[SOLVED] Simple Validation

[phpretard]

I need some code that will validate a full name.

 

Argument: 'John'=No Good | 'Doe'=No Good | 'John Doe'=Good

 

if ($Name=='ONE WORD'){
$pass="No";
}

if ($Name=='TWO WORDS'){
$pass="Yes";
}

Anyone got an Idea

[Fadion]

What i can think of is using explode() and count if there are 2 values on the array:

 

<?php
$input = 'John Smith';
$name = explode(' ', trim($input)); //trim() input if u have "John " or " John"
if(count($name) == 2){ //if $name array has two values
     $pass = 'yes';
} else{
     $pass = 'no';
}
?>

 

or just see if there's any space:

 

<?php
$input = 'John Smith';
if(strstr(trim($input), ' ')){  //if there is a space between the text
    $pass = 'yes';
} else{
    $pass = 'no';
}
?>

 

I would prefer the first anyway.

[darkfreaks]

that will also work with str_word_count instead of count

[Fadion]

that will also work with str_word_count instead of count

 

Didnt know str_word_count(), but guess its almost the same approach

[woobarb]

I like the str_word_count() function because it also handles comms ',' and the such, because some nationalities will write their surname before the given name, and it is proper to do this with a comma.

[phpretard]

Do you have an example of str_word_count.

 

I am struggling to make it work.

[woobarb]

Are you aware of the php manual, that has some examples for each way of using it. The search box is the most invaluable resource available for php programming.

[phpretard]

Yes...I read it, and search google before I post (as descrided in site conditions).

 

The code I keep running into puts it all into an array... I don' think I need an array to count words or do I?

[woobarb]

format

 

    Specify the return value of this function. The current supported values are:

 

        * 0 - returns the number of words found