Using A Variable In Another Variable

[JustinK101]

I am trying to write the following function:

 

public function get($k, $array = "remote") {
		return ($this->$array_preferences[$k]);
	}

 

I don't think this is going to work though, I am trying to use the variable $array to choose the right array. Either:

 

remote_preferences[] or local_preferences[]

 

Thanks.

[DarkWater]

I am trying to write the following function:

 

public function get($k, $array = "remote") {
		return ($this->$array_preferences[$k]);
	}

 

I don't think this is going to work though, I am trying to use the variable $array to choose the right array. Either:

 

remote_preferences[] or local_preferences[]

 

Thanks.

 

function get_array($k, $array = "remote") {

return ($this->$array[$k])

}

 

What are you using this for?  I could probably code something better if I knew what you wanted it for.  Obviously it's an object though.

 

Edit: OH I GET IT.   Umm, ${$array}_preferences[$k] MIGHT work.  Not sure.  Try it out.

[JustinK101]

darkWater,  nope got a parse error. Basically I am trying to do:

 

get($key, $array) {
   echo $this->$array_preferences[$key];
}

 

I guess I could write functions for each array name, just trying to make one function that is reusable though.

[DarkWater]

darkWater,  nope got a parse error. Basically I am trying to do:

 

get($key, $array) {
   echo $this->$array_preferences['key'];
}

 

I guess I could write functions for each array name, just trying to make one function that is reusable though.

 

Lol, I thought it'd be a parse error. =(  I had an idea though.  Use a switch statement and just add preference blocks as necessary.

function get($key, $array) {
switch $array {
case "remote":
  return $remote_preferences[$k];
  break;
case "blah":
  return blah;
  break;
}
}

You get the idea.

[sasa]

<?php
class test{
var $local_preferences = array('l1','l2','l3');
var $remote_preferences = array('r1','r2','r3');
function get($k, $array){
	return $this->{$array.'_preferences'}[$k];
}
}
$a = new test();
echo $b = $a->get(1,'remote');
?>