Logout on the page the user is on

[DeanWhitehouse]

I have a logout script

<?php
require_once ""$_SERVER[REQUEST_URI])"";
session_destroy();
?>

 

but that one doesn't work, how can i log them out on the same page they came from

[BobcatM]

Do not understand the last part of the sentance. Log them out the same page they came from?

 

 

Create a page logout.php

 

<? 
session_start();
session_destroy();
?>

Logout Successful.

 

 

Hope that helps.

[DeanWhitehouse]

wot i ment, was so when they log out they go to the page they where just on before they clicked logout

[BobcatM]

I use java to redirect them when I want.

 

<SCRIPT language="JavaScript">
var count=3;
function redirect()
{
window.location="index.php";
}
function doCount()
{
if (count>1)
{
count--
}
window.status=count + " seconds till redirection!";
setTimeout('doCount()',1000);
}
</SCRIPT>
<SCRIPT language="JavaScript">
doCount();
setTimeout('redirect()',3000);
</SCRIPT>

 

Just change the index.php to whatever you want them to go to, along with the time to be directed.

 

wot i ment,

 

Still do not understand?

 

Hope this helps.

[doni49]

//first we log them out if need be
if ($_GET['cmd']=='logout'){
  $_SESSION = array();
  session_destroy():
  setcookie('PHPSESSID', '', time()-3600, '/', '', 0,0);
}

//now we check to see if they're logged in.
if (isset($_SESSION['user']))(
  echo "You're logged in";

  //include a link that will log them out.
  echo '<a href="' . $_SERVER['PHP_SELF'] . '?cmd=logout"';
}else{
  //display page as though they're not logged in.
}