[SOLVED] link to view the form

[abs0lut]

in order to post, users need to click a link or button (fast reply)

the input form cost is under while loop...

please help me..

[pocobueno1388]

Your going to have to give a lot more detail than that. I don't even see a question.

[abs0lut]

this input form is under while loop

echo "<input type=\"text\" name=\"cost[]\" /><br>";

the input form will not display unless he click the link/button -fast reply

 

[abs0lut]

<?php
$query = mysql_query("SELECT iqid, qty, name FROM
       iqtable WHERE postid=$post");

    while($row = mysql_fetch_array($query))
    {

	$iqid=$row['iqid'];
        $qty = $row['qty'];
        $name = $row['name'];

	if($_SESSION['group']=='vmember'){ 
	echo "<input type=\"text\" name=\"qty[]\" value=".$qty." />";
	echo "<input type=\"text\" name=\"iqid[]\" value=".$iqid." />";
	}

		echo $name;
        if($_SESSION['group']=='vmember'){ 


$results = mysql_query("SELECT cost FROM ctable WHERE userid=$_SESSION[userid] AND postid=$post") or die (mysql_error());
$values = mysql_fetch_array($results);
		if($values['cost'] == ''){
   				 echo "<input type=\"text\" name=\"cost[]\" /><br>";
	}

	}
?>

here's my code, the input form will not display unless he click the link/button -fast reply

any help would be appreciated..

[DarkWater]

Okay, it's really hard to even begin to understand your problem.  Show us the "link/button" code please. =/