[SOLVED] Code error I don't understand

[kyleldi]

Hi All,

 

I'm doing a simple if/then statement that will display a certain image if a users permissions are a certain number (1), while displaying a different image for all others.  Here's my code:

 

<?php if ($row_rs_nav['permissionlevel']) = 1
echo <div class="headingsplash" id="headingmanage"><a href="http://www.domain.com"><img src="images/manageusers.jpg" alt="Manage Users" width="60" height="45" /></div>
else echo <div class="headingsplash" id="headingmanage"><img src="images/blue.jpg" alt="Manage Users" width="60" height="45" /></div> ?>

 

For some reason, when I execute the page, i get the error "Parse error: syntax error, unexpected '=' in /services/main.php on line 144"  This line is of course, the if statement.

 

Can anyone see what i'm doing wrong?  Thanks!

[rarebit]

<?php 
if ($row_rs_nav['permissionlevel']==1)
{
echo '<div class="headingsplash" id="headingmanage"><a href="http://www.domain.com"><img src="images/manageusers.jpg" alt="Manage Users" width="60" height="45" /></div>';
}
else
{
echo '<div class="headingsplash" id="headingmanage"><img src="images/blue.jpg" alt="Manage Users" width="60" height="45" /></div> ?>';
}

Your if statement was wrong, also added quotes for the echoes...

[Fadion]

Is that php? It is missing everything, curly braces, equlity operator, quotes, semicolons. Start from the very basics before attempting to write scripts.