marky83
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Thanks a lot, going to see if I can get it to work later today.
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Hi! I have a SQL database with information about albums and track (music). This is where the user inputs a search term(entersearch.php): <form name="form" action="displaysearchalbum.php" method="get"> <input type="text" name="getsearch" /> <input type="submit" name="Submit" value="search album" /> </form> <br /> <h2>Search for track</h2> <form name="form" action="displaysearchtrack.php" method="get"> <input type="text" name="getsearch2" /> <input type="submit" name="submit2" value="search track" /> </form> And this is where the search result is displayed with links to a pages with more information about the album the user is interested in. <?php // Get the search variable from URL $var = @$_GET['getsearch'] ; $trimmed = trim($var); //trim whitespace from the stored variable // rows to return $limit=20; // check for an empty string and display a message. if ($trimmed == "") { echo "<p>Please enter a search...</p>"; exit; } // check for a search parameter if (!isset($var)) { echo "<p>We dont seem to have a search parameter!</p>"; exit; } //connect to your database mysql_connect("xxx","xxx","xxx"); //(host, username, password) //specify database mysql_select_db("xxx") or die("Unable to select database"); //select which database we're using // Build SQL Query $result = mysql_query("SELECT albumid, albumname FROM album WHERE albumname like '%$trimmed%'"); //$query = "SELECT albumname FROM album WHERE albumname='$trimmed'"; while ($row = mysql_fetch_array($result)) { echo '<a href="albuminfo.php?albumid=' . $row[0] . '">' . $row[1] . '</a>'; echo "<p></p>"; } ?> My problem is that I don't know how to transfer the information from displaysearchalbum.php to albuminfo.php about which album the information is going to be displayed. Preferably I would have a variable in albuminfo.php which contains the albumid in interest. I am a novice in php but think that the code I have so far written is working. Any ideas about necessary changes in the code I wrote or what kind of code I need for albuminfo.php would be helpful. I have not yet written any code for albuminfo.php because I am not quite sure how to.
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I have a MYSQL-database. Table: album with columns: albumname, albumid Table: track with columns: trackname, trackid, genreid Table: genre with columns: genrename, genreid Table: albumtrack with columns: albumid, trackid Table: albumgenre with columns: albumid, genreid I made a search from like this: <body> <h2>Search for album</h2> <form name="form" action="displaysearchalbum.php" method="get"> <input type="text" name="getsearch" /> <input type="submit" name="Submit" value="search album" /> </form> <br /> <h2>Search for track</h2> <form name="form" action="displaysearchtrack.php" method="get"> <input type="text" name="getsearch2" /> <input type="submit" name="submit2" value="search track" /> </form> </body> I am a bit new to php and mysql and have problem getting displaysearchalbum.php to work. The first part of the code seems fine but I'm not sure how to display the result of the SQL-query. Any tips? <?php // Get the search variable from URL $var = @$_GET['getsearch'] ; $trimmed = trim($var); //trim whitespace from the stored variable // rows to return $limit=20; // check for an empty string and display a message. if ($trimmed == "") { echo "<p>Please enter a search...</p>"; exit; } // check for a search parameter if (!isset($var)) { echo "<p>We dont seem to have a search parameter!</p>"; exit; } //connect to your database mysql_connect("x","x","x"); //(host, username, password) //specify database mysql_select_db("cpm08010") or die("Unable to select database"); // Build SQL Query $query = "SELECT albumname FROM album WHERE albumname='$trimmed'"; Best Regards