Login!"> </form>

The best thing is you right away start to read some sql tutorial. its very simple and won't take much time and then read about php and Mysql. Than will start the real fun of coding and Questions. Best wishes!

I have written a code to register users.It uses md5 before saving the password. $password = MD5($_POST['password']); But when user logs in i need to compare the password in database with password he writes. so i convert the password entered by user in hash $password = md5 ($_POST['password']); and now i compare this with passwords in database. But despite entering the correct password its not logging in. Please help!