Need help with domain name(s)

[timmah1]

I need to write a script that will strip the page away from the URL, meaning, if

the website is http://www.test.com/~test/1.html, I want a page that will show just the domain name, http://www.test.com.

 

I need to have a page that will list domain names that I enter, and then list them with just the URL and possibly by Page Rank.

 

Is this possible?

 

Thanks in advance

[MadTechie]

you want to get a list or urls and only show the domain and sort by page rank.. yep thats possible

[timmah1]

WOW!

Thanks, that was exactly what I was looking for.

 

Now, how would I get this to display the http:// with the domain name. From what I've found, you need to have the http:// in the domain name to check the Page Rank

 

Here is the script

$hostname = $_SERVER['SERVER_NAME']; 
$hostname = str_replace('www.', '', $hostname); 
echo $hostname;

 

Thanks in advance

[MadTechie]

the code you have removed the www., i am not 100% sure what your asking..

do you have an example of what you have and what you want it to appear like?

[timmah1]

I am trying to get just the domain name from a list of domains.

 

These domain names:

http://www.test.com/~test/binary/1.html

http://www.foo.com/~test/1.html

http://www.ohyeah.com/letsgo/havesome/t.html

 

To show this:

http://www.test.com

http://www.foo.com

http://www.ohyeah.com

 

Then, check those domain names Page Rank, then list them from highest to lowest.

 

Now, if I use this:

 

  include('pagerank.php');
  $names = array("domain0","domain1","domain2");
  $pr = getPageRank('$name[0]','$name[1]','$name[2]');
  echo ' PR '.$pr;

 

It obviously don't work. I need the array to be just the domains, then checked against Google's Page Rank

 

Does that make sense?

 

 

 

 

[DarkWater]

$parts = parse_url("http://www.google.com/lol");

echo "{$parts['scheme']}{$parts['hostname']}";