mrakodol

Tnx. My fault. I found in only one file <? and when I replace that with <?php code begin work! Thank you very much! When I preparing code for sent to you I wouldn't found such a mistake. Thank you very much [/code]

Here is result of my phpinfo <?php phpinfo(); ?> There is no result when I type: <? phpinfo(); ?> And I replace all <? with <?php and web browser continuous refreshing page. I now written some code in Zend Framework and that code work perfectly. [attachment deleted by admin]

Hi all, How to make that show to user one form, and when he type valid value refer to other form, and when user type valid value save that values to database? For ex., I try that code, but it code didn't do nothing. Without other form he wok properly, but if I give here a other form, nothing is going to work. $form1 = new Form_FirstForm(); $this->view->form=$form1; if($this->getRequest()->isPost()){ if($form1->isValid($_POST)){ $data1 = $form1->getValues(); $this->view->form=$form2; if($this->getRequest()->isPost()){ if($form2->isValid($_POST)){ $data2 = $form2->getValues(); }}}} I use that for making pool module. In first form I enter a question and number of answers and in other form i need to enter the number of which depends on the answers of either entering the number on the previous form. For example: I enter 5 in first form and I must enter 5 answers in other form... This can be resolved by using a jQuery. Can somebody give me a example a code.Please.

Hello everyone. I have a problem with the local server (localhost connection). Until yesterday I used an old version of XAMPP's (version 1.6.4 with PHP 5.2.4) and last night I finally found the time to install XAMPP 1.7.3 with PHP 5.3.1. But some things that I worked under the old XAMPP-om, which are working perfectly now no longer work, and I do not know why. Please find enclosed pics that were under php4 and that now works. So I wonder where is the error and where possible errors. Also under my new PHP-om non-stop is done refresh the page and print portions of the code (as you can see from the picture). :shrug: I am enable short tags support in php.ini. Thank you. PHP 5.3.1 PHP 5.2.4

Hi all, I have a problem with javaScript.Script must add text box and select box(with values from database) when click on Add element.The script work fine without select box but I need textbox and select box. db.php-is settings for connection on database sql.text-is mysql data table Help me please. [attachment deleted by admin]