[preg_replace]

I have strange requirements like these. hope many have answers.

[url http://www.gmail.com]Gmail[/url] should give Gmail which should point to http://www.gmail.com.

 

And also if I type http://www.gmail.com it should be a link.

The first one I could solve easily. but I need that in combination.

 

 

 

[File names on a different server]

Everything that http://www.somedomain.com/images has.

 

But after some time I spent with this, I found out that I can get file names from database! Don't say I wasted your time... I learnt a lot... Thank you..

 

I was believing every image that was other server needs to be displayed.. But it was not the case.. there is some consistent data in our table!! 

 

Thanks every one..

[File names on a different server]

[pre]Some of the directory functions make work already with URL locations.[/pre]

 

Can any one tell me more about this.

 

Thanks a ton.

 

file_get_contents() worked!! So I can use , preg_match_all  right? Is there a better way?

Any one see any downside of this?

 

[File names on a different server]

Thanks. Will re think about it..

[File names on a different server]

Thanks again..

 

I am very poor in explaining though.. I will try again.

Users can just see my website. So if they visit say home page of my site, I need to show list of images with their corresponding image name. So those images are in a different web server.

 

So the code needs to be in my website server.

 

 

[File names on a different server]

Thanks for your reply.

 

I need to fetch the image names. Its also a webserver.

[File names on a different server]

Hi,

 

I am a bit new to php and need some help. This is my situation.

 

I have lots of images on a different sever. And my website is running on a different server. So my code on my website should get the image name from that server and should display it.

 

Can any one help me? Thanks a lot.

 

 

 

[preg_replace]

Thanks you.. I searched and I think I almost found what I need.

 

$replaced = [url http://www.example.com]Test[/url]

 

$replaced = preg_replace ('/\[url(.*?)\](.*?)\[\/url\]/is','<a href="$1">$2</a>', $replaced);

 

Thanks again. I haven't tested fully but this helps a lot..

[preg_replace]

Hello Everyone,

 

I am a bit new to php already loving it.

 

I am stuck in this can any one help me in this. I am having a pattern like this

 

[url http://www.example.com]Test[/url]

 

I need it to replace like this <a href="http://www.example.com">Test</a>

 

Any help is really appreciated. Thanks.