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Posts
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Everything posted by techker
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hey guys i made a script for my boddy and it is only used on on PC now i have multiple little scripts to run and i don't want to make a login on each..is it possible to allow access only with his ip?
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well it goes to a check page and it echo's the user's name and and appointment date and if there is a note in his file it shows an icon.
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all the scripts i find is for triggering sound thru a button not with an event?and i would need to mix it with php? like select * from table WHERE member_id=$id if date ==today alert sound....
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know anything about this? http://www.schillmania.com/projects/soundmanager2b1/#requirements
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so i will check for javascript thx
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its one machine made for the scanner only.so your saying i cant use any html or serverside for this?
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in php but since it has something to do with mysql since im getting the info.?sorry if not.
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hey guys im doing a script for when a member scans his card(barcode0it gets his info in a databse .now it's a membership information, is it possible that if the membership is expired it sound an alarm ?
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so i fanaly found one that maybe has potential!lol xml and ajax. it works good but if i add another on the page and changed the get page to fincity2 and the divtag to city2 the both work but when i select the second one it changes the first one. i will barke down the code: the xml <script> function getXMLHTTP() { //fuction to return the xml http object var xmlhttp=false; try{ xmlhttp=new XMLHttpRequest(); } catch(e) { try{ xmlhttp= new ActiveXObject("Microsoft.XMLHTTP"); } catch(e){ try{ xmlhttp = new ActiveXObject("Msxml2.XMLHTTP"); } catch(e1){ xmlhttp=false; } } } return xmlhttp; } function getCity(strURL) { var req = getXMLHTTP(); if (req) { req.onreadystatechange = function() { if (req.readyState == 4) { // only if "OK" if (req.status == 200) { document.getElementById('citydiv').innerHTML=req.responseText; ( } else { alert("There was a problem while using XMLHTTP:\n" + req.statusText); } } } req.open("GET", strURL, true); req.send(null); } } </script> [code] and the form [code=php:0] <form method="post" action="" name="form1"> <table width="60%" border="0" cellspacing="0" cellpadding="0"> <tr> <td width="150">Country</td> <td width="150"><select name="country" onChange="getCity('findcity.php?country='+this.value)"> <option value="">Select Country</option> <option value="ABS">ABS</option> <option value="ARMS">ARMS</option> <option value="LEGS">LEGS</option> <option value="SHOULDERS">SHOULDERS</option> <option value="CHEST">CHEST</option> </select></td> </tr> <tr style=""> <td>City</td> <td ><div id="citydiv"><select name="city"> <option>Select City</option> </select></div></td> and the reference page for the query is <? $country=$_REQUEST['country']; $link = mysql_connect('localhost', 'openshar_techker', 'techker'); //changet the configuration in required if (!$link) { die('Could not connect: ' . mysql_error()); } mysql_select_db('openshar_trainerstool'); $query="select * from $country "; $result=mysql_query($query); ?> <select name="city"> <option>Select City</option> <? while($row=mysql_fetch_array($result)) { ?> <option value><?=$row['pic']?></option> <? } ?> </select> [/php
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i need server side to in order to get the info from my database?
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but you see i ahve googled just about everything i can think of.what do i look for is the question?
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hey guys is tehre a way to put a select box on a page that when you select the lets say categorie it refreshe's the form to get the info(mysql) in that category? i have tryed lots of was some worked but when i trye to put more then one on a page it refreshe's the first and second box.. i have tryed googling javascript event handler onchange. but i cant find a page that shows a for with a select box refresh...
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it refreshs tonly the fisrt box not the second one .. check http://webworkout.info/sel3.php
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my error is solved with the second script i posted.now the question was can i put it multiple times on one page?
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SELECT DISTINCT pic,id FROM $cat
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ah sorry wrong box..lol here is the code for the new probleme.i got the dselect part working but now i need to add more of the same on a same page ..but it refresh's the hole page so all the boxes reset.i have tryed changing all to select2,querry2..check it out to see.. <? require "config2.php"; $connection = mysql_connect($dbhost, $dbusername, $dbpass); $SelectedDB = mysql_select_db($dbname); $cat=$_GET['cat']; ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> <SCRIPT language=JavaScript> function reload(form) { var val=form.cat.options[form.cat.options.selectedIndex].value; self.location='sel2.php?cat=' + val ; } </script> </head> <body> <form id="cat" name="cat" method="post" action=""> <label> <select onchange="reload(this.form)" name="cat" id="cat"> <option value="selected"><? print"$cat" ?></option> <option value="ABS">ABS</option> <option value="ARMS">ARMS</option> <option value="LEGS">LEGS</option> <option value="SHOULDERS">SHOULDERS</option> <option value="CHEST">CHEST</option> </select> </label> </form> <p> <? if(isset($cat) and strlen($cat) > 0){ $quer=mysql_query("SELECT DISTINCT pic,id FROM $cat" ); }else{$quer=mysql_query("SELECT DISTINCT pic,id FROM $cat "); } echo "<select name='subcat'onChange='swapImage()' ><option value=''>Select one</option>"; while($noticia = mysql_fetch_array($quer)) { if($noticia['pic']==@$cat3){echo "<option selected value='$noticia[pic]'>$noticia[pic]</option>"."<BR>";} else{echo "<option value=/Account/PICS/$cat/$noticia[pic]>$noticia[pic]</option>";} } echo "</select>";?> </p> <p> </p> <table width="442" height="138" border="0" cellpadding="0" cellspacing="0"> <tr> <th scope="row"><form id="cat2" name="cat2" method="post" action=""> <label> <select onchange="reload(this.form)" name="cat2" id="cat2"> <option value="selected"><? print"$cat2" ?></option> <option value="ABS">ABS</option> <option value="ARMS">ARMS</option> <option value="LEGS">LEGS</option> <option value="SHOULDERS">SHOULDERS</option> <option value="CHEST">CHEST</option> </select> </label> </form> <p> <? if(isset($cat2) and strlen($cat2) > 0){ $quer2=mysql_query("SELECT DISTINCT pic,id FROM $cat2" ); }else{$quer2=mysql_query("SELECT DISTINCT pic,id FROM $cat2 "); } echo "<select name='subcat1'onChange='swapImage()' ><option value=''>Select one</option>"; while($noticia2 = mysql_fetch_array($quer2)) { if($noticia2['pic']==@$cat3){echo "<option selected value='$noticia2[pic]'>$noticia2[pic]</option>"."<BR>";} else{echo "<option value=/Account/PICS/$cat2/$noticia2[pic]>$noticia2[pic]</option>";} } echo "</select>";?></th> </tr> </table> <p> </p> </body> </html> http://webworkout.info/sel2.php
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ok so this is the box alone http://webworkout.info/sel.php
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nice thx. is there a way i can copy and past this form mulitiple times on one page?cause when i do so it refresh's all the select boxes..
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hey guys i got some part of my list boxes good but it does not stay on the selected choise? it refreshe's the page but it does not stay on the selected choice>? <? require "config2.php"; $connection = mysql_connect($dbhost, $dbusername, $dbpass); $SelectedDB = mysql_select_db($dbname); $cat=$_GET['cat']; ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> <SCRIPT language=JavaScript> function reload(form) { var val=form.cat.options[form.cat.options.selectedIndex].value; self.location='sel.php?cat=' + val ; } </script> </head> <body> <form id="cat" name="cat" method="post" action=""> <label> <select onchange="reload(this.form)" name="cat" id="cat"> <option value="ABS">ABS</option> <option value="ARMS">ARMS</option> <option value="LEGS">LEGS</option> <option value="SHOULDERS">SHOULDERS</option> <option value="CHEST">CHEST</option> </select> </label> </form> </body> </html>
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hey guys i was wondering on how i can get info from my database from a select box. like i tryed this with no luck: <? require "config2.php"; $connection = mysql_connect($dbhost, $dbusername, $dbpass); $SelectedDB = mysql_select_db($dbname); $cat=$_GET['cat']; $QQQ1 = mysql_query(" SELECT id, pic FROM $cat "); if(!$QQQ1) die(mysql_error()); $err = mysql_num_rows($QQQ1); if($err == 0) die("No matches met your criteria."); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <form id="form1" name="form1" method="post" action=""> <label> <select onchange="reload(this.form)" name="cat" id="cat"> <option value="ABS">ABS</option> <option value="ARMS">ARMS</option> </select> </label> </form> <? while ($line = mysql_fetch_array($QQQ1)) { echo "<option value=\"$line[id]\">$line[pic] </option>"; }?> </body> </html> You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1 im shure it's because it is executing the query before i chose the categorie?
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this is what i tryed up to now. <? $query = "SELECT * FROM clients_graph"; $result = mysql_query($query)or die(mysql_error()); print "<SELECT name=\"client\">"; while ($line = mysql_fetch_array($result)) { echo "<option value=\"$line[id]\">$line[2]</option>"; } //print "</select>"; echo "<img src='/Account/PICS/". $line['2'] ."' border='0' hight=120/>"; print "</select>"; ?>
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hey guys i have a databse withe images in it(just the path to the image folder) i want to make a list menu but instead of the pic name i want the image to show instead?is that possible??? or when you select the name the image apears?that would be better.thx
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hmm javascript .i will check it out
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hey guys i have a script that generates a page with pics on demand. now it has a grid (that i did ) as background and over it shows litle pics in the squares. now it works great but when i try to print it only shows the small pics not the background??