[SOLVED] Foreach in function only returns 1 value

[colombian]

Here is my problem, I need this function to be part of a string of outputs.

$output = "Html" //etc

$output .= "select";

$output .= attending($total_people);

However, it only returns 1 of the 9 supposed values for the select box.

 

<?php
function attending($var) {
$hour = range(1,9);
foreach ($hour as $h) { 
	if($var == $h) { $selected = "selected"; }
	else { $selected = ""; }
	return "<option {$selected} value=\"{$h}\"> {$h} </option>";
}
}	
?>

 

If I use "echo" instead of "return" it does give me all 9 outputs, but then I cannot make the form dynimically through the $output variable.

 

Any help is appreciated.

 

Thank you.

[wildteen88]

chnage

		return "<option {$selected} value=\"{$h}\"> {$h} </option>";
}

to

		$html .= "<option {$selected} value=\"{$h}\"> {$h} </option>";
}

return $html;

[colombian]

Thank you!

 

That did the trick - quick question though.

Why does doing $html = (no .= ) cause it to break?

 

More over, why does declaring $html before that loop cause it to break too?

 

 

I had to declare $html up with the $hour array, and leave as is to make PHP happy.

 

Just trying to understand what PHP is doing here.

 

Thanks again.

 

 

[DarkWater]

The "return" language construct immediately stops execution of the function, so you need to append the whole HTML segment into a variable and return the whole thing.