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techker

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Everything posted by techker

  1. so i fanaly found one that maybe has potential!lol xml and ajax. it works good but if i add another on the page and changed the get page to fincity2 and the divtag to city2 the both work but when i select the second one it changes the first one. i will barke down the code: the xml <script> function getXMLHTTP() { //fuction to return the xml http object var xmlhttp=false; try{ xmlhttp=new XMLHttpRequest(); } catch(e) { try{ xmlhttp= new ActiveXObject("Microsoft.XMLHTTP"); } catch(e){ try{ xmlhttp = new ActiveXObject("Msxml2.XMLHTTP"); } catch(e1){ xmlhttp=false; } } } return xmlhttp; } function getCity(strURL) { var req = getXMLHTTP(); if (req) { req.onreadystatechange = function() { if (req.readyState == 4) { // only if "OK" if (req.status == 200) { document.getElementById('citydiv').innerHTML=req.responseText; ( } else { alert("There was a problem while using XMLHTTP:\n" + req.statusText); } } } req.open("GET", strURL, true); req.send(null); } } </script> [code] and the form [code=php:0] <form method="post" action="" name="form1"> <table width="60%" border="0" cellspacing="0" cellpadding="0"> <tr> <td width="150">Country</td> <td width="150"><select name="country" onChange="getCity('findcity.php?country='+this.value)"> <option value="">Select Country</option> <option value="ABS">ABS</option> <option value="ARMS">ARMS</option> <option value="LEGS">LEGS</option> <option value="SHOULDERS">SHOULDERS</option> <option value="CHEST">CHEST</option> </select></td> </tr> <tr style=""> <td>City</td> <td ><div id="citydiv"><select name="city"> <option>Select City</option> </select></div></td> and the reference page for the query is <? $country=$_REQUEST['country']; $link = mysql_connect('localhost', 'openshar_techker', 'techker'); //changet the configuration in required if (!$link) { die('Could not connect: ' . mysql_error()); } mysql_select_db('openshar_trainerstool'); $query="select * from $country "; $result=mysql_query($query); ?> <select name="city"> <option>Select City</option> <? while($row=mysql_fetch_array($result)) { ?> <option value><?=$row['pic']?></option> <? } ?> </select> [/php
  2. i need server side to in order to get the info from my database?
  3. but you see i ahve googled just about everything i can think of.what do i look for is the question?
  4. hey guys is tehre a way to put a select box on a page that when you select the lets say categorie it refreshe's the form to get the info(mysql) in that category? i have tryed lots of was some worked but when i trye to put more then one on a page it refreshe's the first and second box.. i have tryed googling javascript event handler onchange. but i cant find a page that shows a for with a select box refresh...
  5. techker

    select box

    it refreshs tonly the fisrt box not the second one .. check http://webworkout.info/sel3.php
  6. techker

    select box

    my error is solved with the second script i posted.now the question was can i put it multiple times on one page?
  7. techker

    select box

    SELECT DISTINCT pic,id FROM $cat
  8. techker

    select box

    ah sorry wrong box..lol here is the code for the new probleme.i got the dselect part working but now i need to add more of the same on a same page ..but it refresh's the hole page so all the boxes reset.i have tryed changing all to select2,querry2..check it out to see.. <? require "config2.php"; $connection = mysql_connect($dbhost, $dbusername, $dbpass); $SelectedDB = mysql_select_db($dbname); $cat=$_GET['cat']; ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> <SCRIPT language=JavaScript> function reload(form) { var val=form.cat.options[form.cat.options.selectedIndex].value; self.location='sel2.php?cat=' + val ; } </script> </head> <body> <form id="cat" name="cat" method="post" action=""> <label> <select onchange="reload(this.form)" name="cat" id="cat"> <option value="selected"><? print"$cat" ?></option> <option value="ABS">ABS</option> <option value="ARMS">ARMS</option> <option value="LEGS">LEGS</option> <option value="SHOULDERS">SHOULDERS</option> <option value="CHEST">CHEST</option> </select> </label> </form> <p> <? if(isset($cat) and strlen($cat) > 0){ $quer=mysql_query("SELECT DISTINCT pic,id FROM $cat" ); }else{$quer=mysql_query("SELECT DISTINCT pic,id FROM $cat "); } echo "<select name='subcat'onChange='swapImage()' ><option value=''>Select one</option>"; while($noticia = mysql_fetch_array($quer)) { if($noticia['pic']==@$cat3){echo "<option selected value='$noticia[pic]'>$noticia[pic]</option>"."<BR>";} else{echo "<option value=/Account/PICS/$cat/$noticia[pic]>$noticia[pic]</option>";} } echo "</select>";?> </p> <p> </p> <table width="442" height="138" border="0" cellpadding="0" cellspacing="0"> <tr> <th scope="row"><form id="cat2" name="cat2" method="post" action=""> <label> <select onchange="reload(this.form)" name="cat2" id="cat2"> <option value="selected"><? print"$cat2" ?></option> <option value="ABS">ABS</option> <option value="ARMS">ARMS</option> <option value="LEGS">LEGS</option> <option value="SHOULDERS">SHOULDERS</option> <option value="CHEST">CHEST</option> </select> </label> </form> <p> <? if(isset($cat2) and strlen($cat2) > 0){ $quer2=mysql_query("SELECT DISTINCT pic,id FROM $cat2" ); }else{$quer2=mysql_query("SELECT DISTINCT pic,id FROM $cat2 "); } echo "<select name='subcat1'onChange='swapImage()' ><option value=''>Select one</option>"; while($noticia2 = mysql_fetch_array($quer2)) { if($noticia2['pic']==@$cat3){echo "<option selected value='$noticia2[pic]'>$noticia2[pic]</option>"."<BR>";} else{echo "<option value=/Account/PICS/$cat2/$noticia2[pic]>$noticia2[pic]</option>";} } echo "</select>";?></th> </tr> </table> <p> </p> </body> </html> http://webworkout.info/sel2.php
  9. techker

    select box

    ok so this is the box alone http://webworkout.info/sel.php
  10. nice thx. is there a way i can copy and past this form mulitiple times on one page?cause when i do so it refresh's all the select boxes..
  11. hey guys i got some part of my list boxes good but it does not stay on the selected choise? it refreshe's the page but it does not stay on the selected choice>? <? require "config2.php"; $connection = mysql_connect($dbhost, $dbusername, $dbpass); $SelectedDB = mysql_select_db($dbname); $cat=$_GET['cat']; ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> <SCRIPT language=JavaScript> function reload(form) { var val=form.cat.options[form.cat.options.selectedIndex].value; self.location='sel.php?cat=' + val ; } </script> </head> <body> <form id="cat" name="cat" method="post" action=""> <label> <select onchange="reload(this.form)" name="cat" id="cat"> <option value="ABS">ABS</option> <option value="ARMS">ARMS</option> <option value="LEGS">LEGS</option> <option value="SHOULDERS">SHOULDERS</option> <option value="CHEST">CHEST</option> </select> </label> </form> </body> </html>
  12. techker

    select box

    hey guys i was wondering on how i can get info from my database from a select box. like i tryed this with no luck: <? require "config2.php"; $connection = mysql_connect($dbhost, $dbusername, $dbpass); $SelectedDB = mysql_select_db($dbname); $cat=$_GET['cat']; $QQQ1 = mysql_query(" SELECT id, pic FROM $cat "); if(!$QQQ1) die(mysql_error()); $err = mysql_num_rows($QQQ1); if($err == 0) die("No matches met your criteria."); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <form id="form1" name="form1" method="post" action=""> <label> <select onchange="reload(this.form)" name="cat" id="cat"> <option value="ABS">ABS</option> <option value="ARMS">ARMS</option> </select> </label> </form> <? while ($line = mysql_fetch_array($QQQ1)) { echo "<option value=\"$line[id]\">$line[pic] </option>"; }?> </body> </html> You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1 im shure it's because it is executing the query before i chose the categorie?
  13. this is what i tryed up to now. <? $query = "SELECT * FROM clients_graph"; $result = mysql_query($query)or die(mysql_error()); print "<SELECT name=\"client\">"; while ($line = mysql_fetch_array($result)) { echo "<option value=\"$line[id]\">$line[2]</option>"; } //print "</select>"; echo "<img src='/Account/PICS/". $line['2'] ."' border='0' hight=120/>"; print "</select>"; ?>
  14. hey guys i have a databse withe images in it(just the path to the image folder) i want to make a list menu but instead of the pic name i want the image to show instead?is that possible??? or when you select the name the image apears?that would be better.thx
  15. hmm javascript .i will check it out
  16. hey guys i have a script that generates a page with pics on demand. now it has a grid (that i did ) as background and over it shows litle pics in the squares. now it works great but when i try to print it only shows the small pics not the background??
  17. he wants the site..it free publicity for him.anyways i will figure it out thx.
  18. i don't know if you know but in that art business there is alot of copy's!ever look for a tattoo before?your fisrt step is google ... it has nothing to do with corporate-riaa-microsoft-fud" bullshit mentality when you pay to have it piss you off when you see other people with it.
  19. its because im doing a web site for my boddy that is a tattoois.so he does not want anybody copying his pics.unique styles..
  20. inless i load the image in a page an put some javascript for no right click?
  21. hey guys i have a gallery that has thumbnails and when you click it takes you to the images. i need to prevent downloading of that pic? this is the echo. Code: echo '<th scope="row"><a href="/admin/art/'. $row['pic'] .'" target="_blank" > <img src="/admin/imgsize.php?w=60&h=50&img=art/'. $row['pic'] .'" border="0" alt="" /> </a> so it does not load in a page it gets the images in its directory.. --------------------------------------------------------------------------------
  22. din't do mutch fo me cause it is not the full script.i wanted to get my script one going?
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