[SOLVED] strtotime Help. Pretty Easy, I'm sure.

[Clinton]

$cdlmedical is a date in my database. I have one row currently and the date in there is 4-4-2007.

 

When I try to add 11 months to it and output it I am getting the default time 12/31/1969.

 

Where am I going wrong?

 

while ($row=mysql_fetch_assoc($result)){ extract($row);

echo "$cdlmedical <br />";

$cdlmedical = date('$cdlmedical',strtotime('+ 11 months'));

$cdlmedical = date('n/j/Y',strtotime($cdlmedical));

echo "$lname $cdlmedical";

}

[The Little Guy]

<?php
while ($row=mysql_fetch_assoc($result)){ extract($row);

echo "$cdlmedical <br />";

$cdlmedical = strtotime($cdlmedical.' + 11 months');

$cdlmedical = date('n/j/Y',$cdlmedical);

echo "$lname $cdlmedical";

}
?>

[kenrbnsn]

Use something like this:

<?php
$dt = '4-4-2007';
echo date('Y-m-d',strtotime('+11 months',strtotime($dt))) . "<br>";
?>

 

You really should look at the manual entries for date() and strtotime().

 

Ken

[Clinton]

Thanks Guy.

 

And Ken, I did look at the manual. I even looked multiple places. That's how I was able to attempt putting that whole contraption together. I couldn't figure out why it wasn't working so I posted here for help. Thought I was allowed to do that.

[Clinton]

Here' a question:

 

Why the '.' (dot) after $cdlmedical?

[The Little Guy]

because you are using single quotes, and anything in single quotes will be read as text

 

double quotes it will be read as a dynamic string.

 

<?php
$cdlmedical = strtotime($cdlmedical.' + 11 months');
// is the same as:
$cdlmedical = strtotime("$cdlmedical + 11 months");
?>

 

is that what your asking?

[kenrbnsn]

I did look at the manual. I even looked multiple places. That's how I was able to attempt putting that whole contraption together. I couldn't figure out why it wasn't working so I posted here for help. Thought I was allowed to do that.

Yes, you're allowed to do that, but when I looked at you code snippet it didn't look like you had seen the manual at all.

 

The '.' is the concatenation operator.

 

Ken

[Clinton]

That is what I was asking. Thank you for your help.

 

Sorry Ken, next time I'll try to do a little more research.