interfaces doubt

[Gurzi]

Hello Guys, i defined an interface for my databases and now i have this method in my interface:

 

public function queryUniqueObject($query, $debug );

 

My problem is that i alwasy done without interfaces this methodas as

 

public function queryUniqueObject($query, $debug =  false );

 

If now i try to use this last method in the class that implements the interface, it says that it has to be like that ( interface ).

 

But in the interface, it doesn't let me put the method like $debug= false.

 

Why ?

 

how can i solve this ?

 

because i really dont want to modify my entire code.

[Daniel0]

What do you mean with that it doesn't allow you to set a default value for the $debug argument? Are you sure you even need an interface? What are you using it for?

[aschk]

The following works fine for me:

 

<?php

interface test {

public function method($var, $var1 = false);

}

class example implements test {

public function method($var, $var1 = false){
	// do something
}

}
?>

 

So, as you can see you CAN have a method in an interface that implements a default value inside the method call. Where's the real problem? What error are you getting? Can you post the relevant code?

[Gurzi]

The following works fine for me:

 

<?php

interface test {

public function method($var, $var1 = false);

}

class example implements test {

public function method($var, $var1 = false){
	// do something
}

}
?>

 

So, as you can see you CAN have a method in an interface that implements a default value inside the method call. Where's the real problem? What error are you getting? Can you post the relevant code?

 

It said that i cannot have values defined in interface arguments list.

 

 

 

[Daniel0]

Try to run aschk's code and see if it works (I don't see any reason why it shouldn't). And then post your code along with the error message verbatim.