[SOLVED] default values for function args

[inactive]

not sure if i have my terminology right here, but I know you can set a value for an argument in a function like so

<?php
function dosomething($arg1='foo') {
...
}
?>

so that when the function is called, if $arg1 was not passed, it will take the value of 'foo' instead of throwing up an error

 

why can't you do something like this?:

<?php
function dosomething($arg1= date("Y")) {
...
}
?>

is there a way to do that?

[Northern Flame]

do you get an error when you tried that?

[inactive]

Yes i did...

 

So my actual function:

<?php
function foobar($from_day = date("j"), $from_month = date("n")-2, $from_year = date("Y"), $to_day = date("j")+1, $to_month = date("n"), $to_year = date("Y"))  {
...
}
...
?>

 

And the error I get is:

 

Parse error:  syntax error, unexpected '(', expecting ')' in C:\server\Apache\htdocs\test.php on line 43

 

Where line 43 is the one above. Have I made some other kind of syntax error i missed?

[inactive]

any ideas guys?

 

bit early to bump, but i'm quite desperate here...

[PFMaBiSmAd]

I trust you saw this in the php manual -

 

The default value must be a constant expression, not (for example) a variable, a class member or a function call.

[inactive]

I trust you saw this in the php manual -

 

The default value must be a constant expression, not (for example) a variable, a class member or a function call.

 

hmm yes I really should read that more...ok i'll have to work something else out then...

 

thanks guys...