$_GET Question

[mommydaddy]

Here is my problem:

 

When I do something like "echo $_GET['myvar']", it only prints part of 'myvar'.  The value of myvar has some # signs in it.  Everything after the first # is omitted.  Anyone know how I can work around this? Thanks...

[DarkWater]

It works on my server....Even with the # signs. O_O  Try putting it in double quotes...

echo "{$_GET['myvar']}";

[mommydaddy]

Thanks for the response, but it still doesn't work.  Any other ideas?

[rarebit]

mmm works fine for me locally and on site... but do as DarkWater says...

 

what system are you on?

what server?

[DarkWater]

$myvar = $_GET['myvar'];

echo $myvar;

 

Try that....If it doesn't work, then try this and tell me if it works so we can actually tell if it's the "#" that's causing it:

 

echo str_replace("#", "", $_GET['myvar']);

[mommydaddy]

rarebit: I am using PHP 5.2.3 on Solaris 5.10.

 

DarkWater:  Doing $myvar=$_GET['myvar']; doesn't fix things.  If I do the echo str_replace, on (what is supposed to be) "asdf#asdf", it spits out "asdf".

[benphp]

try adding another fake var at the end of your string:

 

http://www.mysite.com/myscript.php?myvar=asdf#asdf&x=x

[mommydaddy]

benphp:  Good idea.  I tried it, and then $_GET['x'] is an empty string.

[DarkWater]

I got it....# is what signifies an anchor in a URL, so run urlencode() on asdf#asdf before you put it on the URL, and it'll be http://www.mysite.com/index.php?whatever=asdf%23asdf.  Then run urldecode() on the receiving page.

[mommydaddy]

DarkWater:  Excellent work!  Thank you very much!

[DarkWater]

No problem. =P