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Found 1 result

  1. <?php $dir = 'direction'; $q = (isset($_GET['q']))? strtolower($_GET['q']) : ''; $res = opendir($dir); f (strlen($q) < 3) { echo "Search must be longer than 3 characters.<br><br><a href='http://mbrservices.no-ip.org/search.html'>Back To Search Box</a>"; } else { if (!( ($q == "mp3") || ($q == "wav") || ($q == ""))){ while(false!== ($file = readdir($res))) { if(strpos(strtolower($file),$q)!== false &&!in_array($file,$exclude)) { $nicefile = str_replace(".mp3", "", "$file"); $info = pathinfo($file); if (($info["extension"] == "mp3") || ($info["extension"] == "wav")) { show links of the files that contain query of the string) the problem is that i want to create an if statment which check if there is files of query that user searhed show it else if the search result is ended up with nothing it return an error msg. i tried alot of things like: if ($files != ""){show the files} elseif(!isset($errorMsg)){errormsg} if (!empty($files)){show the files} elseif(!isset($errorMsg)){errormsg} if ($files != 0){show the files} elseif(!isset($errorMsg)){errormsg} and more but nothing ended up right they always gave blank with no error msg or nothing, any idea? Thanks alot, Maxwel
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