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Showing results for tags 'php image'.
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Hello sorry for the English if it's bad... I'm going to use facebook as an example, if I uploaded my profile picture 1.9Mb 1920x1200, and then I went to the home page, in the top blue navbar I will find that the profile picture size is just 2.24Ko and it's resolution is 36x36. so I'm wondering how this can be done using php ? Thanks
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Dear All this is my first topic here i need some help with php coding, I have an old script for image gallery that i were able to upgrade on it. I did some change by adding the option of the categories but my issue is when going to the second page ( each page has X amount of images ) and the page splitte to ?page= 2 and like that. but when i add the category id this option didn't work please help. <?php // Get Page config Info $info = @mysql_query("SELECT keywords,description,sitetitle FROM configtable LIMIT 1"); $pageInfo = @mysql_fetch_assoc($info); $pageDesc = $pageInfo['description']; $pageKeyw = $pageInfo['keywords']; $general_title = $pageInfo['sitetitle']; $rowSen = 21; $numRow = $rowSen + 1; //check the page number if(empty($page) || !is_numeric($page)){ $st = 0; $page = 0; }else if(is_numeric($page)){ $st = $page * ($numRow+1); $st = @mysql_real_escape_string($st); } // Get Photos By Category if(isset($_GET['id'])){ $id = @mysql_real_escape_string($_GET['id']); $get_all_images = mysql_query("SELECT * FROM photos WHERE photo_country = $id"); $num_images = mysql_num_rows($get_all_images); $QueryCount = @mysql_query("SELECT count(*) as num FROM photos WHERE photo_country = $id"); $QueryNumbr = @mysql_fetch_assoc($QueryCount); // Get Country By Id $countries_set = @mysql_query("SELECT * FROM countries WHERE id = $id LIMIT 1"); $country = mysql_fetch_assoc($countries_set) ; $countrysnum = @mysql_num_rows($countries_set); } else { $photos_set = @mysql_query("SELECT * FROM countries ORDER BY id desc"); } ?> and herer is my gallery <table width="850px" border="0" cellspacing="0" cellpadding="0" align="center"> <tr> <td><?php if($num_images>0){ $count = 0; $num = 0; $fin = 0; $num_colm = 3; while($row = mysql_fetch_assoc($get_all_images)){ if($count < $rowSen){ $fin++; if($num==$num_colm){ echo "</tr>\n"; echo "<tr>\n"; $num = 0; }else if($num==0){ echo "<tr>\n"; } if($lan=='en'){ $download = "Download"; }else{ $download = "Download"; } $PICnewPath = 'data/photos/'.$row['photo_name'] ; echo '<td><center><a href="'.$PICnewPath.'" rel="lightbox[roadtrip]"><img style="font-size:15px;" onmouseover="this.style.opacity = \'0.4\';" onmouseout="this.style.opacity = \'1\';" height="150" src="'.$PICnewPath.'" alt="'.$row['photo_title'].'" title="'.$row['photo_title'].' " /></a></center><p><center>' . $row['photo_title'] . '<br /> <table width="200" border="0" cellspacing="0" cellpadding="0"> <tr> <td> ' . substr(stripslashes(strip_tags($row['photo_dec'])),0,500) . '<a href="picture.php?&id=' . $row['photo_id'] . '"> Read More</a></td> </tr> </table> </center></p> </div></td>'; $num++; if($fin == $num_images){ if($num!=$num_colm && $fin>$num_colm){ $subtract = $num_colm - $num; for($i=0;$i<$subtract;$i++){ echo '<td> </td>'; } } echo "</tr>\n"; } } $count++; } }else{ $brak = '<br /><br /><br /><br /><br /><br /><br /><br /><br /><br /><br /><br /><br /><br /><br /><br /><br />'; if($lan=='en'){ echo '<tr><td>There is no images right now'.$brak.'</td></tr>'; }else{ echo '<tr><td>There is no images right now'.$brak.'</td></tr>'; } } ?></td> </tr> </table> and here is my page splitting code <?php $dataNum = $QueryNumbr['num']; if($dataNum>$numRow){ $numPages = $dataNum/$rowSen; $numPages = ceil($numPages); for($i=0;$i<$numPages;$i++){ $pageNum = $i + 1; if($i==$page){ echo '<b><span class="shift" style="font-size:15px">'.$pageNum.'</span> '; }else{ echo '<a style="font-size:15px" href="'.$_SERVER['PHP_SELF'].'?id='.$id.'&page='.$i.'" class="shift">'.$pageNum.'</a></b> '; } } } ?> Please help