Jump to content

Joshua4550

Members
 View Profile  See their activity

  • Posts

    148

  • Joined

  • Last visited

    Never

 Content Type 

Everything posted by Joshua4550

  1. Joshua4550
    Thx. How would I do it the way I was trying? Sure I did this before, but forgot how.
  2. Joshua4550
    Well here it is, I have a SELECT object, and a TEXT object. I checked them both with a simple alert to see if they worked, and they did.. but he next part didn't. Please help. var answer = parseInt(input.value, base); alert(input.value + " " + answer); input = TEXT object. What this code does is: If i type 5 into the TEXT object, the alert will say that the input.value is 5 but the answer variable still says not a number (NaN) Oh and the base variable was 2 at this time. Please help! Thanks!
  3. Joshua4550
    No replies now it was moved to Javascript section
  4. Joshua4550
    Well the code posted by priti earlier works, using the same flash detection function, so I cant see how that'd make it not work. And I used the function, still nothin'... <script type="text/javascript"> (function() { if (!FlashDetect.versionAtLeast() { // Dont have flash 8 or later var content = "<b><font color=#FF0000>HOME, TUTORIALS<br /> Install flash 8 or later to view the proper navigation toolbar! </font></b>"; document.write(content); } else { var content = "<ul id=\"menu\" class=\"menu\"> <li> <a href=\"/#\"> <img src=\"images/home-small.png\" class=\"small\" alt=\"HOME\"/> <img src=\"images/home.png\" class=\"big\" alt=\"HOME\"/> <span class=\"title\">Home</span> </a> </li> <li> <a href=\"javascript:alert()\"> <img src=\"images/tutorials-small.png\" class=\"small\" alt=\"TUTORIALS\"/> <img src=\"images/tutorials.png\" class=\"big\" alt=\"TUTORIALS\"/> <span class=\"title\">Tutorials</span> </a> </li> </ul>"; document.write(content); } }) () </script>
  5. Joshua4550
    <div id="main"> <script type="text/javascript"> if (!FlashDetect.versionAtLeast() { // Dont have flash 8 or later var content = "<b><font color=#FF0000>HOME, TUTORIALS<br /> Install flash 8 or later to view the proper navigation toolbar! </font></b>"; document.write(content); } else { var content = "<ul id=\"menu\" class=\"menu\"> <li> <a href=\"/#\"> <img src=\"images/home-small.png\" class=\"small\" alt=\"HOME\"/> <img src=\"images/home.png\" class=\"big\" alt=\"HOME\"/> <span class=\"title\">Home</span> </a> </li> <li> <a href=\"javascript:alert()\"> <img src=\"images/tutorials-small.png\" class=\"small\" alt=\"TUTORIALS\"/> <img src=\"images/tutorials.png\" class=\"big\" alt=\"TUTORIALS\"/> <span class=\"title\">Tutorials</span> </a> </li> </ul>"; document.write(content); } </script> </div> This would all be fine, but it still doesnt actually echo anything on the page.
  6. Joshua4550
    Therefore my script should execute the javascript script when it echos the string that contains the script, and then javascript should echo (document.write()) the infomation i wanted. This is not working , because with my script it just doesnt echo anything, but with the script that priti posted, it echos. Please explain what's wrong with my code.
  7. Joshua4550
    Kk please help me out here, i'm stressin lol. Heres my actual code, it won't fuckin' echo anything $menu = '<script type="text/javascript"> if (!FlashDetect.versionAtLeast() { // Dont have flash 8 or later var content = "<b><font color=#FF0000>HOME, TUTORIALS<br /> Install flash 8 or later to view the proper navigation toolbar! </font></b>"; document.write(content); } else { var content = "<ul id=\"menu\" class=\"menu\"> <li> <a href=\"/#\"> <img src=\"images/home-small.png\" class=\"small\" alt=\"HOME\"/> <img src=\"images/home.png\" class=\"big\" alt=\"HOME\"/> <span class=\"title\">Home</span> </a> </li> <li> <a href=\"javascript:alert()\"> <img src=\"images/tutorials-small.png\" class=\"small\" alt=\"TUTORIALS\"/> <img src=\"images/tutorials.png\" class=\"big\" alt=\"TUTORIALS\"/> <span class=\"title\">Tutorials</span> </a> </li> </ul>"; document.write(content); } </script>'; ... echo ' <body> <noscript class="ERROR">Please enable JavaScript</noscript> <div id="main"> ' . $menu . ' </div> </body> '; HELP!
  8. Joshua4550
    Oh, it seems to work, but when i try doing ordered lists, it doesnt work :@
  9. Joshua4550
    Thanks, but may I ask why javascript alone wont write it onto my page? Because it works as so on the example by adobe. Thanks
  10. Joshua4550
    I looked at the exampe and it was pretty much what I put, yet mine doesnt echo? any idea why? $menu = ' <script type="text/javascript"> if (!FlashDetect.versionAtLeast() { // Dont have flash 8 or later var content = \' <b><font color=#FF0000> Install flash 8 or later! </font></b> \'; document.write(content); } else { var content = \' <p>Hi, you have flash 8 or later.</p> \'; document.write(content); } </script> '; echo ' <body> <noscript class="ERROR">Please enable JavaScript</noscript> <div id="main"> ' . $menu . ' </div> </body> '; It doesnt echo though. Argh, please help xD
  11. Joshua4550
    Hm. I suppose it could be. Would I just do this.. $flashtest = ' <script type="text/javascript"> if (!FlashDetect.versionAtLeast() { // Dont have flash 8 or later document.write("U need flash 8"); } else { document.write("U have flash 8"); } </script> '; echo $flashtest; ?
  12. Joshua4550
    A way to check whether they have flash 8 or later (which evidently can be done in javascript), but then i need to store the values in a serverside variable, so I can use them in php like you saw in the first post. I'm not sure how i'd go about doing this, especially if it needs ajax, because 'm VERY new to ajax too.
  13. Joshua4550
    Oh I see. So what's the best way of doing what i'm trying to achieve, do you think?
  14. Joshua4550
    Ok so basically what i've done, is find the screen size using javascript, assigned it to a variable, and this must work because when i echo it it shows the proper size on the page. I also did this with whether they have flash 8 or later, or not. should set the var to 1 if so, or 0 if not. Again, when i echo it, it shows the right number, but when i ask php if its 1, it doesnt work? Heres the codes (Not full, but the codes appropriate)... //$has_flash = 1 or 0 $has_flash = ' <script type="text/javascript"> if (!FlashDetect.versionAtLeast() { // Dont have flash 8 or later document.write(0); } else { document.write(1); } </script> '; Heres the code to echo it (works apparently) <p>has flash: ' . $has_flash . '</p> But HERES THE PROBLEM. When I do the following, it never works out. if ($has_flash == 1) { $menu = ' HAI U HAV FLASH '; } else { $menu = 'U DONT HAV FLASH< I R SAD'; } echo $menu; It always goes for the else statement. WHY? ALL help appreciated. Thanks alot
  15. Joshua4550
    Just realised that. Thank you very much.
  16. Joshua4550
    I'm gonna cut it short, because this is really starting to ... me off. The following code will not work. $file = "alltime.txt"; $handle = fopen($file, 'r'); The reason for this not working? Warning: fopen(alltime.txt) [function.fopen]: failed to open stream: No such file or directory in /home/*myuser*/public_html/*mysite*.com/Sources/Statistics.inc on line 4 The file is in the same directory as the file running the code. The files permissions are set for the owner to read, write, and execute. Why is it saying it does not exist?
  17. Joshua4550
    The code is fine, as mentioned above; However, you should make sure that the file permissions are set appropriatly.
  18. Joshua4550
    Or just define which values are being inserted with the query, for example: $query = "INSERT INTO `scores_ast` (`score`, `name`) VALUES ('$name','$score')";
  19. Joshua4550
    Basically, i need to convert a String into an int, then convert the int back to a String (making it be the same). Is this possible? So i could have like "The car drove under the bridge". Then convert it to an int. Then convert the int back to a String. The String still equals "The car drove under the bridge". Please post ASAP
  20. Joshua4550
    My bad, it does. Thanks alot again, mate.
  21. Joshua4550
    Still seems to not work? (I changed the variable which the function returns to not confuse myself, but it doesn't work still?) <?php $Menu_Query = mysql_query("SELECT * FROM `Sites_Menus` WHERE `site`='" . $SITENAME . "'") or die(mysql_error()); $Menu = mysql_fetch_array($Menu_Query); function NewCat($Menu, $category, $links, $urls) { //also passed $Menu $Cat = explode(",", $Menu[$category]); $string = ""; if ($Cat[0] == "true") { if ($Cat[2] == "true") { $fieldset_class = "menu gold"; } else { $fieldset_class = "menu"; } $string .= ' <fieldset class="' . $fieldset_class . '"> <legend>' . $Cat[1] . '</legend> <ul> '; $link = explode("^", $Menu[$links]); $url = explode("^", $Menu[$urls]); for ($i = 0; $i < count($link); $i++) { if ($link[$i] == null || empty($link[$i]) || $link[$i] == " " || $url[$i] == null || empty($url[$i]) || $url[$i]==" ") { continue; } $string .= ' <li><a href="' . $url[$i] . '">' . $link[$i] . '</a></li> '; } $string .= ' </ul> </fieldset> '; } return $string; } $MENUS .= NewCat($Menu, 'categories1', 'links1', 'urls1'); ?>
  22. Joshua4550
    Oh, i understand now.. I'm just so used to Java, so i'm guessing PHP functions are equivelant to String methods in Java, you have to return a value. So to call that function, i would do: $MENUS .= NewCat('categories1', 'links1', 'urls1'); (Since the variable $MENUS is in the main file which is why i was trying to use it, because i was thinking about it as if it were the same as a void in Java. So that's how i call the function, if i understand correctly? EDIT: Thanks alot, i now understand. Thanks buddy
  23. Joshua4550
    Okay, i'm a newb to PHP, so please bare with me.... I have made a function which will set a variable depending on other variables and database data. I'm not sure whether in PHP this should even work, so if i'm TOTALLY wrong then just tell me.. okay, here's my original code that worked... // Allow the front page to display 15 recent news entries $NEWS_QUERY = 'SELECT * FROM `Sites_News` WHERE `site`=\'' . $SITENAME . '\' ORDER BY `ID` DESC LIMIT 15'; $Menu_Query = mysql_query("SELECT * FROM `Sites_Menus` WHERE `site`='" . $SITENAME . "'") or die(mysql_error()); $Menu = mysql_fetch_array($Menu_Query); $Cat = explode(",", $Menu['category1']); if ($Cat[0] == "true") { if ($Cat[2] == "true") { $fieldset_class = "menu gold"; } else { $fieldset_class = "menu"; } $MENUS .= ' <fieldset class="' . $fieldset_class . '"> <legend>' . $Cat[1] . '</legend> <ul> '; $link = explode("^", $Menu['links1']); $url = explode("^", $Menu['urls1']); for ($i = 0; $i < count($link); $i++) { if ($link[$i] == null || empty($link[$i]) || $link[$i] == " " || $url[$i] == null || empty($url[$i]) || $url[$i]==" ") { continue; } $MENUS .= ' <li><a href="' . $url[$i] . '">' . $link[$i] . '</a></li> '; } $MENUS .= ' </ul> </fieldset> '; } Now here's when i tried to put it into a function, so i could use it later on.. (This doesn't work, it just doesn't work for some reason? :S) // Allow the front page to display 15 recent news entries $NEWS_QUERY = 'SELECT * FROM `Sites_News` WHERE `site`=\'' . $SITENAME . '\' ORDER BY `ID` DESC LIMIT 15'; $Menu_Query = mysql_query("SELECT * FROM `Sites_Menus` WHERE `site`='" . $SITENAME . "'") or die(mysql_error()); $Menu = mysql_fetch_array($Menu_Query); function NewCat($category, $links, $urls) { $Cat = explode(",", $Menu[$category]); if ($Cat[0] == "true") { if ($Cat[2] == "true") { $fieldset_class = "menu gold"; } else { $fieldset_class = "menu"; } $MENUS .= ' <fieldset class="' . $fieldset_class . '"> <legend>' . $Cat[1] . '</legend> <ul> '; $link = explode("^", $Menu[$links]); $url = explode("^", $Menu[$urls]); for ($i = 0; $i < count($link); $i++) { if ($link[$i] == null || empty($link[$i]) || $link[$i] == " " || $url[$i] == null || empty($url[$i]) || $url[$i]==" ") { continue; } $MENUS .= ' <li><a href="' . $url[$i] . '">' . $link[$i] . '</a></li> '; } $MENUS .= ' </ul> </fieldset> '; } } Just to be clear... the database queries that appear at the very top of the code DO WORK. Anyone got any idea why my function don't work? Thanks alot!
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.