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matthew9090

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Posts posted by matthew9090

    move_uploaded_file not working

    in PHP Coding Help

    Posted

    <?php

        error_reporting(E_ALL);

     

        $name = $_POST['name'];

        $file = $_POST['file'];

     

    $moved = move_uploaded_file($_POST['file']['tmp_name'], "upload/");

    if ($moved) {

    echo "moved!";

    }

    else {

    echo "did not move!";

        }

        echo $name . "<br />" . $file . "<p>";

     

    if (strlen($name)>10)

    {

      echo "name too long";

    }

    else

    {

     

    //private stuff

    show flash file from database

    in PHP Coding Help

    Posted

    I have got a flash file that is stored in the database. So I fetch it and put it in a variable then put the variable in the flash embed code where the src is but the flash comes up blank.

     

    $file = "SELECT * FROM table WHERE column='$name'";
$file2 = mysql_query($sqlfile);
        $file3 = @mysql_fetch_assoc($file2);
$file4 = $file3['gamefile'];
  //skip some code to html embed section
<object width='550' height='400'>
<param name='movie' value='valuename'>
<embed src='$file4' width='550' height='400'>
</embed>
</object>

   

     

    then the page comes up with a white box which when you hover over it says 'file not loaded'.

    php pagination - hightlight current page

    in PHP Coding Help

    Posted

    here is the full code:

     

    <?php

//get data
$button = $_GET['submit'];
$search = $_GET['search'];


$s = $_GET['s'];
if (!$s)
$s = 0;


$e = 10;


$next = $s + $e;
$prev = $s - $e;




if (strlen($search)<=2)
  echo "Must be greater then 3 chars";
else
{
  echo "<br /><table><tr><td><a href = index.php></a></td><td><form action='search.php' method='GET'><a href ='index.php'><img src='logo.png' align='top' height='28' width='60'></img></a><input type='text' value='' size='50' name='search' value='$search'> <input type='submit' name='submit' value='Search'></form></td></tr></table>";
  
  //connect to database
  mysql_connect("localhost","root","");
  mysql_select_db("test");
   
   //explode out search term
   $search_exploded = explode(" ",$search);
   
   foreach($search_exploded as $search_each)
   {
   
        //construct query
    $x++;
    if ($x==1)
     $construct .= "keywords LIKE '%$search_each%'";
    else
     $construct .= " OR keywords LIKE '%$search_each%'";
   
   }
   
  //echo outconstruct
  $constructx = "SELECT * FROM search WHERE $construct";
  
  $construct = "SELECT * FROM search WHERE $construct LIMIT $s,$e";
  $run = mysql_query($constructx);
  
  $foundnum = mysql_num_rows($run);
   
  $run_two = mysql_query("$construct");
  
  if ($foundnum==0)
   echo "No results found for <b>$search</b>";
  else
  {
   echo "<table bgcolor='#0000FF' width='100%' height='1px'><br /></table><table bgcolor='#f0f7f9' width='100%' height='10px'><tr><td><div align='right'><b>$foundnum</b> result(s) found for <b>$search.</b></div></td></tr></table><p>";
   
   while ($runrows = mysql_fetch_assoc($run_two))
   {
    //get data
   $title = $runrows['title'];
   $desc = $runrows['description'];
   $url = $runrows['url'];
   
   echo "<table width='300px'>
   <h4><a href='http://$url'><b>$title</b></a><br />
   $desc<br>
   <font color='00CC00'>$url</font></table></h4>
   ";
   }
?>

<table width='100%'>
<tr>
<td>
<div align="center">

<?php
if (!$s<=0)
echo "<a href='search.php?search=$search&s=$prev'>Prev</a>";

$i =1; 
for ($x=0;$x<$foundnum;$x=$x+$e)
{

echo " <a href='search.php?search=$search&s=$x'>$i</a> ";


$i++;


}

if ($s<$foundnum-$e)
  echo "<a href='search.php?search=$search&s=$next'>Next</a>";

  
}
}  

?>
</div>
</td>
</tr>
</table>

    str_replace with array

    in PHP Coding Help

    Posted

    you could use the implode function to turn it into string then str_replace then explode into array again.

     

    e.g

     

    <?php

$array = //array
implode(" " . $array);
str_replace($replace, $array);
explode(" " . $array);

?>

     

    it should work, just wrote it of the top of my head.

     

    preg_match

    in PHP Coding Help

    Posted

    in my site search some of the results come out still with html. i have used the strip tags function but how would i use the preg_match function to get rid of the "> still left over?

    website suggestions

    in PHP Coding Help

    Posted

    i have made my own website suggestion box but when i start typing in on my websites search box google chrome automatically suggests other words and you can't see underneath. I don't want this to happen to other people viewing my website. Is there any sort of code i an put on my website to stop this?

    find a word within text and put it in bold

    in PHP Coding Help

    Posted

    code so far

    <?php include('simple_html_dom.php'); ?>
<script type="text/javascript">
function redirect(){
window.location.href = "index.html";
}
</script>
<?php 
$s = $_GET["s"];
if ($s == null) 
    echo "you have not searched for anything" . '<script type="text/javascript">window.onload = setTimeout("redirect()", 3000);</script>';
else
    echo "you searched for $s<hr>";


$urls[1] = 'http://url.com/';
$urls[2] = 'http://url2.com';


foreach ($urls as $url)
{
   $html = file_get_html($url);
   strip_tags($html);
   preg_match("/<body>(.*)<\/body>/s", $html, $body);
   preg_match('@^(?:http://)?([^/]+)@i', $html, $matches);
   $htmls_split = split('<', $body[1]);
   
   foreach ($htmls_split as $line)
   {
      if (preg_match("/$s.*/", $line, $matches))
      {
    if (strlen($s) == 0)
	    die();
	else
	    str_replace($s, "<b>$s</b>", $matches[0]);
            echo "<p>$matches[0]";		
      }
   }
}

?>

     

    the str_replace doesn't do anything at the moment.  :'(

     

    please help!

    find a word within text and put it in bold

    in PHP Coding Help

    Posted

    i am making a search engine to search my site and the code is going well but i don't know how to find your search within the results and put it in bold (like google does). I use a thing called http://simplehtmldom.sourceforge.net/ for getting the html of my website.

     

    <?php include('simple_html_dom.php'); ?>
<?php 

$s = $_GET["s"];
if ($s == null) 
    echo "you have not searched for anything";
else
    echo "you searched for $s<hr>";

$urls[0] = 'http://url.com/';
$urls[1] = 'http://url2.com';

foreach ($urls as $url)
{
   $html = file_get_html($url);
   strip_tags($html);
   preg_match("/<body>(.*)<\/body>/s", $html, $body);
   $htmls_split = split('<', $body[1]);
   
   foreach ($htmls_split as $line)
   {
      if (preg_match("/$s.*/", $line, $matches))
      {
         echo "<p>$matches[0]";
      }
   }
}

?>

    php web spider/bot

    in PHP Coding Help

    Posted

    i am making a search engine and i need help because i need it so you submit your url then it automatically scrolls it for the description and keywords then puts it in the database. my html code:

     

    <form action="submit_url.php" method="get">
<input type="text" name="url" value="url" />
<input type="submit" name="submit" value="submit" />
</form>

     

    php code so far:

     

    <html>
<head>
<title>submitting url: <?php $url = $_GET['url']; echo $url; ?></title>
<link href="style.css" rel="stylesheet" type="text/css" />
</head>
<body>

<?php
echo "Submitting <b>$url</b>";

$url = fopen("http://knexideas.co.cc", "r") or exit("Unable to open");
while (!feof($url))
  {
  fgetc($url);
  }
fclose($url);


?>
</body>
</html>

     

    all it does is reads the website if you put 'echo $url' at the bottom it just reads and prints the web page.

    mysql image pagination issues

    in PHP Coding Help

    Posted

    it comes up with this in the database:

     

     

    id name       file_name                         type_of_file

    1 file               [bLOB - 11 Bytes]         Array[type]

    2 another file [bLOB - 11 Bytes]         Array[type]

     

    the insert script:

    <?php
//connection stuff
$sql="INSERT INTO upload (name, file_name, type_of_file, size)
VALUES
('$_POST[name]','$_FILES[file][name]','$_FILES[file][type]')";

if (!mysql_query($sql,$con))
  {
  die('Error: ' . mysql_error());
  }
echo "Idea name: " . $_POST["name"] . "<br />";  
echo "Upload: " . $_FILES["file"]["name"] . "<br />";
echo "Type: " . $_FILES["file"]["type"] . "<br />";
echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />";
echo "<b>Upload sucessful!</b>";

mysql_close($con)
?>

     

     

    Form information doesn't transfer over to php file

    in PHP Coding Help

    Posted

    im not a proffesional but if you want to transfer it over i think you have to create a seperate page called calender and a page with the form on the the data goes to the calender.

     

    e.g:

     

    form.html

     

    <form action="myform.php" method="post">

     

     

    myform.php

     

    //code here

     

    but i think there is another way to do it on the same page:

     

    <form action="<? echo $_SERVER['PHP_SELF']; ?>" method="post"  ENCTYPE="multipart/form-data">

     

    //code down here

     

    or something like that

     

     

    mysql image pagination issues

    in PHP Coding Help

    Posted

    i've found a pagination script of the internet but the image comes up blank. I've stored it in a largeblob. When i check the html it says 'array[name]' as the image pz help me heres the code:

    <?php

//connection stuff here

$page = 1;
if ( isset( $_GET['page'] ) ) {
$page = (int) $_GET['page'];
}

$query = mysql_query("SELECT COUNT(*) FROM `upload`",$link);
list( $total ) = mysql_fetch_row( $query );
$total = ceil( $total / $perPage );
$start = ( $perPage * ( $page - 1 ) );
$limit = '';
$show = true;
if ( $total > 1 ) {
$limit = " LIMIT {$start}, {$perPage}";
}
else {
$show = false;
}

$query = mysql_query("SELECT * FROM `upload` ORDER BY `id`{$limit}");
while( $row = mysql_fetch_assoc( $query ) ) {
echo "<img src=\"{$row['file_name']}\" alt=\"{$row['name']}\" title=\"{$row['name']}\" />";
}

if ( $show ) {
$prev = $page - 1;
$next = $page + 1;
if ( $prev > 0 ) {
	echo "<a href=\"{$thispage}?page={$prev}\">[PREV]</a>";
}
if ( $next < $total ) {
	echo "<a href=\"{$thispage}?page={$next}\">[NEXT]</a>";
}
}

?>

     

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