StirCrazy Posted May 26, 2006 Share Posted May 26, 2006 Can someone help me with the correct syntax for the following ~ not sure what i'm doing wrong.trying to call username,sr_classifieds_score,sr_classifieds_pcnt and put them in $username,$score,$percentagekeep getting mysql_fetch_row(): supplied argument is not a valid MySQL result resource on line 15 - list($username,$score,$percentage) = mysql_fetch_row($r);Thanks in advance.S.C>[code]<?php$db = "******";$dbname = "*******";$dbpass = "********";$link = mysql_connect ('localhost', $dbname, $dbpass) or die;@mysql_select_db('$db', $link);function my_query($sql) { global $link; $result = @mysql_query($sql, $link); if ($result) return $result;} $r = my_query("select username,sr_classifieds_score,sr_classifieds_pcnt from user where userid='$user_id'"); list($username,$score,$percentage) = mysql_fetch_row($r); @mysql_close( $link ); ?>[/code] Link to comment https://forums.phpfreaks.com/topic/10508-php-mysql/ Share on other sites More sharing options...
Barand Posted May 26, 2006 Share Posted May 26, 2006 [code]@mysql_select_db('$db', $link);[/code]Remove the single quotes from '$db' Link to comment https://forums.phpfreaks.com/topic/10508-php-mysql/#findComment-39316 Share on other sites More sharing options...
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