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I have a query below where I want to search a table to find the top row with 1 or 2 empty positions. But it never returns the correct "referral_id". If I remove the "ref_user_1" and "ref_user_2" conditions from the query, then of course it will return the correct referral id. But those conditions are important for me to have. Is having "AND" and "OR" conditions in the same query against the rules? If so what's the solution for this problem? $find_sponsor = $db->prepare("SELECT * FROM referrals WHERE referred_by = :referred_by AND ref_user_1 = :ref_user_1 OR ref_user_2 = :ref_user_2 ORDER BY referral_id ASC LIMIT 1"); $find_sponsor->bindValue(':referred_by', 2); $find_sponsor->bindValue(':ref_user_1', 0); $find_sponsor->bindValue(':ref_user_2', 0); $find_sponsor->execute(); $result_sponsor = $find_sponsor->fetchAll(PDO::FETCH_ASSOC); if(count($result_sponsor) > 0) { foreach($result_sponsor as $row) { $get_referral_id = $row['referral_id']; $get_ref_1 = $row['ref_user_1']; $get_ref_2 = $row['ref_user_2']; } echo $get_referral_id; // this always returns the wrong referral id } // Table referral_id referred_by ref_user_1 ref_user_2 1 2 20 21 2 2 23 24 3 2 25 0 4 2 0 0 As per my table above, what would my new query look like if I want to retrieve #3 as my referral id?

Trying to simplify my code to something like: if($_SESSION['url'] != 'http://www.golden-wand.com/Pages/admin.php'||'http://www.golden-wand.com/Pages/admin-test.php') This is what works that I would like simplified: <!---------------------------------- ADMIN FUNCTIONS START -------------------------------> <?php if($_SESSION['admin']=='1'){ if($_SESSION['url'] != 'http://www.golden-wand.com/Pages/admin.php'){ if($_SESSION['url'] != 'http://www.golden-wand.com/Pages/admin-test.php'){ ?> <input type="button" value="Admin Page" class="button hvr-wobble-skew" onclick="location.href='http://www.golden-wand.com/Pages/admin.php'"> <?php }}} ?> <!----------------------------------- ADMIN FUNCTIONS END -------------------------------->

If ($Hoff == 'Nelspruit') || ($Hoff == 'Hoedspruit') || ($Hoff == 'Klaserie') || ($Hoff == 'Bushbuck Ridge') || ($Hoff == 'Hazyview') || ($Hoff == 'Graskop') OR ($Hoff == 'Sabie') || ($Hoff == 'Lydenburg') || ($Hoff == 'Pilgrims Rest') || ($Hoff == 'Barberton') || ($Hoff == 'Waterval Boven') || ($Hoff == 'Komatipoort') || ($Hoff == 'Malelane') { $addon = $addon +2; } else { $addon = $addon -100; } PHP Parse error: syntax error, unexpected '||' (T_BOOLEAN_OR) in /home/lowveldn/public_html/control/publish.php on line 84 Can someone tell me what is wrong here please.

I am creating a search page with php and codeigniter. I created the query which is; "SELECT * FROM my_account WHERE inex='$inex' AND type='$type' AND date BETWEEN '$date1' AND '$date2' " $date1 and $date2 values comes from form input and I have no problem here. On the other hand $inex value is also coming from form dropdown. $options = array( 'Income' =>'Income', 'Expense' =>'Expense', ); echo "<td>" . form_dropdown('inex',$options) ."</td>"; Now, if i do a search between two dates, i have to use Income or Expense values. But, I need the third option in the options array so that i can also choose both so that i can see both income and expenses between these two dates. I think there is a simple answer for that but somehow i cant figure it out. helps are appreciated. thanks in advance.