Jump to content

Recommended Posts

pstats.gif

 

I use a very simple technique:

You are unique by ip.

Check for uniqueness, if NOT then:

check if ((time() - user record's timestamp) > 120 )

if so then:

update user timestamp to time() (current time)

 

Then query for [users] table for records that are >= time() - 120      (that's 2 minutes)

 

ah yes but the problem is if you on a shared network then the ip would be the same would it not?? ur unique by username tho :P also ip adress can be chnaged and stuff and i think can lead to other problems

 

can any tell my wel this works so that it just keeps adding users rather then replacing them

 

<?
$insert = mysql_query("REPLACE INTO `useronline` SET `timestamp`='$timestamp', `ip`='".$_SERVER['REMOTE_ADDR']."', `file`='$filename',`user`='$username',`user_id`='".$_SESSION['user_id']."'") 
or die(mysql_error()); 
?> 

 

for some reason i have the same users information entred every time the go onto the page rather then replacing the existing one :S

humm how can i get this to work??

 

users viewingthread = <?php
http://www.runningprofiles.com/members/index.php?page=message&forum=$forum&id=$id

$result = mysql_query("SELECT * FROM useronline WHERE(file='http://www.runningprofiles.com/members/index.php?page=message&forum=$forum&id=$id')");
while($row = mysql_fetch_array( $result )) {

$last_active = time() - $row['timestamp'];
$onlineuser = $row['user'];
}

if($last_active < 300) {
echo $onlineuser;
}
?>

hey guys...ok i thought the was solved but two things happend today that puzzeld me...

 

first was it beeing this

 

<?php
//Fetch Users Online
$result = mysql_query("SELECT DISTINCT user FROM useronline");
while($row = mysql_fetch_array( $result )) 

$last_active = time() - $row['timestamp'];
$users = mysql_num_rows($result);
if($last_active < 400){
if($users == 1) {
$ol_label = "user";
} else {
$ol_label = "users";
}}
?>    <?php echo "<b>$users</b> $ol_label"; ?> online

 

it echos every one in  the db as beeing online :S

 

also i signed in and fo some reason it added a result in the table that was me but didnt have my username and id then i went to anouther page and it updates me and not the data it just created ?? :S

 

becuase i get the page they where on i was able to track where this happend

 

<?php 
session_start();
require_once '../settings.php';
checkLogin ('1 2');

include "connect.php"; //mysql db connection here
$timestamp = time();
$timeout = $timestamp - 180;
$username= get_username($_SESSION['user_id']);
function selfURL() { 
$s = empty($_SERVER["HTTPS"]) ? '' : ($_SERVER["HTTPS"] == "on") ? "s" : "";
$protocol = strleft(strtolower($_SERVER["SERVER_PROTOCOL"]), "/").$s; 
$port = ($_SERVER["SERVER_PORT"] == "80") ? "" : (":".$_SERVER["SERVER_PORT"]); 
return $protocol."://".$_SERVER['SERVER_NAME'].$port.$_SERVER['REQUEST_URI']; } 
function strleft($s1, $s2) { return substr($s1, 0, strpos($s1, $s2)); }
$filename = (selfURL());
//Insert User
$insert = mysql_query("REPLACE INTO `useronline` SET `timestamp`='$timestamp', `ip`='".$_SERVER['REMOTE_ADDR']."', `file`='$filename',`user`='$username',`user_id`='".$_SESSION['user_id']."'") 
or die(mysql_error()); 
?> 

is there anything there that would make it do that>?

what am i doing wrong here

 

<?php
include '../settings.php';
//Fetch Users Online
$result = mysql_query("SELECT DISTINCT user FROM useronline WHERE timestamp <60");
while($row = mysql_fetch_array( $result )) 

$last_active = time() - $row['timestamp'];
$users = mysql_num_rows($result);
if($users == 1) {
$ol_label = "user";
} else {
$ol_label = "users";
}
?>    <?php echo "<b>$users</b> $ol_label"; ?> online

 

i think im doing this wrong WHERE timestamp <60"

If you store timestamp in seconds you can do it easily.

 

e.g.

 

"INSERT INTO `db_name` . `table_name` ( `user_id`, `timestamp` ) VALUES ( '23', '" . time() . "' )";

 

Then to check the timeout:

 

<?php
// $uid = $_SESSION['user_id']; // Your user ID variable
$sql = "SELECT `timestamp` FROM `db_name` . `table_name` WHERE `user_id` = '" . $uid . "' LIMIT 1"; // timestamp should be an integer (INT)
$res = mysql_query($sql) or die('MySQL Error: ' . mysql_error());
while($row = mysql_fetch_array($res)) {
  $timeout = 5 * 60; // 5 minutes
  if((time() - $row['timestamp']) < $timeout) { // Remember, if big time minus little time is less than timeout
    // do something
  }
  else {
    // do something else 
  }
}
?>

you see thats the thing.... im not getitng one user online as i do this for that

<?php $result = mysql_query("SELECT * FROM useronline WHERE(user='".$gettopic3['author']."')");
while($row = mysql_fetch_array( $result )) {

$last_active = time() - $row['timestamp'];
}

if($last_active < 300) {
echo "Online";
} else {
echo "Offline";
} ?> 

 

but i want to get a list of how many users are online within the last minute so i thought it would be something like

 

<?php
include '../settings.php';
//Fetch Users Online
$result = mysql_query("SELECT DISTINCT user FROM useronline WHERE timestamp <60");//i thought i need to get the users that are online from a timelimit here

while($row = mysql_fetch_array( $result )) 

$users = mysql_num_rows($result);//this should display all the users
if($users == 1) {// this i thought would chnage if 1 user on say user if more say users
$ol_label = "user";
} else {
$ol_label = "users";
}
?>    <?php echo "<b>$users</b> $ol_label"; ?> online

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.