cbolson
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Hi, A quick and easy solution might be to have the complete image as the background (ie without the white strip down the middle) then put this white background (with padding) on the page contents. This could be done by wrapping the complete contents in a wrapper layer. This wrapper would have a style something like this: #wrapper{ width:900px; background-color:#FFF; padding:10px; margin:0px auto; } Then, in the html you would put : <div id="wrapper"> immedeatly after your <body> tag and close it again directly before the closing </body> tag. Chris
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auto loading data from a selected value on page load php ajax db
cbolson replied to chen2424's topic in PHP Coding Help
you need to add it to the page load (eg in the <body> tag). -
Yes, it looks like exactly the same problem. The register_globals applies to all variables passed, be it via POST or GET. For the he photos you need to use $_GET as they are being passed via the url. Chris
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auto loading data from a selected value on page load php ajax db
cbolson replied to chen2424's topic in PHP Coding Help
Hi, Personally, if you have the id of the user on page load, I would get the data using php rather than using ajax. Alternatively, you could call the javascript function on page load, passing it the id of the user: eg. (where 1=id of user) onload="showUser(1)" Chris -
Try changing $myServer = "127.0.0.1"; to $myServer = "localhost"; Chris
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Hi, your brevity, whilst appreciated, makes it rather difficult to know what is going wrong. Can you post the complete code for additionsuccessful.php? You say: "... "additionsuccessful.php" is displayed with only the first field completed." What do you mean by this? completed where? Are you saving this to a database? Have you tried printing out the POST values to see what your additionsuccessful.php is actually receiving? Try adding print_r($_POST); at the beginning of the page to show what the page is getting. Chris
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How about this: <div style="float:left;background-color:red;height:200px">Menu</div> <div style="float:right;clear:right;background-color:blue">Right</div> <div style="background-color:orange"> <span>Some text here</span> <span style="float:right;background-color:yellow;clear:none;">Right Floated Span</span> </div> <div style="float:left; clear:left;background-color:green">Left</div>
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Hi, With your code I am getting the "Left" column below the rest of the columns. Is this correct? Now, if I move this left-floated column to above the "Menu", it all seems to work correctly (ie your content spans are ligned up un the center column: <div> <div style="float:left; clear:left;background-color:green">Left</div> <div style="float:left;background-color:red;height:200px">Menu</div> <div style="float:right;clear:right;background-color:blue">Right</div> </div> <div style="background-color:orange"> <span>Some text here</span> <span style="float:right;background-color:yellow;clear:none;">Right Floated Span</span> <span style="clear:both;"></span> </div> However I am not totally convinced that that is what you want to do. Anyway, the thing is that the "offending" line is that left-floated layer. I hope that is of some help Chris
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well, can't answer that one for you If it is on wamp I presume that means that you created the database so therefore you should have the ability to go in and modify the settings, don't you? I'm afraid that servers is not my area. sorry Chris
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Hi, you are missing the closing ";" at the end of these lines: $myusername = $_POST['myusername'] $mypassword = $_POST['mypassword'] Chris EDIT - you are also missing one at the end of this line further down: echo "Wrong Username or password"
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Hi, It is opening all the hidden elements because that is what you are telling it to do. In the same way that you have used $('.forumPaster').hide(); to hide them all, you are using the same code when you want to open just one. Either you need to address each hidden layer individually by using a unique id, or you could try to get the "next" layer after the button. I am not familar with jquery, personally preferring mootools, but you could try something like this: $(document).ready(function() { $(".forumPaster").hide(); $(".ForumPasteButton:button").bind('click', function() { this.next(".forumPaster'").toggle(); }); }); As I say, I don't know jquery code that well but this, or an adaption of this should work. Chris
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[SOLVED] Setting condidtions for an input box
cbolson replied to uwictech's topic in PHP Coding Help
I would say that you have 3 choices: 1. - Use javascript to control the format and data type (ie numeric only) 2. - Alternatively you could provide 4 text boxes and set the maxlength on each one accordingly then, when the form is posted, join them up with php. However, you would still need some javascript if you want to only allow them to input numbers. 3. - Finally this could be checked and controlled by php when the form is posted. However, this means that you will have to show the form again if the number is incorrect and prefill all the fields with the data that the user has introduced. Chris -
OK, I have checked your site out and the page is working (ie no php errors)so it is not what I said though it would be a good idea to make that change anyway. So, it is probably due to the fact that you aren't referring to the posted variable correctly. The code uses the variable name directly "assuming" that php know what they are (again, a server side configuration setting) For example you have this: if ($Submit) That should be : if (isset($_POST["Submit"]) Likewise for all the variables within that conditioned section that is supposed to be reading the posted values. Chris
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Hi there, First thing that I noticed is that the code uses the deprecated php short tags. ie <? rather than the (now) correct <?php Newer versions of php have the short tags turned off. Try changing all them and see if it works. Chris
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Good news! Glad to be able to help