mtgriffiths Posted April 21, 2008 Share Posted April 21, 2008 Hi All, What i am trying to achieve but failing miserably at is.... I want to run a query that will select all students registered onto a course....thats the easy bit. Once the students have been displayed i want to print out if they have registered their attendance for that course for that day. To check if they have attended today i run a query against my attendance table. This is where i am becoming stuck....if the student has attended i want to have the word present displayed next to their name and if they have not registered their attendance i want absent next to their name. Anyone able to help? Thanks in advance Matthew ps if anyone needs any code il post on request Quote Link to comment https://forums.phpfreaks.com/topic/102169-display-depending-on-query-result/ Share on other sites More sharing options...
DeanWhitehouse Posted April 21, 2008 Share Posted April 21, 2008 use an if and else statement depending on the query Quote Link to comment https://forums.phpfreaks.com/topic/102169-display-depending-on-query-result/#findComment-522956 Share on other sites More sharing options...
mtgriffiths Posted April 21, 2008 Author Share Posted April 21, 2008 I can work out how to do that but when i put it in to a while loop to get all the students details how do i echo out the correct attendance value? Quote Link to comment https://forums.phpfreaks.com/topic/102169-display-depending-on-query-result/#findComment-522957 Share on other sites More sharing options...
DeanWhitehouse Posted April 21, 2008 Share Posted April 21, 2008 erm, can you post the code you already have and i can edit to show you Quote Link to comment https://forums.phpfreaks.com/topic/102169-display-depending-on-query-result/#findComment-522959 Share on other sites More sharing options...
mtgriffiths Posted April 21, 2008 Author Share Posted April 21, 2008 sure..the query to get the students details is: $Search = mysql_query("SELECT DISTINCT Courses.Course_Name, student_courses.Course_ID, student_courses.Student_ID, students.Enrollment, students.First_Name, students.Last_Name FROM Courses INNER JOIN student_courses ON Courses.Course_ID = student_courses.Course_ID INNER JOIN students ON student_courses.Student_ID = students.Student_ID WHERE Courses.Course_ID='$Course'") or die(mysql_error()); Then i am using a loop to print the results into a table. Shown below: echo "<table border='0'>"; echo "<tr align='center'>"; echo "<td width='20%'><font color='#FFFFFF' face='Calibri'>"; echo "<b>Enrollment No"; echo "</td><td width='20%'><font color='#FFFFFF' face='Calibri'>"; echo "<b>First Name"; echo "</td><td width='20%'><font color='#FFFFFF' face='Calibri'>"; echo "<b>Last Name"; echo "</td></tr>"; while($row = mysql_fetch_assoc($Search)) { echo "<tr align='center'>"; echo "<td><font color ='White' face = 'calibri'>"; echo $row['Enrollment']; echo "</td><td><font color ='White' face = 'calibri'>"; echo $row['First_Name']; echo "</td><td><font color ='White' face = 'calibri'>"; echo $row['Last_Name']; echo "</td></tr>"; } echo "</table>"; } After the last name field is where the attendance would go. Quote Link to comment https://forums.phpfreaks.com/topic/102169-display-depending-on-query-result/#findComment-522964 Share on other sites More sharing options...
mtgriffiths Posted April 21, 2008 Author Share Posted April 21, 2008 Been trying different things... I think that this would be the nicer way to do it but again still unsure... I have 1 query getting all students registered on to a course I have another query selecting all students who have logged in today. If there is a match display present if there is no match display absent. Is this possible to achieve? Quote Link to comment https://forums.phpfreaks.com/topic/102169-display-depending-on-query-result/#findComment-522979 Share on other sites More sharing options...
DeanWhitehouse Posted April 21, 2008 Share Posted April 21, 2008 this should send you in the right direction <?php $Search = mysql_query( "SELECT DISTINCT Courses.Course_Name, student_courses.Course_ID, student_courses.Student_ID, students.Enrollment, students.First_Name, students.Last_Name FROM Courses INNER JOIN student_courses ON Courses.Course_ID = student_courses.Course_ID INNER JOIN students ON student_courses.Student_ID = students.Student_ID WHERE Courses.Course_ID='$Course'") or die(mysql_error()); echo "<table border='0'> <tr align='center'> <td width='20%'><font color='#FFFFFF' face='Calibri'> <b>Enrollment No </td><td width='20%'><font color='#FFFFFF' face='Calibri'> <b>First Name </td><td width='20%'><font color='#FFFFFF' face='Calibri'><b>Last Name</td></tr>" while($row = mysql_fetch_assoc($Search)) $sql = mysql_query(SELECT DISTINCT/*put where the attendance data is coming from here*/); or die(mysql_error()); if ($sql == 1)/*this is the data from the database, 1 = present*/ { echo "<tr align='center'> <td><font color ='White' face = 'calibri'> $row['Enrollment']; </td><td><font color ='White' face = 'calibri'> $row['First_Name']; </td><td><font color ='White' face = 'calibri'> $row['Last_Name']; </td></tr><tr><td><font color ='White' face = 'calibri'>Present </td></tr></table></font>"; } elseif ($sql == 2))/*this is the data from the database, 2= not present*/ { echo "<tr align='center'> <td><font color ='White' face = 'calibri'> $row['Enrollment']; </td><td><font color ='White' face = 'calibri'> $row['First_Name']; </td><td><font color ='White' face = 'calibri'> $row['Last_Name']; </td></tr><tr><td><font color ='White' face = 'calibri'>Absent </td></tr></table></font>"; } ?> Quote Link to comment https://forums.phpfreaks.com/topic/102169-display-depending-on-query-result/#findComment-522983 Share on other sites More sharing options...
mtgriffiths Posted April 21, 2008 Author Share Posted April 21, 2008 Thanks for the reply. The code i am now using is: $Search = mysql_query("SELECT DISTINCT Courses.Course_Name, student_courses.Course_ID, student_courses.Student_ID, students.Enrollment, students.First_Name, students.Last_Name FROM Courses INNER JOIN student_courses ON Courses.Course_ID = student_courses.Course_ID INNER JOIN students ON student_courses.Student_ID = students.Student_ID WHERE Courses.Course_ID='$Course'") or die(mysql_error()); $Count = mysql_num_rows($Search) or die(mysql_error()); echo "<font color='#FFFFFF' face='Calibri'>There are <b>".$Count."</b> students registered on to the course: <br><b>".$CourseName."<br><br><br>"; echo "<table border='0'>"; echo "<tr align='center'>"; echo "<td width='20%'><font color='#FFFFFF' face='Calibri'>"; echo "<b>Enrollment No"; echo "</td><td width='20%'><font color='#FFFFFF' face='Calibri'>"; echo "<b>First Name"; echo "</td><td width='20%'><font color='#FFFFFF' face='Calibri'>"; echo "<b>Last Name"; echo "</td></tr>"; while($row = mysql_fetch_assoc($Search)) $sql = mysql_query("SELECT * FROM student_attendance WHERE date = '$Date'") or die(mysql_error()); if ($sql == 1)/*this is the data from the database, 1 = present*/ { echo "<tr align='center'>"; echo "<td><font color ='White' face = 'calibri'>"; echo $row['Enrollment']; echo "</td><td><font color ='White' face = 'calibri'>"; echo $row['First_Name']; echo "</td><td><font color ='White' face = 'calibri'>"; echo $row['Last_Name']; echo "</td></tr><tr><td><font color ='White' face = 'calibri'>Present</td></tr></table></font>"; } elseif ($sql == 2))/*this is the data from the database, 2= not present*/ { echo "<tr align='center'>"; echo "<td><font color ='White' face = 'calibri'>"; echo $row['Enrollment']; echo "</td><td><font color ='White' face = 'calibri'>"; echo $row['First_Name']; echo "</td><td><font color ='White' face = 'calibri'>"; echo $row['Last_Name']; echo "</td></tr><tr><td><font color ='White' face = 'calibri'>Absent</td></tr></table></font>"; } i am getting the following error: Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in /homepages/29/d239295547/htdocs/DDWA4/SearchCourse.php on line 48 Line 48 is : echo "<td><font color ='White' face = 'calibri'>"; echo $row['Enrollment']; Quote Link to comment https://forums.phpfreaks.com/topic/102169-display-depending-on-query-result/#findComment-522997 Share on other sites More sharing options...
dezkit Posted April 21, 2008 Share Posted April 21, 2008 echo "<td><font color='White' face='calibri'>"; echo $row['Enrollment']; Quote Link to comment https://forums.phpfreaks.com/topic/102169-display-depending-on-query-result/#findComment-522999 Share on other sites More sharing options...
dezkit Posted April 21, 2008 Share Posted April 21, 2008 I might as well fixed your whole code $Search = mysql_query("SELECT DISTINCT Courses.Course_Name, student_courses.Course_ID, student_courses.Student_ID, students.Enrollment, students.First_Name, students.Last_Name FROM Courses INNER JOIN student_courses ON Courses.Course_ID = student_courses.Course_ID INNER JOIN students ON student_courses.Student_ID = students.Student_ID WHERE Courses.Course_ID='$Course'") or die(mysql_error()); $Count = mysql_num_rows($Search) or die(mysql_error()); echo "<font color='#FFFFFF' face='Calibri'>There are <b>".$Count."</b> students registered on to the course: <br><b>".$CourseName."<br><br><br>"; echo "<table border='0'>"; echo "<tr align='center'>"; echo "<td width='20%'><font color='#FFFFFF' face='Calibri'>"; echo "<b>Enrollment No"; echo "</td><td width='20%'><font color='#FFFFFF' face='Calibri'>"; echo "<b>First Name"; echo "</td><td width='20%'><font color='#FFFFFF' face='Calibri'>"; echo "<b>Last Name"; echo "</td></tr>"; while($row = mysql_fetch_assoc($Search)) $sql = mysql_query("SELECT * FROM student_attendance WHERE date = '$Date'") or die(mysql_error()); if ($sql == 1)/*this is the data from the database, 1 = present*/ { echo "<tr align='center'>"; echo "<td><font color='White' face='calibri'>"; echo $row['Enrollment']; echo "</td><td><font color='White' face='calibri'>"; echo $row['First_Name']; echo "</td><td><font color='White' face='calibri'>"; echo $row['Last_Name']; echo "</td></tr><tr><td><font color='White' face='calibri'>Present</td></tr></table></font>"; } elseif ($sql == 2))/*this is the data from the database, 2= not present*/ { echo "<tr align='center'>"; echo "<td><font color='White' face='calibri'>"; echo $row['Enrollment']; echo "</td><td><font color='White' face='calibri'>"; echo $row['First_Name']; echo "</td><td><font color='White' face='calibri'>"; echo $row['Last_Name']; echo "</td></tr><tr><td><font color='White' face='calibri'>Absent</td></tr></table></font>"; } `,=, Quote Link to comment https://forums.phpfreaks.com/topic/102169-display-depending-on-query-result/#findComment-523001 Share on other sites More sharing options...
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