Falanas

Jessica I believe I have used it (it is saved in '$correct_id'). What worries me is that this code is unable to execuite: [$placesql = "SELECT tourism_sites.*, towns.*, place.*, photos.* FROM tourism_sites, towns, place, photos WHERE tourism_sites.cat_id = towns.id AND towns.id = place.cat_id AND place.id = photos.id AND photos.image_id = " . $correct_id;] No any number e.g 1, 2, 3 etc is seen on the URL instead, it redirects me to BASE_DIR i.e header("Location: " . BASE_DIR); Is it because the id sent from index.php to the url does not meet the below conditions? <?php if(isset($_GET['id']) == TRUE) { if(is_numeric($_GET['id']) == FALSE) { header("Location: " . BASE_DIR); } $correct_id = $_GET['id']; } else { header("Location: " . BASE_DIR); } ?> I expected to see something like - details.php?id=1 or details.php?id=2 depending on the link clicked. What do you say? Thanks. =========================================================================================================== <?php if(isset($_GET['id']) == TRUE) { if(is_numeric($_GET['id']) == FALSE) { header("Location: " . BASE_DIR); } $correct_id = $_GET['id']; } else { header("Location: " . BASE_DIR); } ?> <!-- start page --> <div id="page"> <!-- start content --> <div id="content"> <div class="post"> <h2>Reservation</h2> <?php /* *this query links to variable . $sitenumrows['id'] of index.php to display further information about * $site2numrows['hotel_name'] */ $placesql = "SELECT tourism_sites.*, towns.*, place.*, photos.* FROM tourism_sites, towns, place, photos WHERE tourism_sites.cat_id = towns.id AND towns.id = place.cat_id AND place.id = photos.id AND photos.image_id = " . $correct_id; $placeresult = mysql_query($placesql); $placenumrow = mysql_num_rows($placeresult); if($placenumrow == 0){ echo "<h2 class = 'results'>There was a problem querrying database</h2>"; } else{ while ($placenumrow == mysql_fetch_assoc($placeresult)){ echo "<h2 class = 'title'>" . $placenumrow['town_name'] . "</p>"; } } ?>

Forgive me, I am only but a beginner in PHP & Mysql. I am trying to do a simple website but unfortunately I can see myself in a big mess: Getting 'id' from URL has been so hard for me and that's why I will appreciate if you could assist me. Here goes the code: index.php <?php //The first category (KENYA SAFARIS AS DEFAULT VALUE) of table - categoties $catsql = "SELECT * FROM categories WHERE categories.id = 1"; $catresult = mysql_query($catsql); while($catrow = mysql_fetch_assoc($catresult)){ echo "<h2> " .$catrow['cat_name'] . "</h2>"; //list of available sites to be visited (OF - TABLE tourism sites) $sitesql = "SELECT * FROM tourism_sites WHERE cat_id = " .$catrow['id'] . ";"; $siteresult = mysql_query($sitesql); $sitenumrows = mysql_num_rows($siteresult); if($sitenumrows==0){ echo "<h2 class = 'results'>No listed safari site</h2>"; } else{ while($sitenumrows = mysql_fetch_assoc($siteresult)){ echo "<ul>"; echo "<li><a href='#.php?id =" . $sitenumrows['id'] . "'>" . $sitenumrows['hotel_name'] . "</a></li>"; echo "</ul>"; } } echo "</li> "; } ?> <li> <?php //The second category (UGANDA AS DEFAULT VALUE) of categories table $cat2sql = "SELECT * FROM categories WHERE categories.id = 2"; $cat2result = mysql_query($cat2sql); while($cat2row = mysql_fetch_assoc($cat2result)){ echo "<h2>" .$cat2row['cat_name'] . "</h2>"; //list sites in Uganda to be visited $site2sql = "SELECT * FROM tourism_sites WHERE cat_id =" . $cat2row['id'] .";"; $site2result = mysql_query($site2sql); $site2numrows = mysql_num_rows($site2result); if($site2numrows==0){ echo "<h2 class = 'results'> No saved locations..! </h2>"; } else{ while($site2numrows = mysql_fetch_assoc($site2result)){ echo "<ul>"; echo "<li><a href='#.php?id =" . $site2numrows['id'] . "'>" . $site2numrows['hotel_name'] . "</a></li>"; echo "</ul>"; } } echo "</li>"; } ?> <?php if(isset($_GET['id']) == TRUE) { if(is_numeric($_GET['id']) == FALSE) { header("Location: " . BASE_DIR); } $correct_id = $_GET['id']; } else { header("Location: " . BASE_DIR); } ?> <!-- start page --> <div id="page"> <!-- start content --> <div id="content"> <div class="post"> <h2>Reservation</h2> <?php /* *this query links to variable . $sitenumrows['id'] of index.php to display further information about * $site2numrows['hotel_name'] */ $placesql = "SELECT tourism_sites.*, towns.*, place.*, photos.* FROM tourism_sites, towns, place, photos WHERE tourism_sites.cat_id = towns.id AND towns.id = place.cat_id AND place.id = photos.id AND photos.image_id = " . $correct_id; $placeresult = mysql_query($placesql); $placenumrow = mysql_num_rows($placeresult); if($placenumrow == 0){ echo "<h2 class = 'results'>There was a problem querrying database</h2>"; } else{ while ($placenumrow == mysql_fetch_assoc($placeresult)){ echo "<h2 class = 'title'>" . $placenumrow['town_name'] . "</p>"; } } ?> please help

If you areusing wampserver, go to wampserver icon on the taskbar - down there. Left-click on it. Click on config files then you will see php.ini. All the best.

I need help on how I can implement a drop down menu which queries mysql database and output the available data based on price range. This feature has been used here http://www.vebra.com - I will appreciate your help. $searchSQL = "SELECT * FROM simple_search WHERE"; // grab the search types. $types = array(); $types[] = isset($_GET['price'])?"`price` LIKE '%{$searchTermDB}%'":''; $types[] = isset($_GET['location'])?"`location` LIKE '%{$searchTermDB}%'":''; $types = array_filter($types, "removeEmpty"); // removes any item that was empty (not checked) if (count($types) < 1) $types[] = "`id` LIKE '%{$searchTermDB}%'"; // use the estate as a default search if none are checked $andOr = isset($_GET['matchall'])?'AND':'OR'; $searchSQL .= implode(" {$andOr} ", $types) . " ORDER BY `price`"; // order by price. $searchResult = mysql_query($searchSQL) or die("There was an error.<br/>" . mysql_error() . "<br />SQL Was: {$searchSQL}"); if (mysql_num_rows($searchResult) < 1) { $error[] = "The search term provided <i>{$searchTerms}</i> yielded no results."; }else { $results = array(); // the result array $i = 1; while ($row = mysql_fetch_assoc($searchResult)) { $results[] = "{$row['location']} <br/>{$row['image']}<br/>{$row['price']}"; $i++;